Saturday, 21 September 2013

QUANT QUIZ ON TIME AND DISTANCE WITH SOLUTIONS ( SHORTCUTS)

Formulae
(i) Speed = Distance/Time
(ii) x km/hr = (x × 5/18 ) m/sec.
(ii) x metres / sec = (x × 18/5 )km/hr.
1.    A man covers a certain distance between his house and office on scooter.Having an average speed of 30 km/hr, he late by 10 min. However, with a speed of 40 km/hr. he reaches his office 5 min earlier. Find the distance between his house and office.
(1) 20 km                          (2) 40 km
(3) 30 km                          (4) 25 km

2.    A man car does a journey in 10 hrs, the first half at 21 km/hr and the second half at 24 km/hr. Find the distance.
(1) 220 km                                    (2) 215 km
(3) 210 km                                    (4) 224 km

3.    Walking 3/4 of his usual speed, a person is 10 min late to his office. Find his usual time to cover the distance.
(1) 10 minutes                   (2) 50 minutes
(3) 30 minutes                   (4) None of these

4.    Running 4/3 of his usual speed, a person improves his timing by 10 minutes. Find his usual time to cover the distance.
(1) 60 minutes                   (2) 40 minutes
(3) 25 minutes                   (4) 30 minutes

5.    A train travelling 25 km an hour leaves Delhi at 9 a.m. and another train travelling 35 km an hour starts at 2 p.m. in the same direction. How many km from Delhi will they be together?
(1) 437 ½ km                    (1) 436 ½ km
(3) 435 ½ km                    (4) 434 ½ km

6.    Two men A and B walk from P to Q, a distance of 21 km, at 3 and 4 km an hour respectively. B reaches Q, returns immediately and meets A at R. Find the distance from P to R.
(1) 18 km                          (2) 20 km
(3) 35 km                          (4) 15 km

7.    A man sets out to cycle from Delhi to Rohtak, and at the same time another man starts from Rohtak to cycle to Delhi. After passing each other they complete their journeys in 3 1/3and 4 4/5hours respectively. At what rates does the second man cycle if the first cycles at 8 km per hour?
(1) 6 2/3                             (2) 5 2/3
(3) 4 2/3                             (4) None of these

8.    A monkey tries to ascend a greased pole 14 metres high. He ascends 2 metres in first minute and slipsdown 1 metre in the alternate minute. If he continues to ascend in this fashion, how long does he take to reach the top?
(1) 25 minutes                   (2) 20 minutes
(3) 15 minutes                   (4) None of these

9.    A man leaves a point P at 6 a.m. and reaches the point Q at 10 a.m. Another man leaves the point Q at 8 a.m. and reaches the point P at 12 noon. At what time do they meet?
(1) 10 a.m.                         (2) 9 a.m.
(3) 9: 30 a.m.                    (4) 8 a.m

10.  Without any stoppage a person travels a certain distance at an average speed of 80 kmph, and with stoppages he covers the same distance at an average of 60 kmph. How many minutes per hour does he stop?
(1) 25minutes                    (2) 15 minutes
(3) 10 minutes                   (4) None of these


Answers  with Solution:
1.    (3) :
Solution: Let the distance be x km.
Time taken to cover x km at 30 km/hr = x/30 hrs
Time taken to cover x km at 40 km/hr = x/ 40 hrs.
Difference between the time taken = 15 min = ¼ hr.
x/30 – x/40 = ¼  or 4x – 3x = 30 or x = 30 km.

Shortcut: (Try this your self)
 Required distance
= Product of two speeds/ Difference of two speeds    x Difference between arrival times.

2.    (4)
Solution:
Let the distance be x km.Then x/2 km is travelled at a speed of 21 km/hr and x/2 km at a speed of 24 km/hr.
Then time taken to travel the whole journey
= x/(2x21) + x/(2 x 24) = 10 hrs.
so, x =  224 km

Short cut : (Try this your self)
Distance =(2 x Time x S1 x S2 ) / (S1 + S2 )
Where , S1 = Speed during first half and
S2 = Speed during second half of journey

3.    (3) :
Solution:
Let the usual time be x min.
Time taken at ¾ of the usual speed = 4x/3 min
4x/3 – x = 10
x/3 = 10  à x = 30 min.
Shortcut : (Try this your self)
Usual time = Late time / ( 1 ÷ ¾  - 1)  = 10/1/3 = 30 minutes

4.    (2) Shortcut:
 Improved time / (1 -  1 + 4/3 ) = 40 minutes

5.    (1) :
Solution:
The first train has a start of 25 / 5 km and the second train gains ( 35 – 25 ) or 10 km per hour.
The second train will gain 25 x 5 km in  (25 x5) / 10 or 12 ½ hours.
The required distance from Delhi = 12 ½ x 35 km = 437 ½ km

Shortcut : (try this )
Meeting point’s distance from starting point
= (S1 x S2 x Difference in time) / Difference in speed      ( S1 and S2 are the speed  )

6.    (1)
Solution:
When B meets A at R, B has walked the distance PQ + QR and A the distance PR. That is , both of them have together walked twice the distance from P to Q, i.e 42 km.
Now the rates of A and B are 3 : 4 and they have walked 42 km.
Hence the distance PR travelled by A = 3/7 of 42 km = 18 km

7.    (1)
Solution:
If two persons ( or train) A and B start at the same time in opposite directions from two points  and arrive at the pint a and b hrs respectively after having met, then
A’s rate : B’s rate = √b : √a
= (√ 4 4/5 ) / ( √3 1/3 ) = 6/5
2nd man’s rate = 5/6 x 8  =  6 2/3 km/hr.

8.    (1)
Solution:
 In every 2 minutes he is able to ascend 2 – 1 = 1 metre. This way he ascends upto 12 metres because when he reaches at the top. He does not slip down. thus, upto 12 metres he takes 12 x 2 = 24  minutes and for the last 2 metres he takes 1 minutes. Therefore he takes 24 + 1 = 25 minutes to reach the top.

9.    (2)
Solution:
 Let the distance PQ = A km.
And they meet x hrs after the first man starts.
Average speed of first man = A/10 – 6 = A /4 km/hr
Average speed of second man = A / 12 – 8 = A / 4 K/hr.
distance travelled by first man = Ax/4 km
They meet x hrs and the first man starts. The second man, as he starts 2 hrs late, meets after ( x- 2 ) has from has start. Therefore, the distance travelled by the second man = A(x-2) / 4 km
Now , Ax/4 +  A (x-2) /4  km = A
x = 3 hrs.
They meet at 6 a.m. + 3 hrs = 9 a.m.

Shortcut: (Try this your self)
= Starting time + [ ( Time taken by first ) (2nd’s arrival time – 1st starting time ) ] / (sum of time taken by both)

10.  (1)
Solution:
 Let the total distance be x km.
Time taken at the sped of 80 km/hr = x/80 hrs.
Time taken at the sped of 60 km/hr = x/60 hrs.
He rested for ( x/60 – x/80) hrs = 20x / 60 x 80 = x/240 hrs.
his rest per hour = x/240 ÷ x/60 = ¼ hrs. = 15 minutes.

41 comments:

Anonymous said...

Thanks..
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Anonymous said...

Please sir provide same for man and work.... please

Anonymous said...

Please sir provide same for man and work.... please

Anonymous said...

Any one writing this day rrb exam pleas tell me the questions,,plz

Anonymous said...

thanks...do provide us this type of material of profit n loss

Vikesh said...

Kive hoya exam??? Ki ki aya c and g.a kive i c banking ya g.a and reg math kessa tha plz reply

Anonymous said...

Aare sir Rrb me kaisa questions aaya eska to block banao. How was ur RRB?

Anonymous said...

plzzzzzz frnds share some question which are asked in ur today's paper cozzzzz bahut se logo ka kl exam hai to hm logo ko help mil jayegi....
thanx in advance frnds......

Anonymous said...

how was the paper today?plz share your exp who given the paper today.

Anonymous said...

bharat chatri belongs to which sport

Neha Sharma said...

Hockey

Anonymous said...

hii frnds hw was ur rrb exam?

pls share

vkj said...

Sir rrb ka exam huye 2 ghante ho ge hai or aapne abhi tak uska blog bhi nehi banaya...sir plz tohra active hoyiye.....be fast

Anonymous said...

Bhai Logo GK last 3 months ki pad lo...aj ki GK moderate to difficult thi.

Anonymous said...

CEO of world economic forum?
Blue resolution for ?
last country of europion union ?

Anonymous said...

Governer of RBI?
Question on CRR?
Saarc headquater?

Anonymous said...

bhai plzzz ques post kar do nd btao eng , comp sab sections kase aye the,,, plz kal exam h hum sabka???

Anonymous said...

few ga q&a

rrb governor – rajan
blue revolution – fish
turning point authour – kalam
global peace award – nelson mandela
rtgs limit – no limi
ceo of wprld economic forum… klaus schwab
saarc head office- nepal
european newly joined cntry – bulgeria

pankaj said...

thanks admin for the mathematics shorcuts..you give it after a long time.Good for preparation.

Anonymous said...

Pls share questions bhai log ......

Anonymous said...

frens provide ur comment in english

Anonymous said...

newly joined european country is croatia

Anonymous said...

how s tody rrb po exam, share ur experience pls

share the questions pls

Anonymous said...

please share banking awareness questions asked in rrb....please

Anonymous said...

Last ans will be Croatia.

Anonymous said...

Last ans will be Croatia.

Anonymous said...

How was maths and English section in today's exam.

Anonymous said...

How was maths and English section in today's exam.

lusi said...

Exam online hai na anyone reply am going to write exam for the first time pls frnds reply me..

Anonymous said...

thanxs yr.......
nd plzzzzz btao math,nd computer kaisa tha

S r i N u said...

exam is online

Anonymous said...

ASCII full form

Suchismita said...
This comment has been removed by the author.
Suchismita said...

American Standard Code of Information Interchange

pOOja DaHauliYa said...

thanx...syd kuch help mil jae kal

Rahul said...

Hey pooja.. Pls share the questions you faced today in the RRB exams..

niteesh singh said...
This comment has been removed by the author.
Anonymous said...

plz admin provide shortcuts for work and time and for mixture & alligations as well

Anonymous said...

Sir, please provide shortcuts for D.I

Anish Babu said...
This comment has been removed by the author.
nithish said...

sir plz help to solve quant with short cuts

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