Friday, 14 August 2015

Banking Pathway : 2015 Quant Quiz

1.The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).
a.8,20 ,28
b.20 ,35 ,45
c.16,28,36
d.12 ,24 ,36
e.None of the above



2.A and B can do a job together in 7 days. A is 7/4 times as efficient as B. The same job can be done by A alone in :
a.28/3 Days
b.11 days
c.49/4 Days
d.49/3 days
e.None of the above

3.Twenty Girls can do a work in sixteen days. Sixteen Boys can complete the same work in fifteen days. What is the ratio between the capacity of a Boys and a Girls?
a.3:4
b.4:3
c.5:3
d.1 :3
e.None of these

4.The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is:
a.504
b.536
c.544
d.548
e.600

5.The average weight of X, Y and Z is 45 kg. If the average weight of X and Y be 40 kg and that of Y and Z be 43 kg, then the weight of Y is:
a.17 kg
b.20 kg
c.26 kg
d.31 kg
e.34 kg

6.Two taps A and B can fill a cistern in 15 and 30 minutes respectively. There is a third exhaust tap C at the bottom of tank. If all taps are opened at the same time, the cistern will be full in 25 minutes. In what time can exhaust tap C empty the cistern when full? 

a.10 Min
b.12 Min
c.11 Min
d.8 Min
e.14 Min

7.Vijay Wada is at a distance of 340 km from Hyderabad. A train starts from Hyderabad to Vijay Wada at 4 A.M. with a speed of 60 km/hr. Another train starts from Vijay Wada to Hyderabad at 5 A.M. with a speed of 80 km/hr. At what distance from Hyderabad will the two trains cross each othe r and also find the time when they cross each other? 
a.6.30 AM
b.7.15 AM
c.7.00 AM
d7.30 AM
e.8.00 AM

8.A alone can do a piece of work in 6 days and B alone in 8 days. A and B undertook to do it for Rs. 3200. With the help of C, they completed the work in 3 days. How much is to be paid to C
a.Rs.300
b.Rs. 400
c.Rs. 500
d.Rs. 600
e.Rs. 450

9.A contractor undertakes to do a piece of work in 150 days, so he deployed 200 men. He found that only a quarter of work is done in 50 days. How many additional men must be deployed so that the work may be finished on time?
a.Rs.105
b.Rs. 110
c.Rs. 95
d.Rs. 100
e.Rs. 120

10.A rectangular park 60 m long and 40 m wide has two concrete crossroads running in  the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
a.2.91 M
b.5.82 M
c.3.0 M
d.3.5 M
e.None of these

Answers :
1.C
Let their present ages be 4x, 7x and 9x years respectively.
Then, (4x - 8) + (7x - 8) + (9x - 8) = 56
  20x = 80
  x = 4.
  Their present ages are 4x = 16 years, 7x = 28 years and 9x = 36 years respectively.

2.B
(A's 1 day's work) : (B's 1 day's work) =7/4 :1 = 7:4
Let A's and B's 1 day's work be 7x and 4x respectively.
Then, 7x + 4x =1/7   x = 1/77
A's 1 day's work = 1 X7 /77 = 1/11
= 11 Days

3.B
(20 x 16) Girls can complete the work in 1 day.

1 Girl's 1 day's work = 1/320
     (16 x 15) Boy can complete the work in 1 day.
1 Boy ‘s 1 day's work = 1/240

Req. ratio = 1/240  : 1/320

= 4:3

4.D  Required number = (L.C.M. of 12, 15, 20, 54) + 8
    = 540 + 8   = 548.

5.D
X + Y + Z = (45 x 3) = 135 .... (i)
X + Y = (40 x 2) = 80 .... (ii)
Y + Z = (43 x 2) = 86 ....(iii)
Adding (ii) and (iii), we get: X + 2Y + Z = 166 .... (iv)
Subtracting (i) from (iv), we get : Y = 31.
  Y's weight = 31 kg.

6.A
Here, X = 15, Y = 30 and Z = 25

C can empty the full tank in = (XYZ /YZ +ZX –XY) Minutes
= ( 15*30*25/ ( 30*25 +15*25 -15*30)
= 11250/1125 = 10 Minutes


7.C

s1 = 60, s2 = 80, T = time from 4 A.M. to 5 A.M. = 1 hr

Distance of meeting point from Hyderabad = S1 {( d +S2 t) / (S1 +S2)} km

= 60 {( 340 + 80X1) / (60+80)} = 180 km

Time of their meeting = {( d +S2 t) / (S1 +S2)}
{( 340 + 80X1) / (60+80)}

3 Hrs after 4 o clock

@ 7:00 AM


8.B

C's 1 day's work =

1/3−( 1/6+ 1/8) = (1 / 3 − 7 /24)

=1/ 24

=  A:B:C=1/ 6:1/8:1/ 24

=4:3:1

C′s Share=3200 * 1/8 =400

9.D
200men x 50Days = 1/4 of work ,
so Total work = 200*50*4.

Now Let extra Men required is x
Therefore, (200+x)*100(remaining Days) =3/4 of work (That is remaining work).
So , (200+x)*100 = 200*50*4*(3/4)
=> 200+x=300
=> x= 100




10. C


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