**1.The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).**

a.8,20 ,28

b.20 ,35 ,45

c.16,28,36

d.12 ,24 ,36

e.None of the above

**2.A and B can do a job together in 7 days. A is 7/4 times as efficient as B. The same job can be done by A alone in :**

a.28/3 Days

b.11 days

c.49/4 Days

d.49/3 days

e.None of the above

**3.Twenty Girls can do a work in sixteen days. Sixteen Boys can complete the same work in fifteen days. What is the ratio between the capacity of a Boys and a Girls?**

a.3:4

b.4:3

c.5:3

d.1 :3

e.None of these

**4.The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is:**

a.504

b.536

c.544

d.548

e.600

**5.The average weight of X, Y and Z is 45 kg. If the average weight of X and Y be 40 kg and that of Y and Z be 43 kg, then the weight of Y is:**

a.17 kg

b.20 kg

c.26 kg

d.31 kg

e.34 kg

**6.Two taps A and B can fill a cistern in 15 and 30 minutes respectively. There is a third exhaust tap C at the bottom of tank. If all taps are opened at the same time, the cistern will be full in 25 minutes. In what time can exhaust tap C empty the cistern when full?**

a.10 Min

b.12 Min

c.11 Min

d.8 Min

e.14 Min

**7.Vijay Wada is at a distance of 340 km from Hyderabad. A train starts from Hyderabad to Vijay Wada at 4 A.M. with a speed of 60 km/hr. Another train starts from Vijay Wada to Hyderabad at 5 A.M. with a speed of 80 km/hr. At what distance from Hyderabad will the two trains cross each othe r and also find the time when they cross each other?**

a.6.30 AM

b.7.15 AM

c.7.00 AM

d7.30 AM

e.8.00 AM

**8.A alone can do a piece of work in 6 days and B alone in 8 days. A and B undertook to do it for Rs. 3200. With the help of C, they completed the work in 3 days. How much is to be paid to C**

a.Rs.300

b.Rs. 400

c.Rs. 500

d.Rs. 600

e.Rs. 450

**9.A contractor undertakes to do a piece of work in 150 days, so he deployed 200 men. He found that only a quarter of work is done in 50 days. How many additional men must be deployed so that the work may be finished on time?**

a.Rs.105

b.Rs. 110

c.Rs. 95

d.Rs. 100

e.Rs. 120

**10.A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?**

a.2.91 M

b.5.82 M

c.3.0 M

d.3.5 M

e.None of these

**Answers :**

1.C

Let their present ages be 4x, 7x and 9x years respectively.

Then, (4x - 8) + (7x - 8) + (9x - 8) = 56

20x = 80

x = 4.

Their present ages are 4x = 16 years, 7x = 28 years and 9x = 36 years respectively.

2.B

(A's 1 day's work) : (B's 1 day's work) =7/4 :1 = 7:4

Let A's and B's 1 day's work be 7x and 4x respectively.

Then, 7x + 4x =1/7 x = 1/77

A's 1 day's work = 1 X7 /77 = 1/11

= 11 Days

3.B

(20 x 16) Girls can complete the work in 1 day.

1 Girl's 1 day's work = 1/320

(16 x 15) Boy can complete the work in 1 day.

1 Boy ‘s 1 day's work = 1/240

Req. ratio = 1/240 : 1/320

= 4:3

4.D Required number = (L.C.M. of 12, 15, 20, 54) + 8

= 540 + 8 = 548.

5.D

X + Y + Z = (45 x 3) = 135 .... (i)

X + Y = (40 x 2) = 80 .... (ii)

Y + Z = (43 x 2) = 86 ....(iii)

Adding (ii) and (iii), we get: X + 2Y + Z = 166 .... (iv)

Subtracting (i) from (iv), we get : Y = 31.

Y's weight = 31 kg.

6.A

Here, X = 15, Y = 30 and Z = 25

C can empty the full tank in = (XYZ /YZ +ZX –XY) Minutes

= ( 15*30*25/ ( 30*25 +15*25 -15*30)

= 11250/1125 = 10 Minutes

7.C

s1 = 60, s2 = 80, T = time from 4 A.M. to 5 A.M. = 1 hr

Distance of meeting point from Hyderabad = S1 {( d +S2 t) / (S1 +S2)} km

= 60 {( 340 + 80X1) / (60+80)} = 180 km

Time of their meeting = {( d +S2 t) / (S1 +S2)}

{( 340 + 80X1) / (60+80)}

3 Hrs after 4 o clock

@ 7:00 AM

8.B

C's 1 day's work =

1/3−( 1/6+ 1/8) = (1 / 3 − 7 /24)

=1/ 24

= A:B:C=1/ 6:1/8:1/ 24

=4:3:1

C′s Share=3200 * 1/8 =400

9.D

200men x 50Days = 1/4 of work ,

so Total work = 200*50*4.

Now Let extra Men required is x

Therefore, (200+x)*100(remaining Days) =3/4 of work (That is remaining work).

So , (200+x)*100 = 200*50*4*(3/4)

=> 200+x=300

=> x= 100

10. C

## No comments:

## Post a Comment