Tuesday, 29 September 2015

Mission IBPS Exam : Quant Exam (Time and Distance)

1. Two horses start trotting towards each other, one from A to B and another from B to A. They cross each other after one hour and the first horse reaches B, 5 /6 hour before the second horse reaches A. If the distance between A and B is 50 km. What is the speed of the slower horse?
(a) 30 km/h
(b) 15 km/h
(c) 25 km/h
(d) 20 km/h
(e) none of these 

2. Pankaj walked at 5  km/h for certain part of the journey and then he took an auto for the remaining part of the journey travelling at 25 km/h. If he took 10 hours for the entire journey, what part of journey did he travelled by auto if the average speed of the entire journey be 17 km/h :
(a) 750 km
(b) 100 km
(c) 150 km
(d) 200 km
(e) none of these

3. Two trains A and B start simultaneously in the opposite direction from two points P and Q and arrive at their destinations 16 and 9 hours respectively after their meeting each other. At what speed does second train B travel if the first train travels at 120 km/h per hour:
(a) 90 km/h
(b) 160 km/h
(c) 67.5 km/h
(d) 80 km/h
(e) none of these 

4. Abhinav started for the station half a km from his home walking at 1 km/h to catch the train in time. After 3 minutes he realised that he had forgotten a document at home and returned with increased, but constant speed to get it succeded in catching the train. Find his latter speed in km/h:
(a) 1.25
(b) 1.1
(c) 11/9
(d) 2
(e) none of these 

5. Train X starts from point A for point B at the same time that train Y starts from B to A. Point A and B are 300 km apart. The trains are moving at a constant speed at least at 25 km/h. The trains meet each other 3 hours after they start. If the faster trains takes at least 2 more hours to reach the destination. By which time will the slower train have definitely reached its destination? (Ignoring the length of trains in crossing)
(a) 4 hours after the start
(b) 7.5 hours after the start 
(c) 6 hours after the start
(d) 7 hours after the start
(e) none of these


6. In reaching the Purnagiri a man took half as long again to climb the second third as he did to climb the first third and a quarter as long again for the last third as for the second third. He took altogether 5 hs 50 minutes. Find the time he spent on the first third of the journey?
(a) 72 min
(b) 80 min
(c) 81 min
(d) 88 min
(e) none of these

7. A boat covers 48 km upstream and 72 km downstream in 12 hours, while it covers 72 km upstream and 48 downstream in 13 hours. The speed of stream is :
(a) 2 km/h
(b) 2.2 km/h
(c) 2.5 km/h
(d) 4 km/h
(e) none of these

8. A motor boat takes 2 hours to travel a distance of 9 km downstream and it takes 6 hours to travel the same distance against the current. The speed of the boat in still water and that of the current (in km/h) respectively are :
(a) 6, 5
(b) 3, 1.5
(c) 8, 5
(d) 9, 3
(e) none of these

9. A coolie standing on a railway platform observes that a train going in one direction take 4 seconds to pass him Another train of same length going in opposite direction takes 5 seconds to pass him. The time taken (in seconds) by the two trains to cross each other will be :
(a) 35
(b) 36.5
(c) 40/9
(d) 45
(e) none of these

10. Pushpak express leave Lucknow at 6 am and two hours later another train Bhopal express leaves Lucknow. Both trains arrive Bhopal at 4 pm on the same day. If the difference between their speeds be 10 km/h, what is the average speeds of both the trains over entire route :
(a) 40 km/h
(b) 44(4/9) km/h
(c) 42(3/5) km/h
(d) 43 km/h
(e) none of these


Answers

1.(D)
Let speed of faster horse = x
& speed of slower horse = y
x + y = 50/1
x + y = 50 ---- (I)
50/y – 50/x = 5/6 ---- (II)
With the help of option
x = 30 kmph
y = 20 kmph

2.(C)
Total distance = 17*10=170
Let Journey travelled by auto in x hr
25 * x + (10-x ) 5 = 170
25 x + 50 – 5x = 170
x = 6
Required Ans = 6 * 25 = 150 km

3.(B)
S1/S2 = (9/16)^1/2
S1/S2 = ¾
3 = 120
4 = 160

4.(C)
Distance covered in 3 minute = 3*(1000/60) = 50
Now he has to cover (500+50) meters in (30-3) minutes
Required speed = (550/1000)/(27/60) = 11/9 km/h

5.(B)
Let Speed of train x = a kmph
& Speed of train y = b kmph
a + b = 300/3 = 100 kmph
The faster trains takes be atleast = (3+2) hr = 5 hr
i.e speed of slower train = 40 kmph
i.e time = 300/40 = 7.5 hr

6.(B)
Let the time token in first third part of the Journey be x minute, then  the required in second third part of the Journey is 3x/2 & in the last third part of the Journey time required is 15x/8
i.e x+3x/2+15x/8=350 min
x = 80 min

7.(A)
From 1st condition
48/u+72/d = 12 ---- (I)
72/u+48/d = 13 ---- (II)
From eq (I) & (ii)
u = 8 kmph
d = 12 kmph
Speed of streem = (12-8)1/2 = 2 kmph

8.(B)
D = 9/2 = 4.5 kmph
U = 9/6 = 1.5 kmph
x = (4.5+1.5) 1/2 = 3.5 kmph
y = (4.5-1.5)1/2 = 1.5 kmph

9.(C)
Let speed of 1st train = x m/s
& speed of other train = y m/s
(d/x)/(d/y) = 4/5
y/x = 4/5
Required time = (d+d)/(x+y)
= (4x+5y)/(x+y)
=( 4*5+5*4)/(4+5) = 40/9

10.(B)
Let speed of 1st train = x kmph
& speed of 2nd train = (x+10) kmph
So,
X*10 = (x+10) 8
X= 40 kmph
Required Average speed = (2*40*50)/(40+50) = 44(4/9)



No comments:

Post a Comment