**Directions (Q. 1–5): In each question two equations are provided on the basis of these you have to find the relation between x and y. Give answer:**

*1) If x > y*

*2) If x >= y*

*3) If x < y*

*4) If x <= y*

*5) If x = y or no relationship between x and y exists*
1.

I. 42x² + 59x + 20 = 0

II. 20y² – y – 1 = 0

2.

I. 3x² – 7x + 2 = 0

II. 2y² + 9y + 9 = 0

3.

I. x² + 11x + 30 = 0

II. y² + 13y + 42 = 0

4.

I. 6x² + 17x + 7 = 0

II. y² +10y + 21 = 0

5.

I. 20x² – 53x + 35 = 0

II. 3y² – 20y + 32 = 0

**Directions (Q. 6 –10): In the following number series only one number is wrong. Find out the wrong number.**

**6. 118, 137, 176, 238, 314, 413**

1) 238

2) 137

3) 118

4) 413

5) 176

**7. 2, 3, 12, 39, 172, 885**

1) 39

2) 3

3) 885

4) 12

5) 172

**8. 1434, 1484, 717, 239, 59.75, 11.95**

1) 1484

2) 11.95

3) 717

4) 239

5) 1434

**9. 219, 340, 484, 653, 849, 1067, 1330**

1) 340

2) 1330

3) 1067

4) 653

5) 849

**10. 29, 43, 71, 113, 169, 248**

1) 169

2) 113

3) 29

4) 43

5) 248

**Answers:**

1. 3

I. 42x² + 24x + 35x + 20 = 0

(6x + 5) (7x + 4) = 0

x = -5/6, -4/7

II. 20y² – 5y + 4y –1 = 0

(5y + 1) (4y –1) = 0

y = -1/5, 1/4

y > x

2. 1;

I. 3x² –x – 6x + 2 = 0

(x – 2) (3x – 1) = 0

x = 2, 1/3

II. 2y² + 3y + 6y + 9 = 0

(y + 3) (2y + 3) = 0

y = – 3, -3/2

x > y

3. 2;

I. x² + 6x + 5x + 30 = 0

(x + 5) (x + 6) = 0

x = –5, –6

II. y² + 7y + 6y + 42 =0

(y + 6) (y + 7) = 0

y = – 6, –7

x >= y

4. 1

I. 6x² + 14x + 3x + 7 = 0

(3x + 7) (2x + 1) = 0

x = -7/3, -1/2

II. y² + 3y +7y + 21 = 0

(y + 7) ( y + 3) = 0

y = –7, –3

x > y

5. 3

I. 20x² – 28x – 25x + 35 = 0

(5x –7) (4x – 5) = 0

x = 7/5, 5/4

II. 3y² – 8y – 12y + 32 = 0

(3y – 8) (y – 4) = 0

y = 8/3, 4

y > x

6. 1

7. 4

8. 1

9. 3

10. 5

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