**Directions (1-5):**

**1. The seller marked the price of the item D same at its Cost price. Find the profit/loss percentage on item D?**

10% Loss

20% Loss

10% Profit

20% Profit

Solution:

CP = MP = 350

SP = 350 * 90/100 = 315

Loss% = (350 – 315)/350 * 100 = 10%

SP = 350 * 90/100 = 315

Loss% = (350 – 315)/350 * 100 = 10%

**2. The Cost price of item A is same as the cost price of item B. If the seller decides to mark the price 7% more than the Cost price, then how much discount should he offer so that he makes no profit or loss on selling the item?**

6.54%

5.54%

6.14%

5.64%

Data insufficient

Solution:

Let the discount offered be ‘x’ %

MP = 107/100 * 100 = 107

SP is same as CP,

100 = 107/100 * (100 – x)

100 – x = 93.45

x = 6.54%

MP = 107/100 * 100 = 107

SP is same as CP,

100 = 107/100 * (100 – x)

100 – x = 93.45

x = 6.54%

**3. What is the Cost price of item C?**

Rs 100

Rs 120

Rs 150

Rs 200

Data insufficient

Solution:

SP = 220 * 80/100 = 176

CP = 176 * 100 / (100+17.34)

CP = 150

CP = 176 * 100 / (100+17.34)

CP = 150

**4. The seller marks the price of item E double the cost price. What is the percentage profit/loss he will make on the item?**

25% Profit

100% Profit

25% Loss

No Profit No Loss

50% Profit

Solution:

SP = 620 * 75/100 = 465

CP = MP/2 = 620/2 = 310

% Profit = (465 – 310)/310 * 100 = 50%

CP = MP/2 = 620/2 = 310

% Profit = (465 – 310)/310 * 100 = 50%

**5. What is the average of Cost price of the five items?**

Rs 150

Rs 178

Rs 220

Rs 232

Rs 202

Solution:

Average = (100+100+150+350+310)/5=202 Rs

**Directions (6-10): Study the following graph and answer the questions below.**

**Table shows the population and percentage increase/decrease of three cities in year 2001 and 2002.**

**6. What was the population (in Lakhs) of Shimla in 2001?**

1.36

1.26

1.25

1.10

1.40

Solution:

Population of Shimla in 2001 = 1.5 * 100/110 = 1.36 Lakhs

**7. The population of Nainital in 2002 was same as that of of Shimla in 2001, then find average of total population of three cities over 2001 and 2002?**

1.98 Lakhs

1.65 Lakhs

2.11 Lakhs

2.25 Lakhs

2.02 Lakhs

Solution:

Population of Nainital in 2001 = 1.36 * 100/92 = 1.48

Average = (1.36+1.50+3+4+1.48+1.36)/6=12.7/6=2.11 Lakhs

Average = (1.36+1.50+3+4+1.48+1.36)/6=12.7/6=2.11 Lakhs

**8. What is the percentage increase in the population of Ooty from 2001 to 2002?**

66 1/3 %

33 2/3 %

33 1/3 %

66 2/3 %

50 %

Solution:

**9. If in Shimla, population increases by 10% every year, then what was the population (approximately) of Shimla in 2005?**

1.5 Lakhs

1.75 Lakhs

2.25 Lakhs

2.50 Lakhs

2 Lakhs

Solution:

Population of Shimla in 2005 = 1.5* (110/100)*(110/100)*(110/100)=1.99=2 Lakhs

**10.The population of Shimla in 2001 is what percent less than population of Ooty in 2002?**

33%

55%

22%

66%

76%

Solution:

Required % = (4-1.36)/4*100=(2.64/4)*100=66%

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