Reasoning Study Notes: Direction Sense Test and Ranking
Dear Readers,
Today we’ll discuss about Direction Sense. This topic is can fetch you marks easily but you need to know the right concepts and types of questions to practice.
Directions:
Tips:
➀ Read the instructions of the question carefully and mark the points and make a diagram for reference. This will save your time while solving the questions and help you in maintaining accuracy.
Example: Yashita and Sahil are two friends walking in a maze garden. Yashita is on a mark Q and moves ahead in north for 8 meters to point R, then she takes a left turn and after walking 6 meters reaches point S. She now takes a right turn 4 meters reaches point T, then she takes a left turn and after 6 meters reaches point U and she sits down to take some rest. Meanwhile Sahil who is at point B which is 4 meters to the south of point U, walks 8 meters south and takes a left turn and after walking 6 meters reaches point P and rests there.
➁ Concept of shortest distance: Application of Pythagoras theorem
Example:
Sonal Ranks 16th from the top and 15th from the Bottom in a certain examination. How many students are there in her class?
Solution :
Clearly the who class consists of :
(i) 15 students who have a rank higher thanSonal
(ii) 14 students who have rank lower than Sonal
that is (15 + 1 + 14) = 30
Types of Questions for Direction Sense Test and Ranking
Today we’ll discuss about Direction Sense. This topic is can fetch you marks easily but you need to know the right concepts and types of questions to practice.
Tips:
➀ Read the instructions of the question carefully and mark the points and make a diagram for reference. This will save your time while solving the questions and help you in maintaining accuracy.
Example: Yashita and Sahil are two friends walking in a maze garden. Yashita is on a mark Q and moves ahead in north for 8 meters to point R, then she takes a left turn and after walking 6 meters reaches point S. She now takes a right turn 4 meters reaches point T, then she takes a left turn and after 6 meters reaches point U and she sits down to take some rest. Meanwhile Sahil who is at point B which is 4 meters to the south of point U, walks 8 meters south and takes a left turn and after walking 6 meters reaches point P and rests there.
➁ Concept of shortest distance: Application of Pythagoras theorem
Example: Q. (Refer the above example for directions.)Point R happens to be the
exit point of the maze garden which apparently Yashita had missed and walked
past the point. Sahil recognised it and walks the shortest distance from his
resting point and exits the maze garden. How much has he walked from his starting
point?
(a)
24
(b)
28
(c)
10
(d)
26
(e)
20
Now
to get the answer of this question we have to find the distance PR. We can see PQR
forms a right angled triangle and hence Pythagoras Theorem can be applied to
it. The theorem states that Hypotenuse =
sq. root ( (Base)^{2} + (Perpendicular)^{2})
PR
=√ ((PQ)^{2 }+ (QR)^{2}) = √ (36+64) =√ 100 = 10
Hence
PR= 10 meters.
Example
2: Two friends Harish and Pankaj lives in the same neighborhood and their
houses are 3 Kilometers apart linearly. Harish’s house’s front door faces
North West and Pankaj’s house’s front door faces North and two roads end at
their front doors from a nearest junction. Another road from that junction
leads towards a Coffee House. Every evening Harish walks 5 Kilometers to the
junction and takes a right turn and after 12 kilometer he reaches the Coffee
House.
Q1.
How much distance Pankaj has to walk on the road from his house to reach the
junction and in which direction is the Coffee House?
Q2.
One day while returning from the Coffee House Harish discovers that there is a
shortcut and a direct way from the coffee house to his residence, and he walk’s
the shortest distance and reaches back home. What is the total distance he has
walked in that trip?
Solution
1:
Direction of Coffee House is NorthEast.
And,
distance of Pankaj has to walk on the road to the junction:
Let
Harish’s house be point A, Junction be point O and Pankaj’s house be point B.
AO=5,
BA=3, here BO is perpendicular, BA is Base and AO is hypotenuse
BO
= √ ((5)^{2} – (3)^{2}) = 4, Hence distance of Pankaj has to
walk on the road to the junction= 4 Kilometers
Solution
2:
Shortest distance from coffee house to Harish’s house = √((12)^{2} +
(5)^{2}) =13
Total
distance Harish has walked in that trip = 5+12+13= 30 Kilometers.
➂ Be careful of turning left/right directions or information given, one misinterpreted information will lead
you to wrong answer for the simplest of the questions.
➃ In Ranking questions generally the ranks of a person both from the top and from the bottom are mentioned and the total number of persons is asked. However, sometimes the question is put in the form of a puzzle of interchanging seats by two persons.
Left +
Left

Down

Left +
Right

Up

Right +
Right

Down

Up + Left

Left

Up + Right

Right

Down +
Left

Right

Down +
Right

Left

➃ In Ranking questions generally the ranks of a person both from the top and from the bottom are mentioned and the total number of persons is asked. However, sometimes the question is put in the form of a puzzle of interchanging seats by two persons.
Example:
Sonal Ranks 16th from the top and 15th from the Bottom in a certain examination. How many students are there in her class?
Solution :
Clearly the who class consists of :
(i) 15 students who have a rank higher thanSonal
(ii) 14 students who have rank lower than Sonal
that is (15 + 1 + 14) = 30
Types of Questions for Direction Sense Test and Ranking
These two topics are incorporated mainly in three types of questions:
✔ Puzzles
✔ Data Sufficiency
✔ Direct Question of Direction
✔ Puzzles
✔ Data Sufficiency
✔ Direct Question of Direction
Practice Direction Sense Test and Ranking Questions
No comments