Dear Aspirants,

### Reasoning Quiz for IBPS PO Mains 2018

Reasoning Ability is an onerous section. With the increasing complexity of questions, it becomes hard for one to give it the cold shoulder. The only way to make the grade in this particular section in the forthcoming banking exams like IBPS PO Mains is to practice continuously with all your heart and soul. And, to let you practice with the best of the latest pattern questions, here is the Adda247 Reasoning Quiz based on the exact same pattern of questions that are being asked in the exams.

Directions (1-5): Study the following information carefully and answer the questions which follow.

Seven persons of a family i.e. A, B, C, D, E, F and G are seated in a row, four of them are facing to north and three of them are facing to south. Also each of them goes market on different day’s i.e.-Saturday, Wednesday, Sunday, Tuesday, Monday, Friday and Thursday. Both persons who sit on corners face north. There are three generations in the family.

G’s grandchild is seated fourth to the right of him, who is immediate left of one who goes market on Sunday. B’s brother-in-law is seated third to the left of one, who goes market on Thursday. B is the niece of F. The one who goes market on Tuesday sits third to the right of E’s child. C is neither the second generation person of the family nor father-in-law of E. There are two persons between C’s daughter and G’s sister. The one who goes market on Monday sits third to the left of D’s maternal grandmother, who faces to south. E is the father of D and son-in-law of G. The one who goes market on Saturday sits second to the left of C’s sister-in-law, who is not near to one, who goes market on Wednesday. E’s brother is seated at an extreme end but not near to E’s father-in-law.

Q1. Who sits third to the left of G’s wife?

No-one
E
B
G
A
Solution:
From the given conditions, first we try to complete blood relation tree. We have some given points in the conditions. By using these points we can deduce blood-relation tree. The given points are like as G’s grandchild, B’s brother-in-law, B is the niece of F, E’s child; C is neither the second generation person of the family nor father-in-law of E, C’s daughter, G’s sister, D’s maternal Grandmother, E is father of D and son-in-law of G, C’s sister-in-law, E’s brother, E’s father-in-law.
Blood-Relation Tree-

Now we can start sitting arrangement by using rest given conditions.
G’s grandchild is seated fourth to the right of him, who is immediate left of one who goes market on Sunday. The one who goes market on Tuesday sits third to the right of E’s child. From that conditions there are two possibilities occur.
Case-1

Case-2

From the conditions, B’s brother-in-law is seated third to the left of one, who goes market on Thursday. E’s brother is seated at an extreme end but not near to E’s father-in-law. The one who goes market on Monday sits third to the left of D’s maternal grandmother, who faces to south. There are two persons between C’s daughter and G’s sister. From those conditions we deduce the following.Case-1

Case-2

From the rest conditions, both persons who sit on corners face north, Hence Case-1 is eliminate and Case-2 is continued. The one who goes market on Saturday sits second to the left of C’s sister-in-law, who is not near to one, who goes market on Wednesday. Hence F sits immediate left of C.
Final arrangement are-

Blood-Relation Tree-

Q2. How many persons sit/s between A and his sister-in-law?
Four
Five
One
Two
None of these
Solution:
From the given conditions, first we try to complete blood relation tree. We have some given points in the conditions. By using these points we can deduce blood-relation tree. The given points are like as G’s grandchild, B’s brother-in-law, B is the niece of F, E’s child; C is neither the second generation person of the family nor father-in-law of E, C’s daughter, G’s sister, D’s maternal Grandmother, E is father of D and son-in-law of G, C’s sister-in-law, E’s brother, E’s father-in-law.
Blood-Relation Tree-

Now we can start sitting arrangement by using rest given conditions.
G’s grandchild is seated fourth to the right of him, who is immediate left of one who goes market on Sunday. The one who goes market on Tuesday sits third to the right of E’s child. From that conditions there are two possibilities occur.
Case-1

Case-2

From the conditions, B’s brother-in-law is seated third to the left of one, who goes market on Thursday. E’s brother is seated at an extreme end but not near to E’s father-in-law. The one who goes market on Monday sits third to the left of D’s maternal grandmother, who faces to south. There are two persons between C’s daughter and G’s sister. From those conditions we deduce the following.Case-1

Case-2

From the rest conditions, both persons who sit on corners face north, Hence Case-1 is eliminate and Case-2 is continued. The one who goes market on Saturday sits second to the left of C’s sister-in-law, who is not near to one, who goes market on Wednesday. Hence F sits immediate left of C.
Final arrangement are-

Blood-Relation Tree-

Q3. Who sits second to the right of E?
G’s wife
G’s daughter
E’s brother
B’s Father
None of these
Solution:
From the given conditions, first we try to complete blood relation tree. We have some given points in the conditions. By using these points we can deduce blood-relation tree. The given points are like as G’s grandchild, B’s brother-in-law, B is the niece of F, E’s child; C is neither the second generation person of the family nor father-in-law of E, C’s daughter, G’s sister, D’s maternal Grandmother, E is father of D and son-in-law of G, C’s sister-in-law, E’s brother, E’s father-in-law.
Blood-Relation Tree-

Now we can start sitting arrangement by using rest given conditions.
G’s grandchild is seated fourth to the right of him, who is immediate left of one who goes market on Sunday. The one who goes market on Tuesday sits third to the right of E’s child. From that conditions there are two possibilities occur.
Case-1

Case-2

From the conditions, B’s brother-in-law is seated third to the left of one, who goes market on Thursday. E’s brother is seated at an extreme end but not near to E’s father-in-law. The one who goes market on Monday sits third to the left of D’s maternal grandmother, who faces to south. There are two persons between C’s daughter and G’s sister. From those conditions we deduce the following.Case-1

Case-2

From the rest conditions, both persons who sit on corners face north, Hence Case-1 is eliminate and Case-2 is continued. The one who goes market on Saturday sits second to the left of C’s sister-in-law, who is not near to one, who goes market on Wednesday. Hence F sits immediate left of C.
Final arrangement are-

Blood-Relation Tree-

Q4. Which of the following day does D’s mother go to market?
Wednesday
Monday
Thursday
Saturday
None of these
Solution:
From the given conditions, first we try to complete blood relation tree. We have some given points in the conditions. By using these points we can deduce blood-relation tree. The given points are like as G’s grandchild, B’s brother-in-law, B is the niece of F, E’s child; C is neither the second generation person of the family nor father-in-law of E, C’s daughter, G’s sister, D’s maternal Grandmother, E is father of D and son-in-law of G, C’s sister-in-law, E’s brother, E’s father-in-law.
Blood-Relation Tree-

Now we can start sitting arrangement by using rest given conditions.
G’s grandchild is seated fourth to the right of him, who is immediate left of one who goes market on Sunday. The one who goes market on Tuesday sits third to the right of E’s child. From that conditions there are two possibilities occur.
Case-1

Case-2

From the conditions, B’s brother-in-law is seated third to the left of one, who goes market on Thursday. E’s brother is seated at an extreme end but not near to E’s father-in-law. The one who goes market on Monday sits third to the left of D’s maternal grandmother, who faces to south. There are two persons between C’s daughter and G’s sister. From those conditions we deduce the following.Case-1

Case-2

From the rest conditions, both persons who sit on corners face north, Hence Case-1 is eliminate and Case-2 is continued. The one who goes market on Saturday sits second to the left of C’s sister-in-law, who is not near to one, who goes market on Wednesday. Hence F sits immediate left of C.
Final arrangement are-

Blood-Relation Tree-

Q5. How is the person, who goes market on Thursday, related to the person, who goes market on Sunday?
Uncle
Brother-in-law
Aunt
Father
None of these
Solution:
From the given conditions, first we try to complete blood relation tree. We have some given points in the conditions. By using these points we can deduce blood-relation tree. The given points are like as G’s grandchild, B’s brother-in-law, B is the niece of F, E’s child; C is neither the second generation person of the family nor father-in-law of E, C’s daughter, G’s sister, D’s maternal Grandmother, E is father of D and son-in-law of G, C’s sister-in-law, E’s brother, E’s father-in-law.
Blood-Relation Tree-

Now we can start sitting arrangement by using rest given conditions.
G’s grandchild is seated fourth to the right of him, who is immediate left of one who goes market on Sunday. The one who goes market on Tuesday sits third to the right of E’s child. From that conditions there are two possibilities occur.
Case-1

Case-2

From the conditions, B’s brother-in-law is seated third to the left of one, who goes market on Thursday. E’s brother is seated at an extreme end but not near to E’s father-in-law. The one who goes market on Monday sits third to the left of D’s maternal grandmother, who faces to south. There are two persons between C’s daughter and G’s sister. From those conditions we deduce the following.Case-1

Case-2

From the rest conditions, both persons who sit on corners face north, Hence Case-1 is eliminate and Case-2 is continued. The one who goes market on Saturday sits second to the left of C’s sister-in-law, who is not near to one, who goes market on Wednesday. Hence F sits immediate left of C.
Final arrangement are-

Blood-Relation Tree-

Directions (6-10): Study the information carefully answers the questions given below.

Î± means either hour hand or minute hand is at

means either hour hand or minute hand is at 11
® means either hour hand or minute hand is at
£ means either hour hand or minute hand is at
Ã… means either hour hand or minute hand is at
Âµ means either hour hand or minute hand is at
Note: if two symbols are given than by default second symbol is consider as minute hand and first symbol is consider as hour hand. And all time are consider at pm.

Q6. If a man leave from GIP to WOW at ®Ã…. Usually he takes 20 min to reach WOW, but that time he reaches 15 min later, then at what time he will reach WOW?

∞®
®∞
®£
®®
None of these
Solution:
A man leave GIP at ‘®Ã…’ means 6.10, he takes 20 min to reach WOW but he reaches 15 min late means he reach Wow at 6.45 means ‘®£’.

Q7. A person takes 40 minute to reach airport from his office and he has to catch airplane that is scheduled to depart at ‘£Âµ’ so at what time should he leave from his office for the airport to arrive at the airport at 20 minutes earlier?
ÂµÃ…
®∞
Ã…Âµ
Î±Âµ
None of these
Solution:
Airplane departure time is ‘£Âµ’ means 9.25, A person want to reach airport 20 minute earlier means he want to reach airport at 9.05, and he takes 40 minute to reach airport means he should leave office 8.25 means ‘Î±Âµ’.

Q8. If a man leave from his home to office at ‘£∞’ and he takes 2hr to reach his office, at what time he will reach to office?
Âµ£
∞Ã…
∞∞
Can’t be determined
None of these
Solution:
A man leave his home at ‘£∞’ means 9.55, and he takes 2 hour to reach office from his home that means he reaches office at 11.55 means ‘∞∞’.

Q9. If A + B means A is the mother of B; A - B means A is the brother B; A % B means A is the father of B and A x B means A is the son of B, which of the following shows that M is the maternal uncle of Z?
M - N + W x Z
N - M + Z x W
M - N x Z + W
M - N + Z x W
None of these
Solution:

Q10. If A + B means A is the mother of B; A – B means A is the brother B; A % B means A is the father of B and A x B means A is the sister of B, which of the following shows N is the paternal grandfather of A?
N + M ─ B % A × D
N % M ─ B % A × D
N + M ─ B % D × A
N % M ─ A % D × B
None of these
Solution:

Direction (11-15): Study the following diagram and convert it into other diagrams by implementing the instructions which is given in each step to get next step.

For Step-1: Interchange the Alphabets as per the arrows mentioned in the above figure to get step-1.

For step- 2:

(i) If the alphabets contain one vowel and one consonant and number with them is less than 5 then replace the number with its square.
(ii) If the alphabets contain one vowel and one consonant and number with them is greater than 5 then subtract 2 from the given number.
(iii) If the alphabet contains two consonant then change both the letters with their succeeding letter according to alphabetical order.

For Step – 3: Step-3 is coded in some special pattern.

As per the rules followed in the above step, find out the appropriate steps for the given input and answer the following questions.

Q11. Which element comes in step-2 in the second row of third column?

WA20
IJ23
HU18
AX8
None of these
Solution:

For Step-1: Interchange the alphabets as per the arrows mentioned in the above figure to get step –1.

For step- 2:
(i) If the alphabets contain one vowel and one consonant and number with them is less than 5 then replace the number with its square.
(ii) If the alphabets contain one vowel and one consonant and number with them is greater than 5 then subtract 2 from the given number.
(iii) If the alphabet contains two consonant then change both the letters with their succeeding letter according to alphabetical order.

For Step-3: In step 3, the first letter of each element is replaced with the first letter of the element written diagonally opposite to it and the second letter will remain the same. And after this 3 will be added to each even number and 2 will be subtracted from each odd number.

Q12. Which element replaces TG9 from step-2 to step-3?
TL5
VZ20
IH1
UG7
None of these
Solution:

For Step-1: Interchange the alphabets as per the arrows mentioned in the above figure to get step –1.

For step- 2:
(i) If the alphabets contain one vowel and one consonant and number with them is less than 5 then replace the number with its square.
(ii) If the alphabets contain one vowel and one consonant and number with them is greater than 5 then subtract 2 from the given number.
(iii) If the alphabet contains two consonant then change both the letters with their succeeding letter according to alphabetical order.

For Step-3: In step 3, the first letter of each element is replaced with the first letter of the element written diagonally opposite to it and the second letter will remain the same. And after this 3 will be added to each even number and 2 will be subtracted from each odd number.

Q13. Which of the following element is placed just opposite to HS21 in step 3?
UG7
EJ21
TL5
WU21
None of these
Solution:

For Step-1: Interchange the alphabets as per the arrows mentioned in the above figure to get step –1.

For step- 2:
(i) If the alphabets contain one vowel and one consonant and number with them is less than 5 then replace the number with its square.
(ii) If the alphabets contain one vowel and one consonant and number with them is greater than 5 then subtract 2 from the given number.
(iii) If the alphabet contains two consonant then change both the letters with their succeeding letter according to alphabetical order.

For Step-3: In step 3, the first letter of each element is replaced with the first letter of the element written diagonally opposite to it and the second letter will remain the same. And after this 3 will be added to each even number and 2 will be subtracted from each odd number.

Q14. Which of the following element is placed adjacent to IH1 in step 3 in clock-wise direction?
WU9
CX19
EJ21
AX15
None of these
Solution:

For Step-1: Interchange the alphabets as per the arrows mentioned in the above figure to get step –1.

For step- 2:
(i) If the alphabets contain one vowel and one consonant and number with them is less than 5 then replace the number with its square.
(ii) If the alphabets contain one vowel and one consonant and number with them is greater than 5 then subtract 2 from the given number.
(iii) If the alphabet contains two consonant then change both the letters with their succeeding letter according to alphabetical order.

For Step-3: In step 3, the first letter of each element is replaced with the first letter of the element written diagonally opposite to it and the second letter will remain the same. And after this 3 will be added to each even number and 2 will be subtracted from each odd number.

Q15. In Step-3 which of the following number is placed with the alphabet which replaces IJ23 from step 2 to step 3?
9
25
21
11
None of these
Solution:

For Step-1: Interchange the alphabets as per the arrows mentioned in the above figure to get step –1.

For step- 2:
(i) If the alphabets contain one vowel and one consonant and number with them is less than 5 then replace the number with its square.
(ii) If the alphabets contain one vowel and one consonant and number with them is greater than 5 then subtract 2 from the given number.
(iii) If the alphabet contains two consonant then change both the letters with their succeeding letter according to alphabetical order.

For Step-3: In step 3, the first letter of each element is replaced with the first letter of the element written diagonally opposite to it and the second letter will remain the same. And after this 3 will be added to each even number and 2 will be subtracted from each odd number.

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