Dear Aspirants,

Numerical Ability or Quantitative Aptitude Section has given heebie-jeebies to the aspirants when they appear for a banking examination. As the level of every other section is only getting complex and convoluted, there is no doubt that this section, too, makes your blood run cold. The questions asked in this section are calculative and very time-consuming. But once dealt with proper strategy, speed, and accuracy, this section can get you the maximum marks in the examination. Following is the Quantitative Aptitude quiz to help you practice with the best of latest pattern questions.

Q1. The ratio of monthly salaries of two persons, A and B is 8 : 7. If the salary of A is increased by 20% and that of B by 11%, the new ratio becomes 96 : 77. What is A’s salary?
Rs. 800
Rs. 775
Rs. 750
Cannot be determined
None of these

Q2. A 210-metre long train crosses a man running at 9 kmph in opposite direction in 6 seconds. Find the speed of the train.
58 kmph
97 kmph
107 kmph
117 kmph
127 kmph

Q3. Average score of a cricketer in 13 matches is 42 runs. If the average score in the first 5 matches be 54 runs, what is the average score in the last eight matches?
36.5
34.5
35.4
38
None of these
Solution:
Total runs in the last eight matches
= 13×42–5×54=546-270
= 276
∴ Required average
= 276/8=34.5

Q4. The perimeter of a rectangle whose length is 6 metres more than its breadth is 84 metres. What is the area of the triangle whose base is equal to the diagonal of the rectangle and height is equal to the length of the rectangle?
360 sq. metres
380 sq. metres
460 sq. metres
400 sq. metres
540 sq. metres

Q5. Due to decrease of 10% in the price of tea per kg, a consumer buys 250 gm of tea more than before for Rs. 270. What is the original price of tea?
Rs. 130/kg
Rs. 120/kg
Rs. 115/kg
Rs. 140/kg
None of these

Directions (6-10): Study the following graph carefully and answer the following questions Preferences of people (man and children) in buying different ice-cream flavors over the years. Q6. People buying chocolate flavor ice cream in year 2002 and 2003 together are approximately what percent more or less than people buying vanilla flavor ice-cream in 2005 and 2006 together?
5%
8%
12%
15%
6%
Solution:
People buying chocolate flavor in 2002 and 2003 together
=400+300=700
People buying vanilla flavor ice – cream in 2005 and 2006=350+300
=650
Required percentage =50/650×100
=7.69
~ 8% more

Q7. If ratio of man to children buying strawberry flavor ice cream in 2004 is 7 : 5 and children buying vanilla flavor ice cream in 2002 are 120% of children buying strawberry flavor in 2004 then what number of people except children buy vanilla flavor in 2002
150
175
200
225
300

Q8. People buying vanilla flavor ice cream in 2003 are approximately what percent less than people buying all three flavors in 2005?
35%
57%
47%
63%
38%
Solution:
People buying vanilla flavor in 2003 = 375
People buying all three flavor in 2005 = 350+ 250 + 275
= 875
Required percentage = (875-375)/875×100
~ 57%

Q9. What is the ratio of people buying vanilla flavor in 2001, 2004 and 2006 together to the people buying strawberry flavor over all year?
38/69
13/69
31/29
53/23
None of these
Solution:
People buying vanilla flavor ice-creams in 2001, 2004 and 2006 = 400 +250 + 300
= 950
People buying strawberry flavor over all years
=300+350+325+300+275+175
=1725 Required ratio =950/1725
=38/69

Q10. Average of people buying vanilla flavor in 2004 and 2006 together is X and if people buying chocolate flavor in 2007 are 100/11% percent more than x, then find number of people buying chocolate flavor in 2007.
300
400
350
500
250
Solution:
X=550/2
=275
Number of people buying chocolate in 2007 = (100+100/11)% of 275
=1200/(11×100)×275
=300

Directions (11-15): What approximate value should come in place of question mark (?) in the following questions ?

Q11. 36.05% of 350 = ?
105
133
126
145
118
Solution:
? = 36% of 350 = 126

Q12. 8.07% of 449.97 + 5.96% of 1449.97 = 24.98% of ?
576
378
550
625
492
Solution:
8% of 450 + 6% of 1450 = 25% of ?
25% of ? = 36 + 87
25/100×? = 123
? = (123 × 100)/25=492

Q13. 84.04% of 1649.97 + 19.98% of 870.08 = ?
1600
1560
1410
1375
1800
Solution:
? = 84% of 1650 + 20% of 870
? = 1386 + 174 = 1560

Q14. 64.07% of 249.96 + 35.93% of 150.17 = ?
214
180
235
245
340
Solution:
? = 64% of 250 + 36% of 150
? = 160 + 54 ? = 214

Q15. 35.01% of ?= 35.98²-32.02²-62.01
1000
800
600
400
200
Solution:
35/100×? = 36² - 32²-62
35/100×? = 1296-1024-62=210
?= 210×100/35=600

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