Quantitative Aptitude Quiz For IBPS SO Prelims: 27th December 2018

Dear Aspirants,

Quantitative Aptitude Quiz For IBPS SO Prelims: 27th December 2018


Numerical Ability or Quantitative Aptitude Section has given heebie-jeebies to the aspirants when they appear for a banking examination. As the level of every other section is only getting complex and convoluted, there is no doubt that this section, too, makes your blood run cold. The questions asked in this section are calculative and very time-consuming. But once dealt with proper strategy, speed, and accuracy, this section can get you the maximum marks in the examination. Following is the Quantitative Aptitude quiz to help you practice with the best of latest pattern questions.



Directions (1-5): The given Pie chart represents the percentage of failed students in different subjects in Intermediate Annual Exam 2016. 



Note: Here ‘total’ as given in graph denotes the percentage of students who are failed in annual intermediate exam in only these subjects given in the graph.

Q1. If total candidates failed in Intermediate annual exam is only 24% of the total no of candidates appeared for Intermediate half yearly exam, then total no of candidates appeared in Intermediate half yearly exam are approximately how many times the no of candidates failed in Maths section of Annual Exam?
23
15
20
12
18
Solution:

Q2. What is the difference between the no of candidates failed in Hindi & Total all subject and no of candidates failed in Maths Subject?
8640
8600
9000
8000
7775
Solution:
No. of candidate failed in (Hindi & Total all subject) = (22 + 11) ×1440 = 47520
No. of candidate failed in Math subject = 27 × 1440 = 38,880
Difference = 47,520 – 38,880 = 8,640

Q3. Total no of candidates failed in Intermediate annual exam is 75% of the no of candidates appeared for same exam. If the students who got honour in the exam will be one-third of the candidates who passed in Intermediate annual exam, then find the number of students who get honoured:
16600
16000
17000
19000
18000
Solution:

Q4. What is the ratio of no of candidates who failed in English and Hindi together to the no of candidates failed overall in Annual exam?
2 : 3
2 : 1
1 : 2
3 : 2
4 : 5
Solution:

Q5. What is the central angle of the candidates who passed in English and Math ?
85.6
90
80.8
Can’t be determined
None of the above
Solution:
As per given value in graph, Data is not sufficient to calculate the desired value.

Directions (6-10): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer 

Q6. I. 14x² + 11x -15 = 0 
II. 20y² - 31y +12 = 0
if x>y
if x≥y
 if x<y
if x ≤y
if x = y or no relation can be established between x and y.
Solution:

Q7.
if x>y
if x≥y
 if x<y
if x ≤y
if x = y or no relation can be established between x and y.
Solution:

Q8.
if x>y
if x≥y
 if x<y
if x ≤y
if x = y or no relation can be established between x and y.
Solution:

Q9. I. 5x² – 29x + 36 = 0 
II. 10y² – 3y – 27 =0
if x>y
if x≥y
 if x<y
if x ≤y
if x = y or no relation can be established between x and y.
Solution:

Q10. I. 7x² – 54x + 99 = 0 
II. 4y² – 16y + 15 = 0
if x>y
if x≥y
 if x<y
if x ≤y
if x = y or no relation can be established between x and y.
Solution:

Directions (11-15): What should come in place of the question mark (?) in the following number series? 

Q11. 1548, 516, 129, 43, ?
11
10.75
9.5
12
12.25
Solution:
The pattern is ÷3,÷4,÷3,÷4…..

Q12. 949, 189.8, ?, 22.776, 11.388, 6.8328
48.24
53.86
74.26
56.94
64.94
Solution:
Series is ×0.2,×0.3,×0.4,×0.5……

Q13. 121, 144, 190, 259, ?, 466
351
349
374
328
361
Solution:
Pattern is +23×1,+23×2,+23×3,+23×4……

Q14. 14, 43.5, 264, ?, 76188
3168
3176
1587
1590
3174
Solution:
Pattern is ×3+1.5×1,×6+1.5×2,×12+1.5×4,×24+1.5×8

Q15. 41, 164, 2624, ?, 6045696
104244
94644
94464
102444
65600
Solution:
Pattern is ×2², ×4², ×6², ×8²

               






You May also like to Read:


            

Print Friendly and PDF

No comments