# Quantitative Aptitude Quiz For IBPS SO Prelims: 27th December 2018

**Dear Aspirants,**

Numerical Ability or Quantitative Aptitude Section has given heebie-jeebies to the aspirants when they appear for a banking examination. As the level of every other section is only getting complex and convoluted, there is no doubt that this section, too, makes your blood run cold. The questions asked in this section are calculative and very time-consuming. But once dealt with proper strategy, speed, and accuracy, this section can get you the maximum marks in the examination. Following is the Quantitative Aptitude quiz to help you practice with the best of latest pattern questions.

**Directions (1-5): The given Pie chart represents the percentage of failed students in different subjects in Intermediate Annual Exam 2016.**

**Note:**Here ‘total’ as given in graph denotes the percentage of students who are failed in annual intermediate exam in only these subjects given in the graph.

**Q1. If total candidates failed in Intermediate annual exam is only 24% of the total no of candidates appeared for Intermediate half yearly exam, then total no of candidates appeared in Intermediate half yearly exam are approximately how many times the no of candidates failed in Maths section of Annual Exam?**

23

15

20

12

18

**Q2. What is the difference between the no of candidates failed in Hindi & Total all subject and no of candidates failed in Maths Subject?**

8640

8600

9000

8000

7775

Solution:

No. of candidate failed in (Hindi & Total all subject) = (22 + 11) ×1440 = 47520

No. of candidate failed in Math subject = 27 × 1440 = 38,880

Difference = 47,520 – 38,880 = 8,640

No. of candidate failed in Math subject = 27 × 1440 = 38,880

Difference = 47,520 – 38,880 = 8,640

**Q3. Total no of candidates failed in Intermediate annual exam is 75% of the no of candidates appeared for same exam. If the students who got honour in the exam will be one-third of the candidates who passed in Intermediate annual exam, then find the number of students who get honoured:**

16600

16000

17000

19000

18000

**Q4. What is the ratio of no of candidates who failed in English and Hindi together to the no of candidates failed overall in Annual exam?**

2 : 3

2 : 1

1 : 2

3 : 2

4 : 5

**Q5. What is the central angle of the candidates who passed in English and Math ?**

85.6

90

80.8

Can’t be determined

None of the above

Solution:

As per given value in graph, Data is not sufficient to calculate the desired value.

**Directions (6-10): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer**

**Q6. I. 14x² + 11x -15 = 0**

**II. 20y² - 31y +12 = 0**

if x>y

if x≥y

if x ≤y

if x = y or no relation can be established between x and y.

**Q7.**

if x>y

if x≥y

if x ≤y

if x = y or no relation can be established between x and y.

**Q8.**

if x>y

if x≥y

if x ≤y

if x = y or no relation can be established between x and y.

**Q9. I. 5x² – 29x + 36 = 0**

**II. 10y² – 3y – 27 =0**

if x>y

if x≥y

if x ≤y

if x = y or no relation can be established between x and y.

**Q10. I. 7x² – 54x + 99 = 0**

**II. 4y² – 16y + 15 = 0**

if x>y

if x≥y

if x ≤y

if x = y or no relation can be established between x and y.

**Directions (11-15): What should come in place of the question mark (?) in the following number series?**

**Q11. 1548, 516, 129, 43, ?**

11

10.75

9.5

12

12.25

Solution:

The pattern is ÷3,÷4,÷3,÷4…..

**Q12. 949, 189.8, ?, 22.776, 11.388, 6.8328**

48.24

53.86

74.26

56.94

64.94

Solution:

Series is ×0.2,×0.3,×0.4,×0.5……

**Q13. 121, 144, 190, 259, ?, 466**

351

349

374

328

361

Solution:

Pattern is +23×1,+23×2,+23×3,+23×4……

**Q14. 14, 43.5, 264, ?, 76188**

3168

3176

1587

1590

3174

Solution:

Pattern is ×3+1.5×1,×6+1.5×2,×12+1.5×4,×24+1.5×8

**Q15. 41, 164, 2624, ?, 6045696**

104244

94644

94464

102444

65600

Solution:

Pattern is ×2², ×4², ×6², ×8²

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