# Quantitative Aptitude Quiz For IBPS Clerk Mains: 6th January 2019

**Dear Students,**

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**Quantitative Aptitude Quiz For IBPS Clerk Main**

If talked about banking exams, Quant Section is considered to be one of the most difficult sections and so, gives heebie-jeebies to many. The questions asked in this section are calculative and very time-consuming and if you do not practice it well, it can make your blood run cold during the exam. The

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**Directions (1-5): In the following questions two quantities are given for each question. Compare the numeric value of both the quantities and answers accordingly.**

**Q1. ‘A’, ‘B’ and ‘C’ together can complete a work in 48 days if they work alternatively. ‘A’ is 25% more efficient than ‘B’ who is**

**less efficient than ‘C’. Quantity I: Difference between days taken by ‘A’ alone and ‘C’ alone to complete the work. Quantity II: Days in which ‘A’, ‘B’ and ‘C’ together can complete half of the work.**

Quantity I > Quantity II

Quantity I < Quantity II

Quantity I ≥ Quantity II

Quantity I ≤ Quantity II

Quantity I = Quantity II or No relation

**Q2. Neeraj invested Rs. X in two different schemes ‘A’ and ‘B’ equally. Scheme A offers 10% p.a. at S.I and scheme B offers 20% p.a. at C.I. After 2 years he got total Rs.2560 interest from both the schemes. Quantity I: Value of ‘X’ Quantity II: Rs. 7200**

Quantity I ≥ Quantity II

Quantity I = Quantity II or No relation

Quantity I > Quantity II

Quantity I ≤ Quantity II

Quantity I < Quantity II

**Q3. Three partners invested capital in the ratio 2 : 7 : 9. The time period for which each of them invested was in the ratio of the reciprocals of the amount invested.. Quantity I: Profit share of the partner who brought in the highest capital if the profit is Rs. 1080 Quantity II: Profit share of the partner who brought in the lowest capital if the profit is Rs. 1080**

Quantity I > Quantity II

Quantity I ≥ Quantity II

Quantity I < Quantity II

Quantity I = Quantity II or No relation

Quantity I ≤ Quantity II

**Q4. X started from a point A towards point B. After 2 hours. Y started from B towards A. By the time X travelled one-fifth of the total distance, Y had also travelled the same. Y’s speed is thrice of that of X’s speed. Quantity I: Difference in time (in hours) taken by X and Y to reach their respective destinations. Quantity II: 12 hours**

Quantity I = Quantity II or No relation

Quantity I ≤ Quantity II

Quantity I ≥ Quantity II

Quantity I < Quantity II

Quantity I > Quantity II

**Q5. A vessel contains 2.5 litres of water and 10 litres of milk. 20% of the contents of the vessel are removed. To the remaining contents, x litres of water is added to reverse the ratio of water and milk. Then y litres of milk is added again to reverse the ratio of water and milk. Quantity I: Value of ‘y’ Quantity II: Value of ‘x’**

Quantity I = Quantity II or No relation

Quantity I ≤ Quantity II

Quantity I ≥ Quantity II

Quantity I < Quantity II

Quantity I > Quantity II

**Q6. A shopkeeper buys 144 items at 90 paise each. On the way 20 items are broken. He sells the remainder at Rs. 1.20 each. His gain per cent correct to one place of decimal is**

13.8%

14.6%

14.8%

15.8%

None of these

**Q7. The ratio of the number of boys and girls in a school is 2 : 3. If 25% of the boys and 30% of the girls are scholarship holders, the percentage of the school students who are not scholarship holders is**

72%

36%

54%

60%

None of these

**Q8. A boat goes 24 km upstream and 28 km downstream in 6 hours. It goes 30 km upstream and 21 km downstream in 6 hours and 30 minutes. The speed of the boat in still water is**

8 km/hr

9 km/hr

12 km/hr

10 km/hr

None of these

**Q9. A takes three times as long as B and C together to do a job. B takes four times as long as A and C together to do the work. If all the three, working together can complete the job in 24 days, then the number of days, A alone will take to finish the job is**

100

96

95

90

None of these

**Q10. 20 litres of a mixture contains 20% alcohol and the rest water. If 4 litres of water be mixed in it, the percentage of alcohol in the new mixture will be**

**Directions (11-15): In these questions, two equations numbered I and II are given. You have to solve both the equations and give answer:**

**Q11. I. x² – 9x + 18 = 0**

**II. 5y² – 22y + 24 = 0**

if x < y

if x > y

if x ≤ y

if x ≥ y

if relationship between x and y cannot be determined

Solution:

I. x² – 9x + 18 = 0

x² – 6x – 3x + 18 = 0

x (x – 6) –3 (x -6) = 0

(x – 3) (x – 6) = 0

x= 3, 6

II. 5y² – 22y + 24 = 0

5y² – 10y – 12y + 24 = 0

5y (y- 2) –12 (y – 2) = 0

(y – 2) (5y – 12) = 0

y=2, 12/5

∴ x > y

x² – 6x – 3x + 18 = 0

x (x – 6) –3 (x -6) = 0

(x – 3) (x – 6) = 0

x= 3, 6

II. 5y² – 22y + 24 = 0

5y² – 10y – 12y + 24 = 0

5y (y- 2) –12 (y – 2) = 0

(y – 2) (5y – 12) = 0

y=2, 12/5

∴ x > y

**Q12. I. 6x² + 11x + 5 = 0**

**II. 2y² + 5y + 3 = 0**

if x < y

if x > y

if x ≤ y

if x ≥ y

if relationship between x and y cannot be determined

Solution:

I. 6x² + 11x + 5 = 0

6x² + 6x + 5x + 5 = 0

6x (x + 1) + 5 (x + 1) = 0

(x+ 1) (6x +5) = 0

x = -1,-5/6

II. 2y² + 5y + 3 = 0

2y² + 2y + 3y + 3 = 0

2y (y+ 1) + 3 (y+ 1) = 0

(y+ 1) (2y + 3) = 0

y= -1,-3/2

∴x≥y

6x² + 6x + 5x + 5 = 0

6x (x + 1) + 5 (x + 1) = 0

(x+ 1) (6x +5) = 0

x = -1,-5/6

II. 2y² + 5y + 3 = 0

2y² + 2y + 3y + 3 = 0

2y (y+ 1) + 3 (y+ 1) = 0

(y+ 1) (2y + 3) = 0

y= -1,-3/2

∴x≥y

**Q13. I. x² + 10x + 24 = 0**

**II. y² – √625=0**

if x < y

if x > y

if x ≤ y

if x ≥ y

if relationship between x and y cannot be determined

Solution:

I. x² + 10x + 24 = 0

x² +6x + 4x + 24 = 0

x (x + 6) +4 (x+ 6) = 0

(x + 4) (x + 6) = 0

x = –4, –6

II. y² – √625=0

y²=√625

y²=25;

y= ±5

∴ Relationship between x and y cannot be determined

x² +6x + 4x + 24 = 0

x (x + 6) +4 (x+ 6) = 0

(x + 4) (x + 6) = 0

x = –4, –6

II. y² – √625=0

y²=√625

y²=25;

y= ±5

∴ Relationship between x and y cannot be determined

**Q14. I. 10x² + 11x + 1 = 0**

**II. 15y² + 8y + 1 = 0**

if x < y

if x > y

if x ≤ y

if x ≥ y

if relationship between x and y cannot be determined

Solution:

I. 10x² +11x + 1= 0

10x² + 10x+ x+ 1 = 0

10x (x + 1) + 1 (x + 1) = 0

(x + 1) (10x + 1) = 0

x= -1,-1/10

II. 15y² + 8y + 1 = 0

15y² +5y + 3y + 1 = 0

5y (3y + 1) + 1 (3y+ 1) = 0

(3y + 1) (5y + 1) = 0

y=-1/3,-1/5

∴ Relationship between x and y cannot be determined

10x² + 10x+ x+ 1 = 0

10x (x + 1) + 1 (x + 1) = 0

(x + 1) (10x + 1) = 0

x= -1,-1/10

II. 15y² + 8y + 1 = 0

15y² +5y + 3y + 1 = 0

5y (3y + 1) + 1 (3y+ 1) = 0

(3y + 1) (5y + 1) = 0

y=-1/3,-1/5

∴ Relationship between x and y cannot be determined

**Q15. I.15x² – 11x + 2 = 0**

**II. 10y² – 9y + 2 = 0**

if x < y

if x > y

if x ≤ y

if x ≥ y

if relationship between x and y cannot be determined

Solution:

I. 15x² – 11x + 2 = 0

15x² – 5x – 6x + 2 = 0

5x (3x – 1) – 2 (3x – 1) = 0

(3x – 1) (5x – 2) = 0

x=1/3,2/5

II. 10y² – 9y + 2 = 0

10y² – 5y – 4y + 2 = 0

5y (2y – 1) –2 (2y – 1) = 0

(2y – 1) (5y - 2) = 0

y = 1/2,2/5

∴ x ≤ y

15x² – 5x – 6x + 2 = 0

5x (3x – 1) – 2 (3x – 1) = 0

(3x – 1) (5x – 2) = 0

x=1/3,2/5

II. 10y² – 9y + 2 = 0

10y² – 5y – 4y + 2 = 0

5y (2y – 1) –2 (2y – 1) = 0

(2y – 1) (5y - 2) = 0

y = 1/2,2/5

∴ x ≤ y

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