IBPS PO Quantitative Aptitude (Time and Work, Permutation & Combination) Quiz For Prelims: 15th March 2019

Dear Aspirants,


IBPS PO Quantitative Aptitude (Time and Work, Permutation & Combination) Quiz For Prelims: 15th March 2019

Quantitative Aptitude Quiz For IBPS PO/Clerk Prelims

Numerical Ability or Quantitative Aptitude Section has given heebie-jeebies to the aspirants when they appear for a banking examination. As the level of every other section is only getting complex and convoluted, there is no doubt that this section, too, makes your blood run cold. The questions asked in this section are calculative and very time-consuming. But once dealt with proper strategy, speed, and accuracy, this section can get you the maximum marks in the examination. Following is the Quantitative Aptitude quiz to help you practice with the best of latest pattern questions.





Q1. 16 men and 12 women can complete a work in 8 days. If 20 men can complete the same work in 16 days, in how many days 20 women can complete the same price of work?
10 days
8 days
12 days
6 days
14 days
Solution:

Q2. A and B together can do a work in 10 days. C can destroy the same work in 28 days. A and B started the work and work for 12 days simultaneously and C started with them for destroying the work for same 12 days. After that A and C leave and B complete the remaining work in 4 days in how many days A alone can complete the same work.
Solution:

Q3. In how many different ways can the letters of the word ‘VIRTUAL’ be arranged such that all the vowels come together?
720
840
5040
1680
120
Solution:
The word VIRTUAL consists of 7 distinct letters in which vowels are A, I, U
∴ Required number of arrangements = 5! × 3!
= 5 × 4 × 3 × 2 × 1 × 3 × 2 × 1
= 720

Q4.A and B can complete a work in 12 days together, B and C can complete the same work in 15 days together and A and C can complete that work in 20 days together. In how many days A can complete the same work alone?
30 days
40 days
25 days
50 days
45 days
Solution:

Q5. Out of 5 women and 4 men, a committee of three members is to be formed in such a way that at least one member is a woman. In how many different ways can this be done?
80
84
76
96
72
Solution:

Q6. A and B are two pipes which can fill a tank individually in 15 minutes and 25 minutes respectively, however there is a leakage at the bottom of tank which can empty the filled tank in 30 minutes. If the tank is empty initially, how much time will both the taps take to fill the tank (leakage is still there)?
148/11 minutes
150/11 minutes
145/11 minutes
139/11 minutes
None of these
Solution:

Q7. In how many different ways can the letters of the word ‘TOTAL’ be arranged?
120
60
48
72
84
Solution:
Required no.of arrangements = 5!/2! = 60

Q8. In how many ways I can make to seat my 7 friends around a circular table for a tea party such that my best friend always seats in front of me?
120
5040
720
2520
1440
Solution:
Required no. of ways = 6! = 720
Note: Here, we will not multiply by 2! As it is already included in the total no. of ways.

Q9. 2 men can complete a piece of work in 6 days. 2 women can complete the same piece of work in 9 days, whereas 3 children can complete the same piece of work in 8 days. 3 women and 4 children worked together for 1 day. If only men were to finish the remaining work in a day, how many total men would be required?
4
8
6
can’t be determined
None of these
Solution:

Q10. In how many ways the letters of the word ‘PLUMBER’ be arranged such that U, M always come together and P and R always come at end places?
2520
240
120
96
60
Solution:
Required no. of ways = 4! × 2! × 2! = 96

Directions (11-15): In the following questions two equations numbered I and II are given. You have to solve both the equations and– 

Q11. I. 6p² + 5p + 1 = 0 
II. 20q² + 9q = -1
if p > q
if p ≥ q
if p < q
if p ≤ q
if p = q or the relationship cannot be established.
Solution:

Q12. I. 3p² + 17p + 10 = 0 
II. 10q² + 9q + 2 = 0
if p > q
if p ≥ q
if p < q
if p ≤ q
if p = q or the relationship cannot be established.
Solution:

Q13. I. p² + 24 = 10p 
II. 2q² + 18 = 12q
if p > q
if p ≥ q
if p < q
if p ≤ q
if p = q or the relationship cannot be established.
Solution:

Q14. I. 5p + 2q = 96 
II. 3 (7p + 5q) = 489
if p > q
if p ≥ q
if p < q
if p ≤ q
if p = q or the relationship cannot be established.
Solution:

Q15. 

if p > q
if p ≥ q
if p < q
if p ≤ q
if p = q or the relationship cannot be established.
Solution:

               






You May also like to Read:

           




Print Friendly and PDF

No comments