# SBI PO Quantitative Aptitude (Miscellaneous) Quiz For Prelims: 14th April

**Dear Aspirants,**

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**Quantitative Aptitude Quiz For SBI PO/Clerk Prelims**

Numerical Ability or Quantitative Aptitude Section has given heebie-jeebies to the aspirants when they appear for a banking examination. As the level of every other section is only getting complexand convoluted, there is no doubt that this section, too, makes your blood run cold. The questions asked in this section are calculative and very time-consuming. But once dealt with proper strategy, speed, and accuracy, this section can get you the maximum marks in the examination. Following is the Quantitative Aptitude quiz to help you practice with the best of latest pattern questions.

**Directions (1-5): The following table shows the total no. of students studying in five different colleges and ratio of boys and girls in that. Table also shows the percentage of students who are involved in sports also. Study table carefully to answer the following questions.**

**Q1. Find the total no. of students who are involved in sports also from collages P, R and T together.**

40,000

44,000

48,000

52,000

36,000

**Q2. Total no. of boys from collage Q is how much percent more or less than the total no. of girls from the college S?**

20% less

25% more

25% less

20% more

30 % more

**Q3. What is the average no. of students from colleges P, Q and R together who are involved in sports also?**

20,000

24,000

30,000

26,000

18,000

**Q4. What is the difference between total no. of boys and total no. of girls from colleges R and S together?**

40,000

35,000

25,000

30,000

20,000

**Q5. If 20% and 25% students of collages P and T respectively, out of those who are involved in sports also, are sent to a state level game then find the no. of sport students form these colleges who are not sent for the state level games.**

18,500

16,500

14,500

20,500

15,800

**Directions: (6 –10): In the following questions two equations in x and y are given. You have to solve both the equations and give the answer**

**Q6. I. 4x² – 9x + 2 = 0**

**II. 3y² – 7y + 2 = 0**

If x > y

If x < y

If x ≥ y or relationship between x and y cannot be established

If x ≤ y

If x = y

Solution:

I. 4x²–9x + 2 = 0

⇒ 4x²– 8x – x + 2 = 0

⇒ 4x (x – 2)– 1(x–2) = 0

⇒ (x–2) (4x – 1) = 0

⇒ x = 2,1/4

II. 3y² – 7y + 2 = 0

⇒ 3y² – 6y – y + 2 = 0

⇒ 3y (y –2) - 1(y –2) = 0

⇒ y = 2, 1/3

No relation

⇒ 4x²– 8x – x + 2 = 0

⇒ 4x (x – 2)– 1(x–2) = 0

⇒ (x–2) (4x – 1) = 0

⇒ x = 2,1/4

II. 3y² – 7y + 2 = 0

⇒ 3y² – 6y – y + 2 = 0

⇒ 3y (y –2) - 1(y –2) = 0

⇒ y = 2, 1/3

No relation

**Q7. I. 7y² + 19y – 26 = 0**

**II. x² – 36x + 288 = 0**

If x > y

If x < y

If x ≥ y or relationship between x and y cannot be established

If x ≤ y

If x = y

Solution:

I. 7y² + 19y – 26 = 0

⇒ 7y² +26y – 7y – 26 = 0

⇒ y (7y + 26) - 1(7y + 26) = 0

⇒ y = 1, -26/7

II. x² – 36x + 288 = 0

⇒ x²– 12x – 24x + 288 = 0

⇒ x (x–12) –24 (x–12) = 0

⇒ (x – 12) (x –24) = 0

⇒ x = 12, 24

x > y

⇒ 7y² +26y – 7y – 26 = 0

⇒ y (7y + 26) - 1(7y + 26) = 0

⇒ y = 1, -26/7

II. x² – 36x + 288 = 0

⇒ x²– 12x – 24x + 288 = 0

⇒ x (x–12) –24 (x–12) = 0

⇒ (x – 12) (x –24) = 0

⇒ x = 12, 24

x > y

**Q8. I. 6x² + 13x + 5 = 0**

**II. 2y² – 8y – 24 = 0**

If x > y

If x < y

If x ≥ y or relationship between x and y cannot be established

If x ≤ y

If x = y

Solution:

I. 6x² + 13x +5 = 0

⇒ 6x² + 3x + 10x + 5 = 0

⇒ 3x (2x +1) +5 (2x + 1) = 0

⇒ (2x +1) (3x + 5) = 0

⇒ x = -1/2, -5/3

II. 2y² – 8y – 24 = 0

⇒ y² – 4y – 12 = 0

⇒ y² – 6y + 2y – 12 = 0

⇒ y (y–6) +2(y–6) = 0

⇒ (y – 6) (y + 2) = 0

⇒ y = 6, –2

No relation

⇒ 6x² + 3x + 10x + 5 = 0

⇒ 3x (2x +1) +5 (2x + 1) = 0

⇒ (2x +1) (3x + 5) = 0

⇒ x = -1/2, -5/3

II. 2y² – 8y – 24 = 0

⇒ y² – 4y – 12 = 0

⇒ y² – 6y + 2y – 12 = 0

⇒ y (y–6) +2(y–6) = 0

⇒ (y – 6) (y + 2) = 0

⇒ y = 6, –2

No relation

**Q9. I. 22x² – 27x + 8 = 0**

**II. 12y² – 48y + 36 = 0**

If x > y

If x < y

If x ≥ y or relationship between x and y cannot be established

If x ≤ y

If x = y

Solution:

I. 22x² – 27x + 8 = 0

⇒ 22x² – 11x – 16x + 8 = 0

⇒ 11x (2x–1) –8 (2x–1) = 0

⇒ (2x – 1) (11x –8) = 0

⇒ x = 1/2, 8/11

II. 12y² ¬ 48y + 36 = 0

⇒ y² – 4y + 3 = 0

⇒ y² – 3y – y + 3 = 0

⇒ y (y – 3) –1 (y – 3) = 0

⇒ y = 3, 1

y>x

⇒ 22x² – 11x – 16x + 8 = 0

⇒ 11x (2x–1) –8 (2x–1) = 0

⇒ (2x – 1) (11x –8) = 0

⇒ x = 1/2, 8/11

II. 12y² ¬ 48y + 36 = 0

⇒ y² – 4y + 3 = 0

⇒ y² – 3y – y + 3 = 0

⇒ y (y – 3) –1 (y – 3) = 0

⇒ y = 3, 1

y>x

**Q10. I. y² + 42y + 432 = 0**

**II. x² + 38x + 352 = 0**

If x > y

If x < y

If x ≥ y or relationship between x and y cannot be established

If x ≤ y

If x = y

Solution:

I. y² + 42y + 432 = 0

⇒ y² + 18y + 24y + 432 = 0

⇒ y (y + 18) +24 (y +18) = 0

⇒ (y + 18) (y + 24) = 0

⇒ y = –18, –24

II. x² + 38x + 352 = 0

⇒ x² + 16x + 22x + 352 = 0

⇒ x (x + 16) +22 (x +16) = 0

⇒ (x + 16) (x + 22) = 0

⇒ x = –16, –22

No relation

⇒ y² + 18y + 24y + 432 = 0

⇒ y (y + 18) +24 (y +18) = 0

⇒ (y + 18) (y + 24) = 0

⇒ y = –18, –24

II. x² + 38x + 352 = 0

⇒ x² + 16x + 22x + 352 = 0

⇒ x (x + 16) +22 (x +16) = 0

⇒ (x + 16) (x + 22) = 0

⇒ x = –16, –22

No relation

**Q11. A train passes two bridges of lengths 740 m and 270 m in 76 seconds and 38 seconds respectively. The speed of train is (up to two decimal places):**

15.46 m/s

12.36 m/s

21.24 m/s

24.36 m/s

8.36 m/s

**Q12. 14 men complete a work in 24 days. After working for 6 days, 7 men join them. How many more days will all of them take to complete the remaining work?**

10 days

12 days

15 days

9 days

16 days

**Q13. Out of the three given numbers, the first number is thrice the second and four fifth the third. If the average of the three numbers is 279, what is the difference between the first and their third number?**

86

84

76

81

72

**Q14. Out of his total income, Mr. Kapur spends 20% on house rent and 70% of the rest on house hold expenses. If he saves Rs 1,800 what is his total income (in rupees)?**

Rs 7,800

Rs 7,000

Rs 8,000

Rs 7,500

None of these

**Q15. There are 81 litres pure milk in a container. One-third of milk is replaced by water in the container. Again one-third of mixture is extracted and equal amount of water is added. What is the ratio of milk to water in the new mixture?**

1 : 2

1 : 1

2 : 1

4 : 5

3 : 2

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