SBI PO Quantitative Aptitude Quiz: 28th May


SBI PO Quantitative Aptitude Quiz

Here, we are providing free crash course for SBI PO as there is left not enough time to deal in details. The questions asked in the quantitative aptitude section are calculative and very time-consuming. But once dealt with proper strategy, speed, and accuracy, this section can get you the maximum marks in the examination. Following is the Quantitative Aptitude quiz to help you practice with the best of latest pattern questions



Directions (1-5): The following table shows the various expenses (out of his monthly income) in five different months on six different things by Mr. Sharma. Study the table carefully and answer the following questions. 

Note:
In the table some data are in percentage, some in rupees and some are missing.
If there is any requirement of missing data find it first and then proceed.
Mr. Sharma’s monthly salary = Rs 1,20,000


Q1. If total expenses in the month of June was Rs. 73,600 then expenses of his wife’s makeup is what percent of his monthly salary ?
15 ⅓%
13 ⅓%
11 ⅓%
41%
40%
Solution:

Q2. If average expenses on food in all the five months together is Rs. 33,360 then expenses on Food in month of July is approximately what percent more than the expenses on furnitures in the same month ?
150%
160%
180%
210%
200%
Solution:

Q3. If the ratio between expenses on children’s fee in the month of June and expenses on House tax in the month of September be 3 : 4, then expenses on House tax is what percent of total salary in the month of September ?
4%
6%
3%
5%
8%
Solution:

Q4. If total expenses in the month of October was Rs. 1,02,000 then expense on furniture by Mr. Sharma in the month of October is what percent of his monthly salary ?
10%
8%
12%
6%
4%
Solution:

Q5. If total expenses on cloths in all months be 50% of monthly salary then expenses on cloths in August is what percent of expenses on Wife’s make up in the same month ?
45%
48%
60%
50%
52%
Solution:

Directions (6-10): What approximate value will come in place of (?) in the following problems? Q6. 21.01² + 31.9² – 40.01² = ? – 26.9²
485
459
594
694
394
Solution:

Q7. 34.98 % of 400.01 + 44.97 % of 249.98 = 199% of ?
226
126
26
216
136
Solution:

Q8. 11.89 ÷ 2.87 + 124.9 ÷ 4.98 = 9.9% of ?
490
390
190
290
590
Solution:

Q9.
168
192
78
718
178
Solution:

Q10.
76
66
32
36
46
Solution:

Q11. A 5 cm cube is cut into as many 1 cm cubes as possible. What is the ratio of the surface area of the larger cube to that of the sum of the surface areas of the smaller cubes?
1: 6
1: 5
1: 25
1: 125
None of these
Solution:
The volume of the larger cube = 5³ = 125 cm³.
The volume of each of the smaller cubes = 1³ = 1 cm³.
Therefore, one would get 125 smaller cubes.
The surface area of the larger cube = 6a² = 6(5²) = 6 × 25 = 150 cm²
The surface area of each of the smaller cubes = 6 (1²) = 6 cm²
Therefore, surface area of all of the 125, 1 cm³ cubes = 125 × 6 = 750 cm²
Therefore, the required ratio = 150 : 750 = 1 : 5

Q12. Four horses are tethered at 4 corners of a square field of side 70 metres. The length of the rope is half of the side of the field. The area left ungrazed by the horses is:
1050 sq. m.
3850 sq. m.
950 sq. m.
1075 sq. m.
None of these
Solution:
The length of the rope is 35m (70/2).
The area covered by each horse should be equal to the area of sector with radius of 70/2 = 35 m(length of the rope).
Total area covered by the four horses = 4* area of sector of radius 35 metres = Area of circle of radius 35m.
Area left ungrazed by the horses = Area of square field - Area covered by four horses.
= 70² - (22/7) × 35 × 35 = 4900 - 3850 = 1050 sq.m.

Q13. All possible four-digit numbers, with distinct digits are formed, using the digits {1, 3, 4, 5, 6}. How many of them are divisible by 5?
8
12
24
20
28
Solution:

Q14. Ten points are selected on a plane, such that no three of them are collinear. How many different straight lines can be formed by joining these points?
54
45
90
108
64
Solution:

Q15. In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there?
159
194
205
209
169
Solution:

               








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