# LIC AAO Mains Quantitative Aptitude Quiz: 22nd June

Here, we are providing free crash course for LIC AAO Mains as there is left not enough time to deal in details. The questions asked in the quantitative aptitude section are calculative and very time-consuming. But once dealt with proper strategy, speed, and accuracy, this section can get you the maximum marks in the examination. Following is the Quantitative Aptitude quiz to help you practice with the best of latest pattern questions.

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**Q1. The sum of four numbers is 64. If you add 3 to the first number, 3 is subtracted from the second number, the third is multiplied by 3 and the fourth is divided by three, then all the results are equal. What is the difference between the largest and the smallest of the original numbers?**

32

27

21

Cannot be determined

None of these

**Q2. Ms. Pooja Pushpan invests 13% of her monthly salary, i.e. Rs. 8554 in mediclaim Policies. Later she invests 23% of her monthly salary on Child Education Policies. Also, she invests another 8% in her monthly Funds. What is the total monthly amount invested by Ms. Pooja Pushpan?**

Rs. 28952

Rs. 43428

Rs. 347424

Rs. 173712

None of these

**Q3. The batting average of 40 innings of a cricket player is 50 runs. His highest score exceeds his lowest score by 172 runs. If these two innings are excluded the average of the remaining 38 innings is 48. His highest score was:**

172

173

174

176

None of these

Solution:

Let the highest score be x

∴ 40 × 50 = 38 × 48 + x + x – 172

⇒ 2000 = 1824 + 2x - 172

⇒ x = 174 runs.

**Q4. A vessel contains liquid P and Q in the ratio 5 : 3. If 16 L of the mixture are removed and the same quantity of liquid Q is added, the ratio become 3 : 5. What quantity does the vessel hold?**

35 L

45 L

40 L

50 L

None of these

**Q5. Several litres of acid were drawn off a 54 L vessel full of acid and an equal amount of water added. Again, the same volume of the mixture 2 was drawn off and replaced by water. As a result the vessel contained 24 L of pure acid. How much of the acid was drawn off initially?**

12 L

16 L

18 L

24 L

None of these

**Directions (6 – 10): Study the following pie chart and bar graph carefully to answer the following questions. The pie chart shows the percentage distribution of aspirants who have applied for various exams. The bar graph shows the vacancy in these exams.**

**Q6. Average of all aspirants who have applied for various given exam is approximately how many times the total no. of vacancies?**

39

32

35

38

41

**Q7. If Railways reduces two-fifth of its vacancies, then total vacancies will be reduced by how much percent?**

13.56%

14.56%

18.2%

17%

None of these

**Q8. What will be the difference between average number of aspirants per post in SSC and the average number of aspirant per post in IBPS?**

56

41

45

52

48

**Q9. If no. of vacancies of IBPS increased by 10% and for one final selection in all the given vacancies three aspirants would be rejected during interviews. Find no. of aspirant qualified for Interview for IBPS is approximately how many times the no of aspirant qualified for PSUs and KVS interviews both?**

3

3.5

5

4.5

2

Solution:

As per given statement, clearly For one post, 4 will selected for Interviews

No. of posts/ vacancies in IBPS now = 9500 + 950 = 10450

∴ No. of aspirant qualifies for IBPS interview = 10450 × 4 = 41800

No. of aspirants qualifies for PSUs and KVS interviews = (2800 + 700) × 4 = 14000

Desired value = 41800/14000 ≈ 3 times

**Q10. Out of all vacancies allocated, 15% of the selected aspirants didn’t join. Hence 8% of the IBPS and 10% of Railways vacancies remain unfilled. What will be the approximate value of ratio between total vacancies remain unfilled for IBPS and Railways together to Rest of the organizations vacancy which remain unfilled.?**

5 : 7

4 : 5

5 : 9

9 : 11

11 :13

**Directions (11-15): What will come in place of question mark (?) in the following simplification problems?**

**Q12. 36% of 545 + 32% of 215 – 47% of 1300 = ?**

643

346

-411

-346

436

1170

1730

1510

1710

1150

Solution:

? = 35 ÷ 7 × 342 = 1710

9110

9120

8510

9620

8120

Solution:

48 ÷ 3 × 570 = ?

Or, ? = 9120

3

4

5

2

1

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