SBI PO Mains Quantitative Aptitude Quiz: 13th July

SBI-PO-MAINS-Quantitative-Aptitude-Quiz: 13th July
SBI PO Quantitative Aptitude Quiz

Here, we are providing SBI PO Mains Study plan as there is left not enough time to deal in details. The questions asked in the quantitative aptitude section are calculative and very time-consuming. But once dealt with proper strategy, speed, and accuracy, this section can get you the maximum marks in the examination. Following is the Quantitative Aptitude quiz to help you practice with the best of latest pattern questions.

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Directions (1-5): Study the following information carefully and answer the questions given beside.
In an amusement park, the following types of traffic signals are there to drive a toy car.
Red Light (R) = Stop
Yellow light (Y) = Wait
Red and Yellow lights (RY) = Turn left
Red and Green lights (RG) = Turn right
Yellow and Green lights (YG) = Go at 20 km per hour
Red, Yellow, and Green lights (RYG) = Go at 10 km per hour
Green light (G) = Go at 5 km per hour
All children driving the cars inside the amusement park should compulsorily follow the traffic signals and can’t go outside the park to drive the car. A girl Ankita who is facing north, drive the car at the speed of 30 km per hour inside the park and encounters the signals in the following manners. (She can go to the next signal only after passing the previous signal)
Starting Point = S
After half an hour, 1st signal – RY and YG
After 15 minutes, 2nd signal – RYG
After 30 minutes, 3rd signal – RG and RYG
After 15 minutes, 4th signal – RG and YG
After an hour, 5th signal – RY and G
After 2 hours, 6th signal – R

Q1. What is the total distance that Ankita travelled from the starting point till the 6th signal?
59.5 km
57.5 km
55.5 km
48.5 km
67.5 km
Solution:

15 KM + 5 KM + 5 KM + 2.5 KM + 20 KM + 10 KM = 57.5 km

Q2. What is the average speed at which Ankita travelled from the starting point till the 6th signal?
Solution:


Q3. Suppose, in park there is no signals then approximately how much less time Ankita would have taken to reach the final position? (End position is fixed.)
3 hours 32 minutes
2 hours 32 minutes
4 hours 32 minutes
3 hours 42 minutes
3 hours 24 minutes
Solution:

The total time taken by the Ankita = 4.5 hrs
And the shortest distance would have been √(27.5²+ 10²) = √(756.25 + 100 ) = approximately 29.26 km = approximately 29 km @ 30 km per hour = approximately 58 min
The required difference = 4.5 hours – 58 minutes = 3 hours 32 minutes

Q4. If at the starting point, Ankita was facing toward south then what would be the final position from the starting point?
22.5 km towards south and 15 km towards west
10 km towards south and 27.5 km towards west
27.5 km towards south and 10 km towards west
Can’t be determined
27.5 km towards south and 20 km towards west
Solution:

27.5 km towards south and 10 km towards west

Q5. After the starting point, if the first signal was RG and RYG instead of RY and YG then what would be the final position of Ankita from the starting point?
12.5 km towards west and 12.5 km towards north
7.5 km towards west and 12.5 km towards north
2.5 km towards west and 12.5 km towards north
10.5 km towards west and 12.5 km towards north
12.5 km towards west and 2.5 km towards north
Solution:

From the diagram, it is clear that the end point is 12.5 km towards west and 2.5 km towards north.

Q6. Quantity I: Value of P. Manoj lend Rs. P for three years on S.I. at the rate of 15% per annum and Rajesh lend Rs. (P + 8000) for two years on C.I. at the rate of 8% per annum. Suresh borrowed sum equal to what Manoj and Rajesh lend, for two years on C.I. at the rate of 20% per annum. Suresh paid interest Rs. 5352 more.
Quantity II: Investment of B. A, B and C entered into a partnership with some investment for one year. After one-year A got 2/5 profit and B and C got equal part of remaining profit. If total profit after one year is 15% instead of 10% of total investment made by them, then A got 900 Rs. more.
Quantity I > Quantity II
Quantity I < Quantity II
Quantity I ≥ Quantity II
Quantity I ≤ Quantity II
Quantity I = Quantity II or No relation
Solution:

Q7. Quantity I: No. of times A and B meet together in 5 minutes. Two persons A and B are standing diametrically opposite on a circular track with a radius of 3.5 units. They start running in an opposite direction on the circular track and their speeds are 4 units/minute and 7 units/minute respectively. On meeting each other they take rest for half a minute and then start running with twice the original speed.
Quantity II: No. of days required by 32 women and 64 boys together to complete the same job. A man works twice as fast as a woman. A woman works twice as fast as a child. 16 men can complete a job in 12 days.
Quantity I > Quantity II
Quantity I < Quantity II
Quantity I ≥ Quantity II
Quantity I ≤ Quantity II
Quantity I = Quantity II or No relation
Solution:

Q8. A boat cover 60 km upstream and 60 km downstream in 22.5 hr with its usual speed. If boat double its speed, then new upstream speed is 150% more than the usual upstream speed. Find the time taken by boat to cover 80 km in downstream with usual speed.
12 hr
20 hr
5 hr
16 hr
10 hr
Solution:

Directions (9-10): Ramesh and Suresh decided to meet at a common point at the same time in the river. Ramesh had to travel 42 km upstream in the river and Suresh had to travelless distance downstream than that of Ramesh to meet at a common point. They both sets off in their respective boats at the same time and speed of Ramesh’s boat is 20 km/hr more than the speed of Suresh boat. It is given that Suresh covers 280 km upstream in 35 hours. 

Q9. Find the speed of stream of river?

6 km/hr
8 km/hr
5 km/hr
10 km/hr
4 km/hr
Solution:

Q10. After meeting, if they decided to return to their original places but Ramesh travelled for 19 km and Suresh travelled for 16 km, then what is the sum of time taken by both in covering these distances?
150 min
120 min
180 min
90 min
60 min
Solution:

Directions (11-15): Find out the wrong number in the following number series.

Q11. 14, 29, 41, 63, 65, 131, 133

63
131
29
41
133
Solution:

Q12. 2478, 819, 257, 84, 24, 5
257
24
5
819
84
Solution:

Q13. 4, 6, 12, 30, 90 , 315, 1240
315
90
6
12
1240
Solution:

Q14. 289, 266, 285, 270, 281, 275, 277
266
275
277
281
285
Solution:

Q15. 7, 13, 49, 295, 2305, 23041
7
13
49
295
2305
Solution:

               




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