Directions (Q. 1–5): In each question two equations are provided on the basis of these you have to find the relation between x and y. Give answer:
1) If x > y
2) If x >= y
3) If x < y
4) If x <= y
5) If x = y or no relationship between x and y exists
1.
I. 42x² + 59x + 20 = 0
II. 20y² – y – 1 = 0
2.
I. 3x² – 7x + 2 = 0
II. 2y² + 9y + 9 = 0
3.
I. x² + 11x + 30 = 0
II. y² + 13y + 42 = 0
4.
I. 6x² + 17x + 7 = 0
II. y² +10y + 21 = 0
5.
I. 20x² – 53x + 35 = 0
II. 3y² – 20y + 32 = 0
Directions (Q. 6 –10): In the following number series only one number is wrong. Find out the wrong number.
6. 118, 137, 176, 238, 314, 413
1) 238
2) 137
3) 118
4) 413
5) 176
7. 2, 3, 12, 39, 172, 885
1) 39
2) 3
3) 885
4) 12
5) 172
8. 1434, 1484, 717, 239, 59.75, 11.95
1) 1484
2) 11.95
3) 717
4) 239
5) 1434
9. 219, 340, 484, 653, 849, 1067, 1330
1) 340
2) 1330
3) 1067
4) 653
5) 849
10. 29, 43, 71, 113, 169, 248
1) 169
2) 113
3) 29
4) 43
5) 248
Answers:
1. 3
I. 42x² + 24x + 35x + 20 = 0
(6x + 5) (7x + 4) = 0
x = -5/6, -4/7
II. 20y² – 5y + 4y –1 = 0
(5y + 1) (4y –1) = 0
y = -1/5, 1/4
y > x
2. 1;
I. 3x² –x – 6x + 2 = 0
(x – 2) (3x – 1) = 0
x = 2, 1/3
II. 2y² + 3y + 6y + 9 = 0
(y + 3) (2y + 3) = 0
y = – 3, -3/2
x > y
3. 2;
I. x² + 6x + 5x + 30 = 0
(x + 5) (x + 6) = 0
x = –5, –6
II. y² + 7y + 6y + 42 =0
(y + 6) (y + 7) = 0
y = – 6, –7
x >= y
4. 1
I. 6x² + 14x + 3x + 7 = 0
(3x + 7) (2x + 1) = 0
x = -7/3, -1/2
II. y² + 3y +7y + 21 = 0
(y + 7) ( y + 3) = 0
y = –7, –3
x > y
5. 3
I. 20x² – 28x – 25x + 35 = 0
(5x –7) (4x – 5) = 0
x = 7/5, 5/4
II. 3y² – 8y – 12y + 32 = 0
(3y – 8) (y – 4) = 0
y = 8/3, 4
y > x
6. 1
7. 4
8. 1
9. 3
10. 5
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