IBPS Clerk Pre 12/10/2018




Q1. A trader sold 90 quintals wheat at 8% profit and 50 quintals wheat at 10% profit. Had he sold all the wheat at 9% profit he would have earned Rs 120 more. Find per quintal cost price of wheat.
Rs 250
Rs 300
Rs 350
Rs 400
None of these
Solution:

Q2. Two fair dices are thrown. Find the probability of getting a sum of two numbers divisible by 2 and 3.
5/6
1/6
3/4
5/7
7/9
Solution:

Q3. The compound interest on a certain sum for 2 years is Rs 60.60 and simple interest is Rs. 60. Find the rate of interest per annum and the sum.
2%, Rs 1600
2%, Rs 1400
3%, Rs 1500
2%, Rs 1500
4%, Rs.1500
Solution:

Q4. The average age of 8 members of a group is 40 years. The age of 1 member is 55 yrs. After his retirement a new member comes in his place, whose age is 39. The average age of group will decrease by?
2
0
3
5
4.5
Solution:

Q5. An amount of money is to be distributed among A, B and C in the ratio 3 : 1 : 5. The difference between B’s and C’s share is Rs. 3600. What is the total of A’s and B’s share?
Rs. 5400
Rs. 3600
Rs. 2700
Rs. 1800
Rs. 2100
Solution:
Let the common multiple be ‘x’
Now,
5x – x = 3600
∴ 4x = 3600 ⇒ x= 900
A’s share = 3x = 3 × 900 = 2700
B’s share = x = 900
A’s share + B’s share
= 2700 + 900
= 3600

Directions (6-10): What should come in place of the question mark (?) in the following number series?

Q6. 2, 16, 112, 672, 3360, ?
3430
3340
40320
43240
13440
Solution:

Q7. 4, 9, 19, ?, 79, 159, 319
59
39
49
29
40
Solution:

Q8. 87, 89, 95, 107, ?, 157
127
122
139
140
148
Solution:

Q9. 474, 459, 429, 369, 249, ?
4
0
9
11
3
Solution:

Q10. 7, 10, 16, 28, 52, ?, 196
100
90
160
150
180
Solution:

Directions (11-15): Find the approximate value of the following questions. 

Q11. 39% of 405+61% of 610-183.67= ?
450
300
230
280
344
Solution:

Q12. 5682 ÷ 63 × 36 = ? ×17.998
180
190
210
240
140
Solution:

Q13. 4.99 × 12.865 + 599 = ?
650
655
665
670
675
Solution:
? ≃ 5 × 13 + 600
≃ 665

Q14. 250.01 - 429.99 + 549.99 = ?
370
420
340
410
320
Solution:
? ≃ 250 – 430 + 550
= 370

Q15. 
1.5
1.2
2.1
2.4
1.7
Solution:


               

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