Dear Aspirants,

### Reasoning Quiz for Canara PO 2018

Reasoning Ability is an onerous section. With the increasing complexity of questions, it becomes hard for one to give it the cold shoulder. The only way to make the grade in this particular section in the forthcoming banking exams like Canara PO Mains is to practice continuously with all your heart and soul. And, to let you practice with the best of the latest pattern questions, here is the Adda247 Reasoning Quiz based on the exact same pattern of questions that are being asked in the exams.

Directions (1-5): In these questions three statements followed by five conclusions. You have to take the three given statements to be true even if they seem to be at variance from commonly known facts. Read all the conclusions and then decide which of the given conclusions logically does not follow from the given statements disregarding commonly known facts.

Q1. Statement:
All hurdles are posts.
Some posts are works
Conclusion:
(a) All works being hurdles is a possibility
(b) At least some works are post.
(d) All tasks being hurdle is a possibility.
(e) Some post being hurdles is a possibility.

Q2. Statement:
All hurdles are jobs.
Some jobs are works
Conclusion:
(d) All works being hurdles is a possibility.
(e) All jobs being hurdles is a possibility.

Q3. Statements:
Some difficulties are solutions
No solution is a trick
All rules are tricks
Conclusion:
(a) No rule is a solution
(b) Some difficulties are definitely not tricks
(c) All difficulties being tricks is a possibility
(d) Some rules being difficulties is a possibility
(e) All tricks being rule is a possibility.

Q4. Statements:
All M.L.A are deans.
Conclusion:
(a) No principal is M.L.A
(b) All heads being M.L.A is a possibility.
(c) Some M.L.A being head is a possibility.
(e) All deans being M.L.A is a possibility.

Q5. Statements
No queue is a graph
Some queues are rows
All graphs are cubes.
Conclusion:
(a) No row is graph is a possibility
(b) All rows are cube is a possibility
(c) All cubes being queue is a possibility
(d) Some cube is queue is a possibility
(e) Some graphs are cubes.

Directions (6-10): Study the following information carefully and answer the question given below:
Eight persons M, N, O, P, Q, R, S and T all of them face north direction but not necessarily in same order. All of them stay in different floors viz 4th, 7th, 13th, 18th, 21th, 27th, 37st, 45th in a same building but not necessarily in same order. Highest value is considered as a top floor.
* P sits one of the extreme ends of the row and lives on 37th floor. O sits 4th from the right end and live on an even numbered floor. There are two persons sit between O and the person who lives on an even number floor.
* There are two persons sit between R and M and none of them lives on even number floor. R is not an immediate neighbor of P and O. T doesn’t sit at any of the extreme ends of the row.
* R lives on topmost floor. Only one person sits between M and T who lives on the floor which is 6th lowest prime number. The person who lives on 27th floor sits second to the left of T but he is not an immediate neighbor of P.
* S is not an immediate neighbor of R and sits an odd numbered floor. N and S is not an immediate neighbours. N lives an even numbered floor. Q lives one of the prime number floors. Neither 4th nor 18th numbered floor person lives any extreme end of the row. The person who lives on 13th floor is not the neighbor of the person who lives on 18th floor.

Q6. Who sits second to the right of M?
(a) P
(b) R
(c) Q
(d) N
(e) None of these.

Q7. Who lives on 7th floor?
(a) Q
(b) N
(c) S
(d) T
(e) O

Q8. Who lives on 18th floor?
(a) M
(b) R
(c) O
(d) N
(e) Q

Q9. How many of the given eight persons live between R and S?
(a) None
(b) One
(c) Two
(d) Three
(e) More than Three

Q10. Who sits second to the left of S?
(a) The one who stays on 4th floor
(b) N
(c) M
(d) L
(e) No one

Directions (11-15): Study the following information carefully to answer the given questions.
A word and number arrangement machine when given an input line of words and numbers,           rearranges them following a particular rule in each step. The following is an illustration of input and rearrangement. (All the numbers are two-digit numbers.)
Input: 43 ducks 10 sing 92 rights 61 revolt 57 love
Step I: 10 43 ducks sing 92 rights 61 revolt 57 love
Step II: 10 rights 43 ducks sing 92 61 revolt 57 love
Step III: 10 rights 43 revolt ducks sing 92 61 57 love
Step IV: 10 rights 43 revolt 57 ducks sing 92 61 love
Step V: 10 rights 43 revolt 57 ducks 61 sing 92  love
Step V is the last step, find out in each of the rules followed in the above steps, find out in each of the following questions the appropriate step for the given input.
Input: 20 apples 12 arrange 76 best bear 64 might 56

Q11. How many steps will be required to complete the rearrangement?
(a) Eight
(b) Five
(c) Six
(d) Nine
(e) None of these

Q12. Which step number is the following output?
12 arrange 20 might 56 best 64 apples 76

(a) Step V
(b) Step III
(c) Step VI
(d) Step IV
(e) There will be no such step

Q13. Which  of the following represents the position of ‘apples’ in Step III?
(a) Fourth from the left
(b) Sixth from the left
(c) Fourth from the right
(d) Second from the right
(e) None of these

Q14. Which word/number would be at the seventh position from the right in Step VI?
(a) Apples
(b) 20
(c) 76
(d) might
(e) None of these

Q15. Which of the following will be the penultimate step?
(a) 12 20 apples arrange 76 best bear 64 might 56
(b) 12 arrange 20 might 56 apples 64 best 76 bear
(c) 12 arrange 20 apples 56 might 64 76 best bear
(d) 12 arrange 20 might 56 best 64 apples 76 bear
(e) None of these

Solutions

Directions (6-10):
Step-1:-P sits one of the extreme ends of the row and lives on 37th floor. O sits 4th from the right end and live on an even numbered floor. There are two persons sit between O and the person who lives on an even number floor. There should be two possible cases.

Step-2:- There are two persons sit between R and M and none of them lives on even number floor. R is not an immediate neighbor of P and O. R lives on topmost floor. Only one person sits between M and T who lives on the floor which is 6th lowest prime number which we consider according to numerical series. The person who lives on 27th floor sits second to the left of T but he is not an immediate neighbor of P. T doesn’t sit at any of the extreme ends of the row. There are more possible conditions for M and R but from the given conditions these possibilities will be cancelled out.

Step-3:- S is not an immediate neighbor of R and sits an odd numbered floor. N and S is not an immediate neighbours. N lives an even numbered floor. Q lives one of the prime number floors. Neither 4th nor 18th numbered floor person lives any extreme end of the row. The person who lives on 13th floor is not the neighbor of the person who lives on 18th floor. From these statements Case-2 has been eliminated.

S6. Ans.(e)

S7. Ans.(a)

S8. Ans.(d)

S9. Ans.(e)

S10. Ans.(a)

Directions (11-15):

Students let us understand the Logic behind this Question and lets understand how to solve it. As a first step lets first understand the logic behind the Output. If you will see the final output you will observe the following:
(i) The machine rearranges the numbers and words in alternative steps and starting from a number.
(ii) The numbers are arranged in ascending order from left to right.
(iii) The words are arranged in descending order in terms of the number of alphabets in a given word from left to right. If two words contain the same number of alphabets then they are arranged in increasing order of the number of vowels in the word.

Now lets take the arrangement given in the Question

Input: 20 apples 12 arrange 76 best bear 64 might 56
Step I: 12 20 apples arrange 76 best bear 64 might 56
Step II: 12 arrange 20 apples 76 best bear 64 might 56
Step III: 12 arrange 20 apples 56 76 best bear 64 might
Step IV: 12 arrange 20 apples 56 might 76 best bear 64
Step V: 12 arrange 20 apples 56 might 64 76 best bear
Step VI: 12 arrange 20 apples 56 might 64 best 76 bear
Step VI is the final step of the rearrangement.

S11.Ans.(c)

S12.Ans.(e)

S13.Ans.(a)

S14.Ans.(a)

S15.Ans.(c)