# IBPS Clerk Pre Quant 20/10/2018

**Q1. A dealer allowed a discount of 25% on the marked price of Rs 12000 on an article and incurred a loss of 10%. What discount should he allow on the marked price so that he gains Rs 440 on the article?**

11%

13%

19%

15%

17%

**Q2. Rana is twice as good a workman as Sunder and Finishes a piece of work in 3 hours. In how many hours they together could finish that piece of work?**

**Q3. A sum of Rs 2200 is invested at two different rates of interest. The difference between the simple interests got after 4 years is Rs 202.40 at these two rates, what is the difference between the rates of interest?**

3.3%

2.3%

3.5%

2.5%

4.3%

**Q4. While selling a watch, a shopkeeper gives a discount of 15%. If he gives a discount of 20%, he earns Rs 51 less as profit. What is the original marked price of the watch?**

Rs 920

Rs 985

Rs 1125

Rs 1020

Rs 1220

**Q5. In how many different ways can the letters of the word ‘THERAPY’ be arranged so that the vowels never come together?**

720

1440

5040

3600

4800

Solution:

Required arrangements

= 7! – 6! × 2!

= 5 × 6!

= 3600

= 7! – 6! × 2!

= 5 × 6!

= 3600

**Directions (6-10): Study the following table carefully to answer the questions that follows. Table shows number of students studying in different colleges over the years.**

**Q6. Number of students in college C in year 2007 is approximately what % of the total number of students in that college from all the years together?**

17%

20%

15%

28%

32%

**Q7. What is the difference between the average number of students from all the colleges together in year 2006 and 2008?**

12

10

14

16

20

**Q8. What is the average number of students in all the colleges together in the year 2007?**

2628

2640

2602

2614

2460

**Q9. What is the respective ratio of total number of students in college D in the years 2008, and 2010 together to the total number of students in college A from the same years?**

465 : 343

508 : 495

510 : 496

504 : 485

405 : 584

Solution:

Total students in 2008 and 2010 together in college D = 2540 + 2540 = 5080

Total students in 2008 and 2010 in college A = 2550 + 2400 = 4950

So, the ratio = 5080: 4950 = 508: 495

Total students in 2008 and 2010 in college A = 2550 + 2400 = 4950

So, the ratio = 5080: 4950 = 508: 495

**Q10. If average age of students in college B in 2006 is 18 years and average age of students in college C is 16 years in the same year, then find the difference between sum of ages of all students in these two colleges in year 2006 (in numerical value).**

6540

6250

6520

6450

6640

Solution:

Required difference = 2540 × 18 ̶ 2450 × 16

= 6520

= 6520

**Directions (11-15): In each of the following questions two equations are given. You have to solve the equations and Give answer —**

**Q11. I. 7x² + 13x + 6 = 0**

**II. 4y² + 7y – 11 = 0**

if x < y

if x ≤ y

relationship between x and y cannot be determined

if x ≥ y

if x > y

**Q12. I. x² + 46x + 520 = 0**

**II. 3y² – 17y + 24 = 0**

if x < y

if x ≤ y

relationship between x and y cannot be determined

if x ≥ y

if x > y

**Q13. I. 5y² – 13y – 18 = 0**

**II. 11x² + 23x + 12 = 0**

if x < y

if x ≤ y

relationship between x and y cannot be determined

if x ≥ y

if x > y

Solution:

b

**Q14. I. x⁴ – 13x² + 36 = 0**

**II. y² + 4y – 45 = 0**

if x < y

if x ≤ y

relationship between x and y cannot be determined

if x ≥ y

if x > y

**Q15. I. 6y² – 14y + 8 = 0**

**II. 4x² – 15x + 14 = 0**

if x < y

if x ≤ y

relationship between x and y cannot be determined

if x ≥ y

if x > y

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