Q1. A dealer allowed a discount of 25% on the marked price of Rs 12000 on an article and incurred a loss of 10%. What discount should he allow on the marked price so that he gains Rs 440 on the article?
11%
13%
19%
15%
17%
Solution:

Q2. Rana is twice as good a workman as Sunder and Finishes a piece of work in 3 hours. In how many hours they together could finish that piece of work?

Solution:

Q3. A sum of Rs 2200 is invested at two different rates of interest. The difference between the simple interests got after 4 years is Rs 202.40 at these two rates, what is the difference between the rates of interest?
3.3%
2.3%
3.5%
2.5%
4.3%
Solution:

Q4. While selling a watch, a shopkeeper gives a discount of 15%. If he gives a discount of 20%, he earns Rs 51 less as profit. What is the original marked price of the watch?
Rs 920
Rs 985
Rs 1125
Rs 1020
Rs 1220
Solution:

Q5. In how many different ways can the letters of the word ‘THERAPY’ be arranged so that the vowels never come together?
720
1440
5040
3600
4800
Solution:
Required arrangements
= 7! – 6! × 2!
= 5 × 6!
= 3600

Directions (6-10): Study the following table carefully to answer the questions that follows. Table shows number of students studying in different colleges over the years.

Q6. Number of students in college C in year 2007 is approximately what % of the total number of students in that college from all the years together?
17%
20%
15%
28%
32%
Solution:

Q7. What is the difference between the average number of students from all the colleges together in year 2006 and 2008?
12
10
14
16
20
Solution:

Q8. What is the average number of students in all the colleges together in the year 2007?
2628
2640
2602
2614
2460
Solution:

Q9. What is the respective ratio of total number of students in college D in the years 2008, and 2010 together to the total number of students in college A from the same years?
465 : 343
508 : 495
510 : 496
504 : 485
405 : 584
Solution:
Total students in 2008 and 2010 together in college D = 2540 + 2540 = 5080
Total students in 2008 and 2010 in college A = 2550 + 2400 = 4950
So, the ratio = 5080: 4950 = 508: 495

Q10. If average age of students in college B in 2006 is 18 years and average age of students in college C is 16 years in the same year, then find the difference between sum of ages of all students in these two colleges in year 2006 (in numerical value).
6540
6250
6520
6450
6640
Solution:
Required difference = 2540 × 18 ̶ 2450 × 16
= 6520

Directions (11-15): In each of the following questions two equations are given. You have to solve the equations and Give answer —

Q11. I. 7x² + 13x + 6 = 0
II. 4y² + 7y – 11 = 0
if x < y
if x ≤ y
relationship between x and y cannot be determined
if x ≥ y
if x > y
Solution:

Q12. I. x² + 46x + 520 = 0
II. 3y² – 17y + 24 = 0
if x < y
if x ≤ y
relationship between x and y cannot be determined
if x ≥ y
if x > y
Solution:

Q13. I. 5y² – 13y – 18 = 0
II. 11x² + 23x + 12 = 0
if x < y
if x ≤ y
relationship between x and y cannot be determined
if x ≥ y
if x > y
Solution:
b

Q14. I. x⁴ – 13x² + 36 = 0
II. y² + 4y – 45 = 0
if x < y
if x ≤ y
relationship between x and y cannot be determined
if x ≥ y
if x > y
Solution:

Q15. I. 6y² – 14y + 8 = 0
II. 4x² – 15x + 14 = 0
if x < y
if x ≤ y
relationship between x and y cannot be determined
if x ≥ y
if x > y
Solution: