Dear Aspirants,

Reasoning Questions for SBI PO Prelims 2018 (Week-06)

Reasoning Ability is an onerous section. With the increasing complexity of questions, it becomes hard for one to give it a cold shoulder. The only way to make the grade in this particular section in the forthcoming SBI PO Prelims and other banking exams is to practice continuously with all your heart and soul. And, to let you practice with the best of latest pattern questions, here is the Adda247 Reasoning Quiz with the exact same pattern of questions that are being asked in the exams.

Following the study plan for SBI PO Preliminary Examination 2018, the sixth week includes practice questions on Puzzles & Seating Arrangement, Input-output, and Inequalities. To ensure proper preparation of the section we advise you to go through all the questions sincerely and try to attempt each one of them. Afterward, match your solutions and the approach with the one that would be provided later. Practice more and more questions on the same section to enhance your grip over the topics. Following is the Reasoning Ability quiz to help you practice with the best of latest pattern questions.

There are ten people sitting in two rows such that in row 2 M, N, O, P, Q are sitting and facing in north direction and in row 1 D, E, F, G, H are sitting and facing in south direction and they are of different ages 15, 20, 23, 30, 33, 35, 38, 45 ,49, 50 but not in the same order. No two persons are sitting together according to alphabetical order, except G and F.

There are two people sitting between M and Q and either M or Q is sitting at one of the extreme ends. G is 20 years old and sits third to the left of H. Neither H nor F sits opposite to M and Q, who is not the oldest. The age of P is a multiple of 11. G sits opposite to N whose age  is  a  multiple of 7. Two persons sits between the one who is   the youngest and the one who sits opposite to the one whose age is 35. Three person sit between the one whose age is 49  and the one  who  is  the  youngest. O’s age is twice the age of H. The age of the person who is facing the person who is sitting 2nd to the left of Q is a prime number . The age of M is equal to the sum of ages of H and O. Only one person is sitting between H and F.

Q1. What is the age of F?
(a) 23 years
(b) 30 years
(c) 45years
(d) 15 years
(e) None of these

Q2. Who among the following is the oldest?
(a) H
(b) O
(c) E
(d) D
(e) None of these

Q3. Who among the following sits to  the  immediate left of E?
(a) P
(b) O
(c) no   one
(d) H
(e) None of these

Q4. Which of the following combination is true regarding the given arrangement?
(a) E- 50
(b) M-  45
(c) F- 33
(d) D- 49
(e) none of these

Q5. Who among the following is 33  year old ?
(a) H
(b) G
(c) P
(d) E
(e) None of these

Solutions (1-5):

(i). From the given condition, there are two people sitting between M and Q and either M or Q is sitting at one of the extreme ends. Neither H nor F sits opposite to M and Q, who is not the oldest. G is 20 years old and sits third to the left of H. G sits opposite to N whose age is a multiple of 7. The age of the person who is facing the person who is sitting 2nd to the left of Q is a prime number, So, from this statement Q doesn’t sits at the extreme left and second left position. we get two possible arrangement:
(ii). Now according to statement, No two persons are sitting together according to alphabetical order, except G and F, from this case 2 will get eliminated since there is no other place for P and O. O’s age is twice the age of H i.e. H is 15 year old and O is 30 years old. The age of M is equal to the sum of ages of H and O it means M is 45 years old. Three persons sit between the one whose age is 49 and the one who is the youngest as we know H is 15 years old and the youngest so from this E is 49 years old. Two persons sits between the one who is the youngest and the one who sits opposite to the one whose age is 35, so N is 35 years old.
(iii). From the rest conditions, The age of P is a multiple of 11, so P is 33 year old. Q, who is not the oldest means Q is not 50 years old, so Q is 38 and D is 50 years old. Hence, we will get the final solution.
S1. Ans.(a)
Sol.

S2. Ans.(d)
Sol.

S3. Ans.(c)
Sol.

S4. Ans.(b)
Sol.

S5. Ans.(c)
Sol.

Directions (6-10): In the following questions, the symbols @, #, %, * and \$ are used with the following meaning as illustrated below:

‘P @ Q’ means ‘P is not smaller than Q’.
‘P # Q’ means ‘P is not greater than Q’.
‘P % Q’ means ‘P is neither greater than nor equal to Q’.
‘P * Q’ means ‘P is neither smaller than nor greater than Q’.
‘P \$ Q’ means ‘P is neither smaller than nor equal to Q’.

Now in each of the following questions assuming the given statements to be true, find which of the three conclusions I, II and III given below them is/are definitely true and give your answer accordingly.

Q6. Statements: M % O# R # S \$ T * N
Conclusions:
I. N * R
II. N \$ R
III. S \$ M
(a) All follow
(b) Only either I or II follows
(c) Only III follows
(d) Only either I or III and II follows
(e) None of these

Q7. Statements: J #N *O @M \$ T \$ K
Conclusions:
I. J % T
II. K % N
III. N @ J
(a) None follows
(b) Only I and II follow
(c) Only I and III follow
(d) Only II and III follow
(e) All follow

Q8. Statements: B * D \$ E @ H * G % F
Conclusions:
I. B \$ F
II. D # F
III. D \$ F
(a) None follows
(b) Only  II follows
(c) Only either  II or III follow
(d) Only III follows
(e) All follow

Q9. Statements: T \$ U % K # L *  R @ M
Conclusions:
I. M # L
II. R \$ U
III. R @ K
(a) All follow
(b) Only either I or III follows
(c) Only either I or II follows
(d) Only either II or III follows
(e) None of these

Q10. Statements: V @ M *A \$ P * R # N
Conclusions:
I. R # A
II. V @ R
III. R \$ M
(a) Only I follows
(b) Only II follows
(c) Only III follows
(d) None follows
(e) All follow

Directions (11-15): Study the following information and answer the questions.

Input: left 33 burn 32 21 part 36 zibe bold 11 mint 17

Step I : 36 left 33 burn 32 21 part zibe 11 mint 17 bold
Step II : 33 36 left 32 21 part zibe 11 mint 17 bold burn
Step III : 32 33 36 21 part zibe 11 mint 17 bold burn left
Step IV :  21 32 33 36  part zibe 11 17 bold burn left mint
Step V : 17 21 32 33 36 zibe 11 bold burn left mint part
Step VI : 11 17 21 32 33 36 bold burn left mint part zibe

And Step VI is the last step of the above arrangement as the intended arrangement is obtained. As per the rules followed in the given steps find out the appropriate steps for the given input.

Input: 48 19 glow sick 58 rice 16 cat brick 31

Q11. How many steps will be required to complete the given rearrangement?
(a)Five
(b)Six
(c)Seven
(d)Four
(e)None of these

Q12. Which of the following is the sixth element from the left in step V?
(a) 58
(b) brick
(c) cat
(d) glow
(e) None of these

Q13. Which of the following is Step II of the given input?
(a) 48 19 glow sick 58 rice 16 cat brick 31
(b) 31 48 58 19  sick rice 16 brick cat glow
(c) 48 58 19 glow  sick rice 16 31 brick cat
(d) 19 31 48 58 sick 16 brick cat glow rice
(e)None of these

Q14. Which element is third to the right of ‘16’ in step III?
(a) 31
(b) 48
(c) cat
(d) glow
(e) None of these

Q15. Which element is fourth to the left of ‘rice’ in step V?
(a) cat
(b) brick
(c) glow
(d) 48
(e) 58

Solutions (11-15):

Sol. Students let us understand the Logic behind this Question and let’s understand how to solve it. When we see the each step, then we can find that

The machine rearranges one word and one number in each step simultaneously, words are arranged from right end and numbers are arranged from left end.

(i) In this, words are arranged according to alphabet series from right. In step 1, the smallest word according to alphabetical series goes to the right end and in step 2 the second smallest word goes to the right end. The word which arranged in 1st step will shift one place left in second step and so on until the final step.

(ii) Numbers are arranged in increasing order, In step 1 the largest number goes to the left end and in step 2 the second largest number goes to the left end. The number which arranged in 1st shift will shift one place right in second step and so on until the final step.

Input: 48 19 glow sick 58 rice 16 cat brick 31

Step I: 58 48 19 glow  sick rice 16 cat 31 brick
Step II: 48 58 19 glow  sick rice 16 31 brick cat
Step III: 31 48 58 19  sick rice 16 brick cat glow
Step IV: 19 31 48 58 sick 16 brick cat glow rice
Step V: 16 19 31 48 58 brick cat glow rice sick

S11. Ans.(a)
Sol.

S12. Ans.(b)
Sol.

S13. Ans.(c)
Sol.

S14. Ans.(d)
Sol.

S15. Ans.(e)
Sol.

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