# Numerical Ability for SBI Clerk Prelims Exam 2018: 20th March 2018

**Dear Students,**

**Numerical Ability for SBI Clerk Prelims 2018**

**Numerical Ability Section**has given

**heebie-jeebies**to the aspirants when they appear for a banking examination. As the level of every other section is only getting

**complex and convoluted,**there is no doubt that this section, too, makes your blood run cold. The questions asked in this section are calculative and very time-consuming. But once dealt with proper strategy, speed, and accuracy, this section can get you the maximum marks in the examination. Following is the

**Numerical Ability quiz**to help you practice with the best of latest pattern questions.

**Q1. Ranveer goes to a place on bicycle at speed of 22 kmph and comes back at a speed of 20 kmph. If the time taken by him in second case is 36 min. more than that of first case, what is the total distance travelled by him (in km)?**

(a)128

(b)136

(c)123

(d)132

(e)134

**Q2. The average of sixty observations was calculated as 30. It was found later, that 45 and 46 of the observation were misread as 54 and 64 respectively. What is the correct average?**

(a)26.7

(b)34.25

(c)29.55

(d)32.55

(e)28.87

**Q3. A man swimming in a stream which flows 2.5 kmph finds that in a given time he can swim thrice as far with the sream as he can against it. How many distance he will cover in 4 hours against the current?**

(a)10 km

(b)14 km

(c)8 km

(d)9 km

(e)12 km

**Q4. Two barrels contain a mixture of petrol and disel. The content of petrol is 40% in the first barrel and 70% in the second barrel. In what ratio must the mixtures from the first and the second barrels be taken to form a mixture containing 55% disel?**

(a)1 : 5

(b)5 : 1

(c)3 : 2

(d)5 : 3

(e)5 : 6

**Q5. The difference in the probability of selecting 1 blue Ball and 2 Blue balls is 8/49. If total balls are 50, find the number of blue balls.**

(a) 10

(b) 15

(c) 20

(d) 8

(e) 12

**Solutions (1-5):**

**Directions (6-10): Simplify the following questions.**

**Q6. 3333 + 333 + 33 + 3.33 + 0.30 + 0.033=?**

(a) 3702.663

(b) 3936.848

(c) 3396.884

(d) 3720.663

(e) 3672.063

**Q8. 3% of 500/18 of 2/5 ? = 300**

(a) 800

(b) 900

(c) 1200

(d) 1500

(e) 1800

**Q9. 174 + 568 + 974 – 810 =?**

(a) 902

(b) 904

(c) 905

(d) 904

(e) 906

**Q10. 10 × 30 ÷ 45 × 9 + 6**

(a) 66

(b) 76

(c) 86

(d) 56

(e) 46

**Solutions (6-10):**

**Directions (11-15) Study the following graph carefully & answer accordingly.**

**The following graph shows the percentage of number of girls born in three different states of India for the years 2005-2010**

**Q11. If the total no. of girls born in Keral were 70,000 in 2007, then find the total number of girls born in Rajsthan in the same year 2007.**

(a) 85,000

(b) 80,000

(c) 84,000

(d) 1,30,000

(e) 1,02,000

**Q12. The average value of percentage of girls born in Rajsthan throughout the six years together is approximately how many times the average value of percentage of girls born in Keral over all the years together?**

(a) 3

(b) 1.5

(c) 2.5

(d) 2

(e) 1.16

**Q13. From 2008 to 2009, there was increment of 20% in total no. of girls born in all three states. If no. of girls born in Bihar in 2009 was 60,000 then find the total no. of girls born in Rajsthan in 2008.**

(a) 90,000

(b)1,00,000

(c) 95,000

(d) 85,000

(e) 1,05,000

**Q14. If number of girls born in Rajsthan in 2006 was 80,000, then find the average number of girls born in Bihar and Keral together in 2006.**

(a) 1,21,000

(b) 1,15,000

(c) 1,25,000

(d) 1,20,000

(e) 1,00,000

**Q15. If in 2008, there were 30,000 girls born in Bihar then find the ratio of no. of girls born in Keral and Rajsthan in that year.**

(a) 2 : 3

(b) 9 : 5

(c) 5 : 9

(d) 6 : 5

(e) 3 : 2