Dear Students,

Numerical Ability for SBI Clerk Prelims 2018

Numerical Ability Section has given heebie-jeebies to the aspirants when they appear for a banking examination. As the level of every other section is only getting complex and convoluted, there is no doubt that this section, too, makes your blood run cold. The questions asked in this section are calculative and very time-consuming. But once dealt with proper strategy, speed and accuracy, this section can get you the maximum marks in the examination. Following is the Numerical Ability quiz to help you practice with the best of latest pattern questions.

Directions (Q1-5): In these questions, two equations numbered I and II are given. You have to solve both the equations and give answer:
(a) if x < y
(b) if x > y
(c) if x ≤ y
(d) if x ≥ y
(e) if x = y or relationship between x and y cannot be determined

Q1. I. x² – 9x + 18 = 0
II. 5y² – 22y + 24 = 0

S1. Ans.(b)
Sol.
I. x² – 9x + 18 = 0
x² – 6x – 3x + 18 = 0
x(x – 6) –3 (x -6) = 0
(x – 3) (x – 6)= 0
x= 3, 6
II. 5y² – 22y + 24 = 0
5y² – 10y – 12y + 24 = 0
5y(y- 2) –12 (y – 2) = 0
(y – 2) (5y – 12) = 0
y=2,12/5

∴ x > y

Q2. I. 6x² + 11x + 5 = 0
II. 2y² + 5y + 3 = 0

S2. Ans.(d)
Sol.
I. 6x² + 11x + 5 = 0
6x² + 6x + 5x + 5 = 0
6x (x + 1) + 5 (x + 1) = 0
(x+ 1) (6x +5)= 0
x=-1,-5/6
II. 2y² + 5y + 3 = 0
2y² + 2y + 3y + 3 = 0
2y(y+ 1) + 3 (y+ 1) = 0
(y+ 1) (2y + 3) = 0
y= -1,-3/2

∴x≥y

Q3. I. x² + 10x + 24 = 0
II. y² – √625=0

S3. Ans.(e)
Sol.
I. x² + 10x + 24 = 0
x² +6x + 4x + 24 = 0
x(x + 6) +4 (x+ 6)= 0
(x + 4) (x + 6) = 0
x = –4, –6
II. y² – √625=0
y²=√625
y^2=25;y= ±5

∴ Relationship between x and y cannot be determined

Q4. I. 10x² + 11x + 1 = 0
II. 15y² + 8y + 1 = 0

S4. Ans.(e)
Sol.
I. 10x² +11x + 1= 0
10x² + 10x+ x+ 1 = 0
10x (x + 1) + 1 (x + 1) = 0
(x  + 1) (10x + 1)= 0
x= -1,-1/10
II. 15y² + 8y + 1 = 0
15y² +5y + 3y + 1 = 0
5y (3y + 1)+ 1 (3y+ 1) = 0
(3y + 1) (5y + 1)= 0
y=-1/3,-1/5

∴ Relationship between x and y cannot be determined

Q5. I.15x² – 11x + 2 = 0
II. 10y² – 9y + 2 = 0

S5. Ans.(c)
Sol.
I. 15x² – 11x + 2 = 0
15x² – 5x – 6x + 2 = 0
5x(3x – 1) – 2 (3x – 1)= 0
(3x – 1) (5x – 2)= 0
x=1/3,2/5
II. 10y² – 9y + 2 = 0
10y² – 5y – 4y + 2 = 0
5y(2y – 1) –2 (2y – 1) = 0
(2y – 1) (5y - 2)=0
y=1/2,2/5

∴ x ≤ y

Directions (Q.6-10): In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer
(a) if x < y
(b) if x > y
(c) if x ≤ y
(d) if x ≥ y
(e) if x = y or relationship between x and y cannot be determined

Q6. I. √x-√6/√x=0
II. y^3-6^(3/2)=0

Q7. I. 3x-2y=10
II. 5x-6y=6

Q8. I. x^2+x-12=0
II. y^2-5y+6=0

Q9. I. x^2+9x+18=0
II. y^2-13y+40=0

Q10. I. √(x+6)=√121-√36
II. y^2+112=473

Directions (Q11-15) : In each of the these questions, two equation (I) and (II) are given. You have to solve both the equations and give answer
(a) if x < y
(b) if x > y
(c) if x ≤ y
(d) if x ≥ y
(e) if x = y or no relationship can be established between x and y.