# Quantitative Aptitude Quiz for SBI PO/CLERK Mains: 15th July 2018

**Dear Students,**

Numerical Ability or Quantitative Aptitude Section is getting complex and convoluted every year. The questions asked in this section are calculative and very time-consuming. One needs to fight tooth and nail to get a desirable score in this section. Once dealt with proper strategy, speed, and accuracy, this section can get you the maximum marks in the examination. Following is the Quantitative Aptitude quiz to help you practice with the best of latest pattern questions for SBI PO and SBI Clerk Mains Exam. Not only this, these quizzes will also prove propitious for the upcoming Bank of Baroda Exam. Now, pull up your socks, it’s time for Blood, sweat and tears.

**This quiz is according to the SBI PO/Clerk Study Mains Preparation Study Plan and with the help of this 25 Days Plan you’ll cover all important topics for Data Interpretation and Analysis section of Mains.****Q1. In a set of prime and composite numbers, the composite numbers are twice the number of prime numbers and the average of all the numbers of the set is 9. If the number of prime numbers and composite numbers are exchanged then the average of the set of numbers is increased by 2 and during the exchange of the numbers the average of the prime numbers and composite numbers individually remained constant, then find the ratio of the average of composite numbers to the average of prime numbers (initially).**(a) 7 : 13

(b) 13 : 7

(c) 9 : 11

(d) 13 : 15

(e) Can’t be determined

**Q2. Abhishek sellsfruit juice mixture using apple juice and watermelon juice. Abhishek prepares this mixture by drawing out a jug of apple juice from a 10 litre container filled with apple juice, and replacing it with watermelon juice. If Abhishek draws out another jug of the resultant mixture and replaces it with watermelon juice, the container will have equal volumes of apple juice and watermelon juice. The volume of the jug, in litres, is**(a) 2

(b) > 2 and ≤ 2.5

(c) 2.5

(d) > 2.5 and < 3

(e) > 4 and ≤ 5

**Q3. Ages of A, B, and C are in geometric progression while ages of A, Q and R is in arithmetic progression. If ratio between common difference of arithmetic progression formed by second group (A, Q, R) and common ratio of geometric progression formed by first group (A, B and C) is 2: 1 and total sum of ages of first group (A, B, C) is 182 and total sum of second group (A, Q, R) is 60 then which of the following options given below will be the ages of A, B, C respectively.**

(a) 126, 42, 14

(b) 42, 14, 126

(c) 14, 42, 126

(d) 36, 60, 86

(e) Can’t be determined

**Q4. A circle with radius 2 unit is placed against a right angle. Another smaller circle is also placed as shown in the adjoining figure. What is the radius of the smaller circle.**

(a) (3-2√2) unit

(b) (4-2√(2 )) unit

(c) (7-4√2) unit

(d) (6-4√2) unit

(e) (5-3√2) unit

**Q5. In an examination, there are 500 students out of which 150 students passed the first paper and 350 passed the second paper. 50 students passed both the papers. Find the probability that if a student selected at random has failed in both the papers.**

(a) 1/5

(b) 1/10

(c) 3/10

(d) 3/5

(e) 2/5

**Solutions (1-5)**

**S1. Ans.(a)**

**Sol.**

Let average of prime numbers = P

Average of composite numbers = C

Let no. of prime numbers = x

∴ no. of composite numbers = 2x

According to first condition,

⇒P+2C=27 …(i)

According to second condition,

(2Px+Cx)/3x=11⇒2P+C=33 …(ii)

Solving eqn. (i) and (ii), we get

**S2. Ans.(d)**

**Sol.**

Let volume of Jug = v

Volume of apple juice after first replacement = (10 – v)

Volume of apple juice after 2nd replacement

Total volume of watermelon juice

**S3. Ans.(c)**

**Sol.**

Let ages of A, B, C are a, ar and ar² respectively.

(∵ A, B, C → G.P.)

Ages of A, Q, R are a, a+ d, a +2d

(∵ A, Q, R → A.P.)

Where d= common difference

r = common ratio

According first condition

According to second condition

From these equations, we can find a new equation

(20 – 2r) (r² + r + 1) = 182 (∵ d = 2r & a = 20 –d)

⇒ (10– r) (r²+ r+ 1) = 91

⇒ r³ – 9r² – 9r + 81 = 0

⇒ r² (r – 9) – 9 (r – 9) = 0

⇒ (r – 9) (r² – 9) = 0

⇒ r = 9, 3, –3

a = 20 – 2 × 9 or 20 – 2 × 3

= 2 or 14

∴ Ages of A, B. C → 2, 18, 162, or 14, 42, 126

From options the correct ans is 14, 42 and 126 yrs

**S4. Ans.(d)**

**Sol.**

R = 2 unit

Let radius of smaller circle = r unit

∴ Let OC = x

∴x = 2√2

Part of hypotenuse OC which is not included in any circle

= 2√2 –(2+2r)

= 2√(2 )–2 –2r

And, also this is equal to (r√2 –r)

∴r√2–r=2√2 –2 –2r

⇒r(√2+1)=2(√2–1)

⇒r = 2(√2–1)/(√2+1)×(√2–1)/(√2–1)

= 2(2+1–2√2)/(2–1)

r=2(3–2√2)

r=(6–4√2)

**S5. Ans.(b)**

**Sol.**

Total no. of students who have passed at least 1 paper in the examination = 150 + 350 – 50

= 450

∴ No. of students who failed in both subjects = 500 – 450 = 50

∴ Required probability = 50/500 = 1/10

**Directions (6-10): Each question below is followed by two statements A and B. You have to determine whether the data given in the statement is sufficient for answering the question. You should use the data and your knowledge of Mathematics to choose the best possible answer.**

**Give answer (a)**if the statement A alone is sufficient to answer the question, but the statement B alone is not sufficient.

**Give answer (b)**if the statement B alone is sufficient to answer the question, but the statement A alone is not sufficient.

**Give answer (c)**if both statements A and B together are needed to answer the question.

**Give answer (d)**if either the statements A alone or statement B alone is sufficient to answer the question

**Give answer (e)**if you cannot get the answer from the statements A and B together, but need even more data.

**Q6. Triangle ABC has angle BAC equal to 90°. What is the measure of the angle ABC?**

A. The angle ACB is 35°.

B. The angle CBA is 55°.

**Q7. X, Y and Z are three consecutive even numbers (not necessarily in this order). What is the sum of these numbers?**

A. The difference between X and Z is 4.

B. One-third of Y is 14.

**Q8. What is the salary of P, in a group of P, Q, R, S, T and U, if average salary of group is Rs. 35,000?**

A. Total of the salary of Q and S together is Rs. 54000.

B. Total of the salary of T and U together is Rs. 58000.

**Q9. What is the rate of interest p.a. on an amount of Rs. 6,000 deposited in a Bank?**

A. The simple interest for four years is Rs. 3600.

B. The difference between the simple interest and compound interest is Rs. 894.0375.

**Q10. What is the number?**

A. 20% of that number is one fifth of that number.

B. 5/6th of that number is less than that number by 15.

From statement A

∠ABC = 180 – (∠BAC + ∠ACB)

= 180 – (90+ 35) = 55°

From statement B, ∠ABC = 55°

So, nos. are 40, 42, 44

So, both statements together are required to answer the question

P + Q + R+ S +T +U = 6 × 35,000 = 210,000

A. Q +S = 54,000

B. T + U = 58,000

P + R = 210,000 – (54,000 + 58,000)

= 210,000 – 112,000

=98,000

We cannot find salary of P from given data

Principle = 6000

A. S.I. =3600

T = 4 years

Rate =(3600×100)/(6000×4)=15%

B. CI – SI =894.0375 (Year is not given)

So, we can find rate from statement A, but statement B is not sufficient.

So, statement A is insufficient whereas statement B alone is sufficient to answer the question.

**Solutions (6-10)**

**S6. Ans.(d)****Sol.**From statement A

∠ABC = 180 – (∠BAC + ∠ACB)

= 180 – (90+ 35) = 55°

From statement B, ∠ABC = 55°

**S7. Ans.(c)****Sol.**So, nos. are 40, 42, 44

So, both statements together are required to answer the question

**S8. Ans.(e)****Sol.**P + Q + R+ S +T +U = 6 × 35,000 = 210,000

A. Q +S = 54,000

B. T + U = 58,000

P + R = 210,000 – (54,000 + 58,000)

= 210,000 – 112,000

=98,000

We cannot find salary of P from given data

**S9. Ans.(a)****Sol.**Principle = 6000

A. S.I. =3600

T = 4 years

Rate =(3600×100)/(6000×4)=15%

B. CI – SI =894.0375 (Year is not given)

So, we can find rate from statement A, but statement B is not sufficient.

**S10. Ans.(b)****Sol.**So, statement A is insufficient whereas statement B alone is sufficient to answer the question.

**Directions (11-15): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer**

(a) if x > y

(b) if x y

(c) if x < y

(d) if x y

(e) if x = y or no relation can be established between ‘x’ and ‘y’.

**Q11.**I. 2x2 + 13x - 7 = 0

II. 2y2- 5y + 3 = 0

**Q12.**I. 2x2-15x + 28 = 0

II. 4y2- 16y + 15 = 0

**Q13.**I. x2 + 8x + 16 = 0

II. y2 = 16

**Q14.**I. x2- 2x - 24 = 0

II. y2 + 8y = 0

**Q15.**I. x2 + 4x = 0

**S14. Ans.(e)**

**Sol.**

**S15. Ans.(a)**

**Sol.**

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