Dear Aspirants,

Reasoning Quiz for IBPS PO Prelims: 9th September 2018

Reasoning Questions for IBPS PO 2018

Reasoning Ability is an onerous section. With the increasing complexity of questions, it becomes hard for one to give it the cold shoulder. The only way to make the grade in this particular section in the forthcoming banking exams like IBPS PO is to practice continuously with all your heart and soul. And, to let you practice with the best of the latest pattern questions, here is the Adda247 Reasoning Quiz based on the exact same pattern of questions that are being asked in the exams.




Directions (1-3): Study the given information carefully and answer the given questions. 

Six mobile phones i.e. – M, N, O, P, Q and Rare kept in container of different size. Phone M is kept in that container which is only less in size than container in which phone P is kept. Only three phone containers are less in size than the container in which phone O is kept. Container in which phone R is kept is less in size than container in which phone Q is kept. Phone R is not kept in the least size container. 

Q1. Which among the following Phone is kept in least size container?
N
M
Q
O
None of these
Solution:
Size of phone containers in which different phones are kept:
P’s box >M’s box >O’s box >Q’s box >R’s box >N’s box

Q2. If size of container in which phone Q is kept is 26 cm2, then which of the following may be the size of container in which phone M is kept?
19 cm2
22 cm2
28 cm2
17 cm2
12 cm2
Solution:
Size of phone containers in which different phones are kept:
P’s box >M’s box >O’s box >Q’s box >R’s box >N’s box


Q3. How many containers are less in size than container in which phone Q is kept?
One
Two
Three
Four
More than four
Solution:
Size of phone containers in which different phones are kept:
P’s box >M’s box >O’s box >Q’s box >R’s box >N’s box


Q4. Raman’s rank is 20th from the top and 25th from the bottom among all the students in the class, who passed an examination. From the class of Raman, ten students could not participated in the exam and six students failed in that exam. Find the number of boys and number of girls in the class, if boys and girls are in the ratio of 3:2.
34 boys, 26 girls
36 boys, 24 girls
17 boys, 10 girls
Can’t be determined
None of these
Solution:
No of students who passed an exam= 20+25-1= 44
 Total no of students in a class= 44+10+6= 60
Boys and girls ratio is given 3:2
Let boys= 3x and girls=2x 3x+2x= 60,
hence x=12 Boys= 36, girls= 24

Q5. There are 60 students in a class and the ratio of Girls and Boys is 2:1. Sumit is a boy and his rank is 14th from the top in an examination, if there are 10 girls are ahead of Sumit then how many boys after Sumit in an examination?
15
14
16
18
None of these
Solution:
Girls and Boys ratio= 2:1
2x+x=60
x= 40,
So girls= 40 and boys =20
Number of students behind Sumit= 60-14=46
Number of girls behind Sumit=40-10=30
Number of boys behind Sumit= 46-30=16



Directions (6-10): Study the following information carefully and answer the questions given below.
There are seven persons, A, B, C, D, E, F and G and they are faculty of different subjects viz. Hindi, English, Maths, Science, and Art but not necessarily in the same order. They play different games viz. Polo, Chess, Badminton, Cricket, Football, Tennis, and Kho-Kho but not necessarily in the same order. Only Maths and Science are the subjects which have two faculties and remaining subjects have only one faculty.

The following information is known about them. D is not the faculty of Hindi. A is a faculty of English. B plays either Chess or Tennis. The ones who are the faculties of Science do not play Badminton. D and F are same subject’s faculty. D plays Polo. G plays Football and Neither B nor F is faculty of Maths subject. The person who plays Kho-Kho is a faculty of Maths subject. F doesn’t play Chess. E is Art’s faculty and plays cricket.

Q6. Which of the following subject’s faculty plays Badminton game?
Hindi
Maths
English
Arts
None of these
Solution:
From the conditions, A is a faculty of English. E is Art’s faculty and plays cricket. D plays Polo. D and F are same subject’s faculty. B plays either Chess or Tennis so two possible cases will be there which are shown below. G plays Football and Neither B nor F is faculty of Maths subject, if F is not the faculty of Maths it means D is also not the faculty of Maths. D is not the faculty of Hindi it is clear that F is also not the faculty of Hindi so there is only one possibility that D and F are the faculties of Science subject. The person who plays Kho-Kho is a faculty of Maths subject, only C is left so C will be the faculty of Maths.
The ones who are the faculties of Science do not play Badminton so it is clear that A will play Badminton. F doesn’t play Chess from this condition case-2 will be cancelled out because in Case-2 F will play Chess, there is no possibility other than this. From the rest conditions, neither B nor F is faculty of Maths subject so B will be the faculty of Hindi and it will be fixed that G is faculty of Maths because it is given that Maths subject has two faculties. Finally we get the solution.


Q7. Which one of the following faculty plays Tennis?
B
F
D
A
None of these
Solution:
From the conditions, A is a faculty of English. E is Art’s faculty and plays cricket. D plays Polo. D and F are same subject’s faculty. B plays either Chess or Tennis so two possible cases will be there which are shown below. G plays Football and Neither B nor F is faculty of Maths subject, if F is not the faculty of Maths it means D is also not the faculty of Maths. D is not the faculty of Hindi it is clear that F is also not the faculty of Hindi so there is only one possibility that D and F are the faculties of Science subject. The person who plays Kho-Kho is a faculty of Maths subject, only C is left so C will be the faculty of Maths.
The ones who are the faculties of Science do not play Badminton so it is clear that A will play Badminton. F doesn’t play Chess from this condition case-2 will be cancelled out because in Case-2 F will play Chess, there is no possibility other than this. From the rest conditions, neither B nor F is faculty of Maths subject so B will be the faculty of Hindi and it will be fixed that G is faculty of Maths because it is given that Maths subject has two faculties. Finally we get the solution.


Q8. Who are the faculties of Maths subject?
DG
CA
GB
GC
None of these
Solution:
From the conditions, A is a faculty of English. E is Art’s faculty and plays cricket. D plays Polo. D and F are same subject’s faculty. B plays either Chess or Tennis so two possible cases will be there which are shown below. G plays Football and Neither B nor F is faculty of Maths subject, if F is not the faculty of Maths it means D is also not the faculty of Maths. D is not the faculty of Hindi it is clear that F is also not the faculty of Hindi so there is only one possibility that D and F are the faculties of Science subject. The person who plays Kho-Kho is a faculty of Maths subject, only C is left so C will be the faculty of Maths.
The ones who are the faculties of Science do not play Badminton so it is clear that A will play Badminton. F doesn’t play Chess from this condition case-2 will be cancelled out because in Case-2 F will play Chess, there is no possibility other than this. From the rest conditions, neither B nor F is faculty of Maths subject so B will be the faculty of Hindi and it will be fixed that G is faculty of Maths because it is given that Maths subject has two faculties. Finally we get the solution.


Q9. Which of the following statements is true?
A plays cricket
C is faculty of Hindi
E plays Polo
B is faculty of Hindi
None of these
Solution:
From the conditions, A is a faculty of English. E is Art’s faculty and plays cricket. D plays Polo. D and F are same subject’s faculty. B plays either Chess or Tennis so two possible cases will be there which are shown below. G plays Football and Neither B nor F is faculty of Maths subject, if F is not the faculty of Maths it means D is also not the faculty of Maths. D is not the faculty of Hindi it is clear that F is also not the faculty of Hindi so there is only one possibility that D and F are the faculties of Science subject. The person who plays Kho-Kho is a faculty of Maths subject, only C is left so C will be the faculty of Maths.
The ones who are the faculties of Science do not play Badminton so it is clear that A will play Badminton. F doesn’t play Chess from this condition case-2 will be cancelled out because in Case-2 F will play Chess, there is no possibility other than this. From the rest conditions, neither B nor F is faculty of Maths subject so B will be the faculty of Hindi and it will be fixed that G is faculty of Maths because it is given that Maths subject has two faculties. Finally we get the solution.


Q10. Which of the following faculty plays Chess game?
E
A
D
F
B
Solution:
From the conditions, A is a faculty of English. E is Art’s faculty and plays cricket. D plays Polo. D and F are same subject’s faculty. B plays either Chess or Tennis so two possible cases will be there which are shown below. G plays Football and Neither B nor F is faculty of Maths subject, if F is not the faculty of Maths it means D is also not the faculty of Maths. D is not the faculty of Hindi it is clear that F is also not the faculty of Hindi so there is only one possibility that D and F are the faculties of Science subject. The person who plays Kho-Kho is a faculty of Maths subject, only C is left so C will be the faculty of Maths.
The ones who are the faculties of Science do not play Badminton so it is clear that A will play Badminton. F doesn’t play Chess from this condition case-2 will be cancelled out because in Case-2 F will play Chess, there is no possibility other than this. From the rest conditions, neither B nor F is faculty of Maths subject so B will be the faculty of Hindi and it will be fixed that G is faculty of Maths because it is given that Maths subject has two faculties. Finally we get the solution.


Directions (11-15): Study the following information carefully to answer the given questions. 

A word and number arrangement machine when given an input line of words and numbers rearranges them following a particular rule in each step. The following is an illustration of input and rearrangement.

Input: Lone fine 38 40 apple 62 grow 61 pineapple snooze 50 44 
Step I: Snooze 3 lone fine 40 apple 62 grow 61 pineapple 50 44
Step II: Snooze 3 lone 20 fine apple 62 grow 61 pineapple 50 44
Step III: Snooze 3 lone 20 pineapple 24 fine apple 62 grow 61 50
Step IV: Snooze 3 lone 20 pineapple 24 grow 35 fine apple 62 61
Step V: Snooze 3 lone 20 pineapple 24 grow 35 fine 47 apple 62
Step VI: Snooze 3 lone 20 pineapple 24 grow 35 fine 47 apple 56

Step VI is the last step, find out in each of the rules followed in the above steps, find out in each of the following questions the appropriate step for the given input. 

Input: Faster 36 what 48 honey loot 53 2 fast beast 60 61 

Q11. Which of the following will be the penultimate step of the above input?
Step VI
Step V
Step IV
Step III
None of these
Solution:
Students let us understand the Logic behind this Question and lets understand how to solve it. As a first step lets first understand the logic behind the Output. If you will see the final output you will observe the following:
i) The machine rearranges one word and one number in each step.
ii) The word with the highest value of sum of its vowels is arranged at the leftmost end. For example snooze(O=15+15+5=35). If two words have the same value of the sum of its vowels then they are arranged in alphabetical order.
iii) The number are arranged alternatively in each step in increasing order and the numerical value of the sum of the vowels in the word arranged is subtracted from that number.
For example loot=30 – 2 = 28 Now lets take the arrangement given in the Question

Input: Faster 36 what 48 honey loot 53 2 fast beast 60 61 
Step I: loot 28 faster 36 what 48 honey 53 fast beast 60 61
Step II: loot 28 honey 16 faster what 48 53 fast beast 60 61
Step III: loot 28 honey 16 beast 42 faster what 53 fast 60 61
Step IV: loot 28 honey 16 beast 42 faster 47 what fast 60 61
Step V: loot 28 honey 16 beast 42 faster 47 fast 59 what 61
Step VI: loot 28 honey 16 beast 42 faster 47 fast 59 what 60

Q12. What will be the position of ‘60’ in the last but one step?
Seventh from the left
Second from the right
Sixth from the left
Fifth from the left
None of these
Solution:
Students let us understand the Logic behind this Question and lets understand how to solve it. As a first step lets first understand the logic behind the Output. If you will see the final output you will observe the following:
i) The machine rearranges one word and one number in each step.
ii) The word with the highest value of sum of its vowels is arranged at the leftmost end. For example snooze(O=15+15+5=35). If two words have the same value of the sum of its vowels then they are arranged in alphabetical order.
iii) The number are arranged alternatively in each step in increasing order and the numerical value of the sum of the vowels in the word arranged is subtracted from that number.
For example loot=30 – 2 = 28 Now lets take the arrangement given in the Question

Input: Faster 36 what 48 honey loot 53 2 fast beast 60 61
Step I: loot 28 faster 36 what 48 honey 53 fast beast 60 61
Step II: loot 28 honey 16 faster what 48 53 fast beast 60 61
Step III: loot 28 honey 16 beast 42 faster what 53 fast 60 61
Step IV: loot 28 honey 16 beast 42 faster 47 what fast 60 61
Step V: loot 28 honey 16 beast 42 faster 47 fast 59 what 61
Step VI: loot 28 honey 16 beast 42 faster 47 fast 59 what 60


Q13. Which word/number would be the fourth from the left end in Step IV?
26
78
16
36
None of these
Solution:
Students let us understand the Logic behind this Question and lets understand how to solve it. As a first step lets first understand the logic behind the Output. If you will see the final output you will observe the following:
i) The machine rearranges one word and one number in each step.
ii) The word with the highest value of sum of its vowels is arranged at the leftmost end. For example snooze(O=15+15+5=35). If two words have the same value of the sum of its vowels then they are arranged in alphabetical order.
iii) The number are arranged alternatively in each step in increasing order and the numerical value of the sum of the vowels in the word arranged is subtracted from that number.
For example loot=30 – 2 = 28 Now lets take the arrangement given in the Question

Input: Faster 36 what 48 honey loot 53 2 fast beast 60 61
Step I: loot 28 faster 36 what 48 honey 53 fast beast 60 61
Step II: loot 28 honey 16 faster what 48 53 fast beast 60 61
Step III: loot 28 honey 16 beast 42 faster what 53 fast 60 61
Step IV: loot 28 honey 16 beast 42 faster 47 what fast 60 61
Step V: loot 28 honey 16 beast 42 faster 47 fast 59 what 61
Step VI: loot 28 honey 16 beast 42 faster 47 fast 59 what 60


Q14. After how many steps no further rearrangement of words is possible?
Five
Four
Six
Seven
Eight
Solution:
Students let us understand the Logic behind this Question and lets understand how to solve it. As a first step lets first understand the logic behind the Output. If you will see the final output you will observe the following:
i) The machine rearranges one word and one number in each step.
ii) The word with the highest value of sum of its vowels is arranged at the leftmost end. For example snooze(O=15+15+5=35). If two words have the same value of the sum of its vowels then they are arranged in alphabetical order.
iii) The number are arranged alternatively in each step in increasing order and the numerical value of the sum of the vowels in the word arranged is subtracted from that number.
For example loot=30 – 2 = 28 Now lets take the arrangement given in the Question

Input: Faster 36 what 48 honey loot 53 2 fast beast 60 61
Step I: loot 28 faster 36 what 48 honey 53 fast beast 60 61
Step II: loot 28 honey 16 faster what 48 53 fast beast 60 61
Step III: loot 28 honey 16 beast 42 faster what 53 fast 60 61
Step IV: loot 28 honey 16 beast 42 faster 47 what fast 60 61
Step V: loot 28 honey 16 beast 42 faster 47 fast 59 what 61
Step VI: loot 28 honey 16 beast 42 faster 47 fast 59 what 60


Q15. What will be the position of fast in step VI?
Sixth from right
Seventh from right
Seventh from left
Fourth from right
None of these
Solution:
Students let us understand the Logic behind this Question and lets understand how to solve it. As a first step lets first understand the logic behind the Output. If you will see the final output you will observe the following:
i) The machine rearranges one word and one number in each step.
ii) The word with the highest value of sum of its vowels is arranged at the leftmost end. For example snooze(O=15+15+5=35). If two words have the same value of the sum of its vowels then they are arranged in alphabetical order.
iii) The number are arranged alternatively in each step in increasing order and the numerical value of the sum of the vowels in the word arranged is subtracted from that number.
For example loot=30 – 2 = 28 Now lets take the arrangement given in the Question

Input: Faster 36 what 48 honey loot 53 2 fast beast 60 61
Step I: loot 28 faster 36 what 48 honey 53 fast beast 60 61
Step II: loot 28 honey 16 faster what 48 53 fast beast 60 61
Step III: loot 28 honey 16 beast 42 faster what 53 fast 60 61
Step IV: loot 28 honey 16 beast 42 faster 47 what fast 60 61
Step V: loot 28 honey 16 beast 42 faster 47 fast 59 what 61
Step VI: loot 28 honey 16 beast 42 faster 47 fast 59 what 60


               


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