Directions (1-5): Study the information carefully and answer the questions given below

In a zoo there are six spots A, B, C, D, E, F which have inhabited different animals i.e. lion, tiger, chimpanzee, monkey, giraffe and bear and in different number 2, 3, 4, 5, 6, 10. The zoo are divided equally in two categories Î± and Î².
E has giraffe. Î² category zoo does not has chimpanzee. C has the 2nd least number of animals. F is not Î± category zoo. C and E are in same category. The number of chimpanzee which is not an odd number, is equal to the sum of the number of lion and bear. Monkeys are in highest number. B and D are in same category. C and F do not belong to same category. B has 4 animals. A and the zoo which has giraffe belong to same category. The number of lion is more than the number of tiger. A and D does not have lion and bear.

Q1. What is the number of giraffe in zoo E?
4
3
2
5
none of these
Solution:
E has giraffe. C has the 2nd least number of animals. F is not Î± category zoo So, F is Î². C and F do not belong to same category, so C is Î±. B has 4 animals
The number of chimpanzee, which is not an odd number, is equal to the sum of the number of lion and bear. Monkeys are in highest number. So only one possibility is there, Lion/bear- 2/4 and chimpanzee-6. So, either A can have monkey or D. A and D does not has lion and bear. So in case 1 D has chimpanzee and in case2 A has chimpanzee. In both the cases C has tiger and E has 5 giraffe. Case1-
Case2-
C and E are in same category. A and the zoo which has giraffe belong to same category. The number of lion is more than the number of tiger. B and D are in same category. So, lion are 4 in number. Case1-
Case2-
Î² category zoo does not has chimpanzee. So, case1 gets eliminated. The final arrangement is:

Q2. In which of the following zoo is tiger inhabited?
E
F
C
B
none of these
Solution:
E has giraffe. C has the 2nd least number of animals. F is not Î± category zoo So, F is Î². C and F do not belong to same category, so C is Î±. B has 4 animals
The number of chimpanzee, which is not an odd number, is equal to the sum of the number of lion and bear. Monkeys are in highest number. So only one possibility is there, Lion/bear- 2/4 and chimpanzee-6. So, either A can have monkey or D. A and D does not has lion and bear. So in case 1 D has chimpanzee and in case2 A has chimpanzee. In both the cases C has tiger and E has 5 giraffe. Case1-
Case2-
C and E are in same category. A and the zoo which has giraffe belong to same category. The number of lion is more than the number of tiger. B and D are in same category. So, lion are 4 in number. Case1-
Case2-
Î² category zoo does not has chimpanzee. So, case1 gets eliminated. The final arrangement is:

Q3. Which of the following combination is true?
E-giraffe-2
F-lion-4
C-tiger-6
B-lion-10
none of these
Solution:
E has giraffe. C has the 2nd least number of animals. F is not Î± category zoo So, F is Î². C and F do not belong to same category, so C is Î±. B has 4 animals
The number of chimpanzee, which is not an odd number, is equal to the sum of the number of lion and bear. Monkeys are in highest number. So only one possibility is there, Lion/bear- 2/4 and chimpanzee-6. So, either A can have monkey or D. A and D does not has lion and bear. So in case 1 D has chimpanzee and in case2 A has chimpanzee. In both the cases C has tiger and E has 5 giraffe. Case1-
Case2-
C and E are in same category. A and the zoo which has giraffe belong to same category. The number of lion is more than the number of tiger. B and D are in same category. So, lion are 4 in number. Case1-
Case2-
Î² category zoo does not has chimpanzee. So, case1 gets eliminated. The final arrangement is:

Q4. Four of the following belongs to a group find the one that does not belong to that group?
E
F
D
B
A
Solution:
E has giraffe. C has the 2nd least number of animals. F is not Î± category zoo So, F is Î². C and F do not belong to same category, so C is Î±. B has 4 animals
The number of chimpanzee, which is not an odd number, is equal to the sum of the number of lion and bear. Monkeys are in highest number. So only one possibility is there, Lion/bear- 2/4 and chimpanzee-6. So, either A can have monkey or D. A and D does not has lion and bear. So in case 1 D has chimpanzee and in case2 A has chimpanzee. In both the cases C has tiger and E has 5 giraffe. Case1-
Case2-
C and E are in same category. A and the zoo which has giraffe belong to same category. The number of lion is more than the number of tiger. B and D are in same category. So, lion are 4 in number. Case1-
Case2-
Î² category zoo does not has chimpanzee. So, case1 gets eliminated. The final arrangement is:

Q5. Which of the following animal is inhabited in zoo A?
tiger
lion
monkey
chimpanzee
none of these
Solution:
E has giraffe. C has the 2nd least number of animals. F is not Î± category zoo So, F is Î². C and F do not belong to same category, so C is Î±. B has 4 animals
The number of chimpanzee, which is not an odd number, is equal to the sum of the number of lion and bear. Monkeys are in highest number. So only one possibility is there, Lion/bear- 2/4 and chimpanzee-6. So, either A can have monkey or D. A and D does not has lion and bear. So in case 1 D has chimpanzee and in case2 A has chimpanzee. In both the cases C has tiger and E has 5 giraffe. Case1-
Case2-
C and E are in same category. A and the zoo which has giraffe belong to same category. The number of lion is more than the number of tiger. B and D are in same category. So, lion are 4 in number. Case1-
Case2-
Î² category zoo does not has chimpanzee. So, case1 gets eliminated. The final arrangement is:

Directions (6-7): Study the following information carefully and answer the questions given below:

A is the daughter of E. F has only two children – A and G. H is the brother of I. G is married to K. F has only two daughters. M is the mother of E. H is married to A. M is married to N. F is the son of O.

Q6. Who among the following is the father of E?
M
O
F
N
None of these
Solution:

Q7. Who among the following is the sister-in-law of I?
K
A
E
M
O
Solution:

Directions (8-10) : Study the following information to answer the given questions:

In a certain code, ‘za la ka ga’ is code for ‘cat key pen mobile’,
‘ za fa sa na ‘ is code for ‘we key the boys’ ,
‘ na la da sa’ is a code for ‘ we cat be boys’ ,
and ‘wa sa za da’ is code for ‘be boys key girls’.

Q8. Which of the following is the code for ‘cat’?
sa
da
la
na
None of these
Solution:

Q9. What does the code ‘za’ stand for?
pen
cat
be
girls
key
Solution:

Q10. Which of the following is the code for ‘boys’?
sa
wa
za
la
fa
Solution:

Directions (11-15) : Some statements are given followed by some conclusions. You have to consider the --statements to be true even if they seem to be at variance from commonly known facts. You have to decide which of the following conclusions if any, follow from the given statements:

Q11. Statements: All boys are girls.
Some girls are men.
No men is a women
Conclusion: (i) Some girls are not women
(ii) Some girls are women
(iii) Some boys are not women
Only (i) follow
Only (ii) and (iii) follow
Either (i) or (ii) follow
All follow
None of these
Solution:

Q12. Statements: Some birds are animals.
Some animals are idiots.
All idiots are humans.
No idiots are bat.
Some bats are Animals
Conclusion: (i) Some animals are bats
(ii) Some humans being bat is a possibility
(iii) some humans are definitely not bat
Only (i) follow
Only (ii) and (iii) follow
Only (i) and (ii) follow
All follow
None of these
Solution:

Q13. Statements: All boys are girls.
Some girls are not men.
No men is a women.
Some women are girls.
No women are human.
Conclusion : (i) Some girls are not human.
(ii) Some girls being men is a possibility.
(iii) All boys being men is a possibility.
Only (i) follow
Only (ii) and (iii) follow
Only (i) and (ii) follow
All follow
None of these
Solution:

Q14. Statements: All beetels are nuts.
All nuts are leaves.
All leaves are trash.
Some trash is ball.
No leave is important.
Some important are trash.
Conclusion : (i) All ball being important is a possibility
(ii) Some trash being beetel is a possibility
(iii) Some important being beetel is a possibility
Only (i) follow
Only (ii) and (iii) follow
Only (i) and (ii) follow
All follow
None of these
Solution:

Q15. Statements: All fun is revenge.
No fun is entertainment.
All entertainment is awesome.
Some awesome is revenge.
No revenge is heart.
Conclusion : (i) Some awesome is heart
(ii) Some awesome is not entertainment
(iii) Some awesome is not heart
Only (i) follow
Either (i) or (ii) and (iii) follow
Either (i) or (iii) and (ii) follow
All follow
None of these
Solution: