# IBPS Clerk Pre Quant 16/10/2018

**Q1. In how many different ways the letters of the word ‘LUMINOUS’ can be arranged such that M, I, N never come together?**

18,900

19,800

20,800

18,000

19,000

**Q2. How many numbers greater than 60000 can be made using the digits 0, 2, 4, 6, 4 (repetition is not allowed)?**

24

48

18

32

40

Solution:

Required numbers = 1 × 4 × 3 × 2 × 1 = 24

**Q3. A room is 8 m long, 4√5 wide and 16 m in height. Find the length of the largest rod which can be kept inside the room.**

15 m

18 m

24 m

20 m

30 m

**Q4. The probability of making two digits no. divisible by ‘2’ using the digits 0, 1, 2, 3 is (repetition of digits is not allowed)**

2/3

4/9

5/9

7/9

2/9

Solution:

Possible no. = 3 × 3 = 9

Required no. = 3 × 2 – 1 = 5

∴ Required prob. = 5/9

Required no. = 3 × 2 – 1 = 5

∴ Required prob. = 5/9

**Q5. The perimeter of a rectangle is 66 ⅔% of perimeter of a square whose side is 24 m. If breadth of rectangle is 14 m then its area will be**

225 m²

252 m²

262 m²

272 m²

244 m²

**Directions (6-10): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer**

**Q6.**

if x>y

if x≥y

if x<y

if x ≤y

if x = y or no relation can be established between x and y.

**Q7.**

if x>y

if x≥y

if x ≤y

if x = y or no relation can be established between x and y.

**Q8.**

if x>y

if x≥y

if x ≤y

if x = y or no relation can be established between x and y.

**Q9.**

if x>y

if x≥y

if x ≤y

if x = y or no relation can be established between x and y.

**Q10.**

if x>y

if x≥y

if x≤y

if x = y or no relation can be established between x and y.

**Directions (11-15): Simplify the following questions.**

**Q11. 36 × 15 – 56 × 784 ÷ 112 =?**

138

238

158

258

148

Solution:

? = 540 – 392
= 148

**Q12. 28.314 – 31.427 + 113.928 =? + 29.114**

81.711

80.701

71.711

81.701

80.107

Solution:

? = 81.701

**Q13. 6573 ÷ 21 × (0.2)² =?**

18.25

22.6

15.65

12.52

12.89

Solution:

? = 12.52

**Q14. 475 + 64% of 950 = 900 +?**

183

233

198

186

283

Solution:

? = 475 + 608 – 900 = 183

**Q15.**

7

2

8

3

4

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