IBPS Clerk Pre Quant 16/10/2018




Q1. In how many different ways the letters of the word ‘LUMINOUS’ can be arranged such that M, I, N never come together?
18,900
19,800
20,800
18,000
19,000
Solution:

Q2. How many numbers greater than 60000 can be made using the digits 0, 2, 4, 6, 4 (repetition is not allowed)?
24
48
18
32
40
Solution:
Required numbers = 1 × 4 × 3 × 2 × 1 = 24

Q3. A room is 8 m long, 4√5 wide and 16 m in height. Find the length of the largest rod which can be kept inside the room.
15 m
18 m
24 m
20 m
30 m
Solution:

Q4. The probability of making two digits no. divisible by ‘2’ using the digits 0, 1, 2, 3 is (repetition of digits is not allowed)
2/3
4/9
5/9
7/9
2/9
Solution:
Possible no. = 3 × 3 = 9
Required no. = 3 × 2 – 1 = 5
∴ Required prob. = 5/9

Q5. The perimeter of a rectangle is 66 ⅔% of perimeter of a square whose side is 24 m. If breadth of rectangle is 14 m then its area will be
225 m²
252 m²
262 m²
272 m²
244 m²
Solution:

Directions (6-10): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer 

Q6. 
if x>y
if x≥y
 if x<y
if x ≤y
if x = y or no relation can be established between x and y.
Solution:

Q7. 
if x>y
if x≥y
 if x<y
if x ≤y
if x = y or no relation can be established between x and y.
Solution:

Q8. 
if x>y
if x≥y
 if x<y
if x ≤y
if x = y or no relation can be established between x and y.
Solution:

Q9. 
if x>y
if x≥y
 if x<y
if x ≤y
if x = y or no relation can be established between x and y.
Solution:

Q10. 
if x>y
if x≥y
 if x<y
if x≤y
if x = y or no relation can be established between x and y.
Solution:

Directions (11-15): Simplify the following questions. 

Q11. 36 × 15 – 56 × 784 ÷ 112 =?
138
238
158
258
148
Solution:
? = 540 – 392 = 148

Q12. 28.314 – 31.427 + 113.928 =? + 29.114
81.711
80.701
71.711
81.701
80.107
Solution:
? = 81.701

Q13. 6573 ÷ 21 × (0.2)² =?
18.25
22.6
15.65
12.52
12.89
Solution:
? = 12.52

Q14. 475 + 64% of 950 = 900 +?
183
233
198
186
283
Solution:
? = 475 + 608 – 900 = 183

Q15. 
7
2
8
3
4
Solution:


               

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