**1.Adam can do a job in 15 days, John can do the same job in 20 days. If they work together for 4 days on this job. What fraction of job is incomplete ?**

**2. Ram takes 6 hours to type 32 pages. Shaam takes 5 hours to type 40 pages. In how many hours they will type 110 pages together ?**

**3.7 men take 12 days to complete a job. They worked for 5 days, after 5 days 2 men left the job. In how many days 5 men will complete the job ?**

**4.If A, B and C can do a job in 20, 30 and 60 days respectively. In how many days A can do the work if B and C help him on every third day ?**

**5.A is twice as good as workman as B and together they finish a piece of work in 18 days. In how many days will B alone finish the work?**

**6.A is thrice as good a workman as B and takes 10 days less to do a piece of work than B takes. B alone can do the whole work in ?**

**7.4 men and 6 women finish a job in 8 days, while 3 men and 7 women finish it in 10 days. In how many days will 10 women working together finish it ?**

**8.10 women can complete a work in 7 days and 10 children take 14 days to complete the work. How many days will 5 women and 10 children take to complete the work?**

**9.5 men and 2 boys working together can do four times as much work as a man and a boy. Working capacity of man and boy is in the ratio?**

**10.A work is done by three person A,B and C. A alone takes 10 hours to complete a single product but B and C working together takes 4 hours, for the completion of the same product. If all of them worked together and completed 14 products, then how many hours have they worked?**

**Next topic is Partnership.**

**Answers:**

**1.(D)**

Adam can do 1/15 of the job per day

John can do 1/20 of the job per day

If they work together they can do 7/60 of the work together

Remaining job 1 – 4*7/60 = 32/60 = 8/15

2.**(C)**

Ram can type 32/6 pages per hour

Shaam can type 8 pages per hourThey can type 32/6 + 8 = 40/3 pages per hour

So they will take 110/40 × 3 = 33/4 hours or 8 hours 15 minutes

3.**(E)**

7 men can do 1/12 of the job per day

So after 5 days they have completed 5/12th job. Still 7/12 part of the job is to be completed.

5 men can do 1/12 × 5/7 = 5/84 of the job per day

So they will take 7/12 × 84 /5 = 9 ⅘ days to complete the job

4.**(B)**

Efficiency of A = 1/20 = 5% per day

Efficiency of B = 1/30 = 3.33% per day

Efficiency of C = 1/60 = 1.66% per day

In three days A can do 15% of the job himself and B and C do 5% of the job ( 1.66% + 3.33% )

In three days they can do 20% of the job, to do 100% of the job, they need 3 × 5 = 15 days

5.**(B)**

As per question, A do twice the work as done by B.

So A:B = 2:1

Also (A+B) one day work = 1/18

To get days in which B will finish the work, lets calculate work done by B in 1 day =

=(1/18∗1/3)=1/54

[Please note we multiplied by 1/3 as per B share and total of ratio is 1/3]

So B will finish the work in 54 days

6.**(A)**

Ratio of times taken by A and B = 1:3

Means B will take 3 times which A will do in 1 time

If difference of time is 2 days, B takes 3 days

If difference of time is 10 days, B takes (3/2) * 10 =15 days

7.**(B)**

Let 1 man’s 1 day work = x

and 1 woman’s 1 days work = y.

Then, 4x + 6y = 1/8

and 3x+7y = 1/10

solving, we get y = 1/400 [means work done by a woman in 1 day]

10 women 1 day work = 10/400 = 1/40

10 women will finish the work in 40 days

8**.(B)**

1 woman’s 1 day’s work = 1/70

1 Child’s 1 day’s work = 1/140

5 Women and 10 children 1 day work =

(5/70+10/140)=1/7

So 5 women and 10 children will finish the work in 7 days.

9.**(C)**

Let 1 man 1 day work = x

1 boy 1 day work = y

then 5x + 2y = 4(x+y)

x = 2y

x/y = 2/1

x:y = 2:1

10**.(C)**

1/A=1/10 and

1/B+1/C=1/4 (Given)

1/A+1/B+1/C=1/4+1/10

=7/20

In 20 hours, working together they will complete 7 products.

Thus in 40 hours they will complete 14 products