Reasoning Ability is an onerous section. With the increasing complexity of questions, it becomes hard for one to give it the cold shoulder. Today is the Day 58 of the 60 Days SBI Clerk Prelims Study Plan. The only way to make the grade in this particular section in the forthcoming banking exams is to practice continuously with all your heart and soul. And, to let you practice with the best of the latest pattern questions, here is the Adda247 Reasoning Quiz based on the study plan and the exact same pattern of questions that are being asked in the exams.
Q1. How many such pairs of letters are there in the word ‘RAID’ each of which has as many letters between them in the word as in the English alphabet series ?
(e) More than three
S1. Ans(a) Sol. There is no such pair.
Q2. If in a certain pattern, there is a series, find the next elements which will come in the place of ? according to that pattern of the series?
AD7DH14 HM23 ?
(e) None of these
S2. Ans (d) Sol.
For Number- The number with the alphabets is obtained by adding 2 in resultant of addition of numerical value (place value) of both the letters. For eg- A (1) + D (4) + 2= 7
Q3. If 2 is subtracted from each odd digit in the number 9758462587 and 1 is added to each even digit in number then how many digits of the following number is repeated more than two times in the new number so obtained?
(e) more than three
S3. Ans(c) Sol. new number obtain is 7539573395 i.e. 5 and 3 is repeated more than two times.
Q4. How many pairs of letters are there in the word ” NARENDRAMODI” which have as many letters between them in the word as in the alphabetical series?
(e) more than three
S4. Ans(e) Sol.
Q5. How many meaningful words can be formed using the 3rd ,4th,6thand 7th alphabet of the word “PUBLICATION”?
(e) more than three S5. Ans.(a) Sol.
Directions (6-10): Read the following information and answer the questions that follow:
Rajesh walks 10 m south from point A to reach point B. He then takes a right turn and walks 9 m to reach point C. On the other side, Rohit, who is north to point B, walks 5 m north from point P to reach point Q. Next ‘Rohit’ turns to his left and walks 4m to reach point R and again takes a left turn and walks 10m to reach point E. Also Rajesh turned right from point C and reached point D after walking 5 m. Q is 7m either north or south to point B.
Q6. What is the shortest distance between points B and E?
(a) 6 m
(b) 4 m
(c) 8 m
(d) 5 m
(e) Cannot be Determined
Q7. If Rohit walks 4 m east from point E, then he is in which direction with respect to point B?
Q8. What is the shortest distance between points A and R?
(a) 6 m
(b) 5 m
(d) 4 m
(e) Either (b) or(c)
Q9. What is the direction of D with respect to point Q?
Q10. If Rohit walks a distance of 5m east from point R, then what is the direction of Rohit with respect to point P?
Directions (11-15): In each of the questions below are given some statements followed by some conclusions. You have to take the given statements to be true even if they seem to be at variance with commonly known facts. Read all the conclusions and then decide which of the given conclusions logically follows from the given statements disregarding commonly known facts.
(a) If only conclusion I is true
(b) If only conclusion II is true
(c) If either conclusion I or II is true
(d) If neither conclusion I nor II is true
(e) If both conclusion I and II are true
All banker are adda.
All banker are 247.
Some CP are adda.
I. All 247 can never be CP.
II. Some adda are not banker.
For I- There is no direct relation in between 247 and cp so we cannot say that all 247 can never be a part of cp. For II- There is a relation that some adda are also a part of banker but we cannot conclude that some adda are not a part of banker.
Some ssc are ctet.
All Ctet are jbt.
No ssc is a bjt.
I. All ctet can be ssc.
II. No ssc is a jbt.
For I- There is direct relation of some in between ctet and ssc but we cannot conclude that all ctet are ssc while in a case of possibility it is true that all ctet are ssc.
For II- From the venn diagram, it is clear that, there is a relation of some in between ssc and jbt, but we cannot conclude that no ssc is jbt so it is a false conclusion.
Some files are boxes.
Some plastics are not cartoons.
Some cartoon are files.
I. No file is a plastic.
II. All cartoon can be file .
For I- From the venn diagram , it is clear that, there is no direct relation of no in between file and plastic, so this conclusion can’t be concluded.
For II- From the venn diagram , it is clear that, there is a direct relation of some in between cartoon and file, but as it is a possibility that all cartoon are file so it is true.
All desks are chairs.
Some chairs are seats.
Some seat are desk.
No table is desk.
I. All desks are seat.
II. No chairs is table.
For I- From the venn diagram, it is clear that, there is a direct relation of some in between desk and seat, but we cannot say that all desk are seat, it will be true in a possibility.
For II- From the venn diagram, it is clear that, there is a direct relation of no in between desk and table, but there is no certain relation of no in between chair and table so this conclusion can’t be concluded.
Some Ram are Pray.
Some Rat are Pray.
Some pal are Ram.
I. some Rat are pal. II. Some palarenotrat.
From the venn diagram, we can conclude that both conclusion are false as in conclusion 1 there is no certain relation between Rat and pal and conclusion 2 is negative conclusion and it is also false. But the subject and predicate of both conclusions are same and there is an either-or case as one is positive and other is negative.