SBI PO Quantitative Aptitude (Quadratic Equation) For Prelims: 22nd March 2019

Dear Aspirants,
SBI PO Quantitative Aptitude (Quadratic Equation) For Prelims: 22nd March 2019

Quantitative Aptitude Quiz For SBI PO 

Numerical Ability or Quantitative Aptitude Section has given heebie-jeebies to the aspirants when they appear for a banking examination. As the level of every other section is only getting complex and convoluted, there is no doubt that this section, too, makes your blood run cold. The questions asked in this section are calculative and very time-consuming. But once dealt with proper strategy, speed, and accuracy, this section can get you the maximum marks in the examination. Following is the Quantitative Aptitude quiz to help you practice with the best of latest pattern questions.

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Directions (1-5): In each of these questions, two equation (I) and (II) are given. You have to solve both the equations and give answer 


Q1. I. 6x²+77x+121=0 
II. y²+9y-22=0

if x < y
if x > y
if x ≥ y
if x ≤ y
if x = y or no relationship can be established between x and y
Solution:

Q2. I. x = √625 
II. y = √676

if x < y
if x > y
if x ≥ y
if x ≤ y
if x = y or no relationship can be established between x and y
Solution:

I. x = √625
= +25
II. y = √676
= +26
So, y > x

Q3. I. x²+4x+4=0 
II. y²-8y+16=0

if x < y
if x > y
if x ≥ y
if x ≤ y
if x = y or no relationship can be established between x and y
Solution:

Q4. 

if x < y
if x > y
if x ≥ y
if x ≤ y
if x = y or no relationship can be established between x and y
Solution:

Q5. I. x²-19x+84=0 
II. y²-25y+156=0

if x < y
if x > y
if x ≥ y
if x ≤ y
if x = y or no relationship can be established between x and y
Solution:

Directions (6-10): In each of the following questions two equations are given solve these equations and give answer. 


Q6. I. 3x + 5y = 28 
II. 8x – 3y = 42

if x ≥ y
if x > y
if x ≤ y
if x < y
if x = y or no relation can be established between x and y
Solution:

Q7. I. 6x² + 23x + 20 = 0 
 II. 6y² +31y + 35 = 0

if x ≥ y
if x > y
if x ≤ y
if x < y
if x = y or no relation can be established between x and y
Solution:

Q8. I. 4x² - 25x + 39 = 0 
 II. 18y² - 15y + 3 = 0

if x ≥ y
if x > y
if x ≤ y
if x < y
if x = y or no relation can be established between x and y
Solution:

Q9. I. x² - 72 = x 
 II. y² = 64

if x ≥ y
if x > y
if x ≤ y
if x < y
if x = y or no relation can be established between x and y
Solution:

Q10. I. 30x² + 11x + 1 = 0 
 II. 42y² + 13y + 1 = 0

if x ≥ y
if x > y
if x ≤ y
if x < y
if x = y or no relation can be established between x and y
Solution:

Directions (11-15): In these questions, two equations numbered I and II are given. You have to solve both the equations and give answer 


Q11. I. 25x² + 35x + 12 = 0 
 II. 10y² + 9y + 2 = 0

x ≥ y
x ≤ y
x < y
x > y
x = y or Relationship between x and y cannot be established
Solution:

Q12. I. 12x² + 7x + 1 = 0 
 II. 6y² + 5y + 1 = 0

x ≥ y
x ≤ y
x < y
x > y
x = y or Relationship between x and y cannot be established
Solution:

Q13. I. 3x² - 13x – 10 = 0 
 II. 3y² + 10y – 8 = 0

x ≥ y
x ≤ y
x < y
x > y
x = y or Relationship between x and y cannot be established
Solution:

Q14. I. 2x² - 21x + 52 = 0 
 II. 2y² - 11y + 12 = 0

x ≥ y
x ≤ y
x < y
x > y
x = y or Relationship between x and y cannot be established
Solution:

Q15. I. 3x² - 13x + 14 = 0 
 II. 2y² - 5y + 3 =0

x ≥ y
x ≤ y
x < y
x > y
x = y or Relationship between x and y cannot be established
Solution:

               






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