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Quantitative Aptitude For IBPS PO/Clerk Prelims: 4th February 2019

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Quantitative Aptitude For IBPS PO/Clerk Prelims: 4th February 2019

Quantitative Aptitude Quiz For IBPS PO/Clerk Prelims

Numerical Ability or Quantitative Aptitude Section has given heebie-jeebies to the aspirants when they appear for a banking examination. As the level of every other section is only getting complex and convoluted, there is no doubt that this section, too, makes your blood run cold. The questions asked in this section are calculative and very time-consuming. But once dealt with proper strategy, speed, and accuracy, this section can get you the maximum marks in the examination. Following is the Quantitative Aptitude quiz to help you practice with the best of latest pattern questions.


Q1. If the average age of father, mother & their 2 sons is 41 years. And 5 years ago, the ratio of ages of father, mother and two sons (elder and younger) was 7 : 4 : 3 : 2. Then find the sum of ages of two sons after 6 years ?

59 years.
62 years
57 years
47 years
67 years
Solution:

Let total present age of father, mother & two sons = 41 × 4 = 164 years
Let total ages, 5 years before be 16x
ATQ,
16x = 164 – 20 = 144
x = 9 years
∴ Total age of both sons after 6 years = 9 × 3 + 9 × 2+10 + 12 = 67 years

Q2. A person’s present age is 2.5 times of his son’s present age whereas the ratio of his wife’s present age to his present age is 5 : 6. 10 years ago, the ratio of person, his son and his wife’s age is 25 : 7 : 20. Find the present average age of all the three?

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Solution:

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Q3. The sum of present age of Veer and Abhi is 56 years. The age of Abhi two years hence is equal to the age of Satish two years ago and the average of present age of Satish and Abhi is 26 years. Then find the present age of Veer ?

26 years
28 years
30 years
32 years
34 years
Solution:

Let the present age of Abhi = x years
Then, present age of Veer = (56 – x) years.
Present age of Satish = (x + 2) + 2 = (x + 4) yr.
ATQ,
⇒ x + x + 4 = 52
⇒ 2x = 48
⇒ x = 24 yr.
Present age of Veer = 32 years.

Q4. The average age of 60 students in a college was calculated as 21 years. Later, it was realized that the age of one of the students was taken as 54 years instead of 24 years. Then, find the actual average age of all the students.

19 year
19.5 year
20 year
20.5 year
21 year
Solution:

Total age of 60 students = 60 × 21 = 1260 yrs.
Actual age of 60 students = 1260 – 54 + 24 = 1230 yrs.
Actual avg. age = 1230/60 = 20.5 yrs

Q5. Present age of mother age is 3 times the present age of his son, 5 years hence mother age will be 5/2 times the age of his son. After 10 years from now mother age will be how many times of age of his son at that time.

4 times
3.5 times
3 times
2.2 times
2.8 times
Solution:

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Q6. Average age of all the employees in a company is 32 years. 60% of the employees in the company are female and the ratio of the average age of all female to average age of all male employees is 6 : 7. Find the average age of all the male employees if there are total 50 employees in the company.

35 years
42 years
28 years
49 years
30 years
Solution:

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Q7. The age of father is 4 times the age of his son. 5 years ago the age of son was 1/5 times of his father age. Find the present age of son.

20 yrs
30 yrs
28 yrs
25 yrs
32 yrs
Solution:

Let the age of his son be x yrs
Therefore age of father = 4x yrs
Atq,
(x - 5) = (4x - 5) × (1/5)
5x - 25 = 4x – 5
x = 20 yrs
∴ age of son = 20 yrs

Q8. The sum of the ages of mother and daughter is 65 years. 10 years ago the product of their ages was 5 times the age of mother at that time. Then find the ratio of the present age of mother to the present age of daughter(age of mother is greater than 30 years).

10 : 3
12 : 5
9 : 2
3 : 1
4 : 1
Solution:

Let the present age of mother be x yr.
and that of daughter = (65 – x) yr.
ATQ,
(x – 10) (65 – x – 10) = 5 × (x – 10)
65x - x² - 10x - 650 + 10x + 100 = 5x - 50
-x² + 65x - 550 = 5x - 50
x² - 60x + 500
⇒ x = 50, 10
Required ratio = 50/15 = 10 : 3

Q9. The age of Abhishek is 3/4th of the age of Ayush. The age of Ayush is 11 years more than the average age of his two sons whose total age is 50 years. Then find the difference of age of Abhishek and Ayush ?

14 years
6 years
12 years
8 years
9 years
Solution:

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Q10. Three years ago, average age of ‘A’, ‘B’ and ‘C’ is 27 years. Four years hence, ratio of A and C’s age is 7 : 10. If B is 6 years younger than C, then find present age of ‘A’?

24 years
27 years
30 years
28 years
36 years
Solution:

Three year ago, sum of age of A, B and C together = 27 × 3 = 81 year
Four years hence, sum of ages of A, B and C together = 81 + 7 × 3 = 102
Let Four years hence
A’s age be 7x ⇒ C’s age be 10x and B’s age be 10x–6
ATQ,
7x+10x–6+10x = 102
⇒ 27x = 108 ⇒ x = 4
Four years hence, A’s age = 7×4 = 28
Present age of A = 28–4 = 24 year

Q11. 5 years ago, age of Ankur is 3 times of the age of Arun at that time. Ratio of age of Arun, 5 year hence, and age of Ajay, 5 year ago, is 3 : 5. If difference between age of Ajay and Ankur is 10 years(Ajay is younger than Ankur), then find the age of Arun.

20 years
15 years
18 years
10 years
25 years
Solution:

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Q12. Ratio of age of Amit and Sumit 5 year ago is 5 : 4 and age of Amit 3 year hence is same as present age of Raghav. If average age of all three two year hence is 22 years. Find the present age of Sumit?

17 years
12 years
15 years
None of these
19 years
Solution:

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Q13. Ratio of age of Vikas to age of Rohit 2: 3 and average age of Rohit, Vikas and Rahul is 23. When Arjun joins the group average age of these 4 persons is 25 years. Calculate sum of age Arjun and Rahul, if Rahul is 13 years older than Vikas ?

40 years
47 years
60 years
can’t be determined
None of these
Solution:

Let age of Arjun, Vikas, Rohit and Rahul is a, b, c and d respectively
Now,
b : c = 2 : 3 …(i)
b + c + d = 23 × 3 = 69 …(ii)
a + b + c + d = 25 × 4 = 100
∴ a = 31 years.
Also d – b = 13
d = b + 13
Put this value in eq. (ii)
2b + c = 56
From (i) b = 16 years, d = 29 years
c = 24 years
∴ a + d = 31 + 29 = 60 years.

Q14. In a group of 4 friends, ratio of present age of A and D is 4:5 and that B to C is 3:4. Calculate the present average age of A, B and C, if 4 years ago, A was 20 years younger than C and at present C is twice of age of A.

20 years
50 years
40 years
25 years
30 years
Solution:

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Q15. The average age of a group of six children is 15 years. From the group, two children, whose ages were 3 years more and 5 years more than the average age, left. 4 new children, whose average age is 4 years more than the given average age, join the group. Find the new average age.

15 years
16 years
17 years
18 years
12 years
Solution:

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