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Reasoning For IBPS Exams 2019: 24th January 2019

Dear Aspirants,
Reasoning For IBPS Exams 2019: 24th January 2019 |_2.1

Reasoning Questions for IBPS EXAM 2019:

Reasoning Ability is an onerous section. With the increasing complexity of questions, it becomes hard for one to give it the cold shoulder. The only way to make the grade in this particular section in the forthcoming banking exams. And, to let you practice with the best of the latest pattern questions, here is the Adda247 Reasoning Quiz based on the exact same pattern of questions that are being asked in the exams.


Directions (1-5): Study the following information carefully and answer the questions given below: 

Eight persons A, B, C, D, M, N, O and P were born in different months i.e. March, April, September, October on two different dates 22nd or 25th.

C was born in the month which have odd number of days. More than three persons was born in between C and D. N was born on 25th October. Only two persons was born in between D and P who was born before D. B was born in the month which have even numbers of days and on even number date. M was born in March and four persons was born in between M and A. O was born after P but not in same month.

Q1. Who was born on 25th April?


B
P
A
D
O
Solution:
Reasoning For IBPS Exams 2019: 24th January 2019 |_3.1

Q2. How many persons was born in between C and A?
None
One
Two
Three
More than three
Solution:
Reasoning For IBPS Exams 2019: 24th January 2019 |_3.1
Q3. D was born on which date?
March-25th
April-25th
September-25th
October-22nd
March-22nd
Solution:
Reasoning For IBPS Exams 2019: 24th January 2019 |_3.1
Q4. Four of the following five are alike in a certain way and hence form a group. Who among the following does not belong to that group?
C
P
O
A
N
Solution:
Reasoning For IBPS Exams 2019: 24th January 2019 |_3.1
Q5. Which of the following combination is false?
M- 22nd March
A- 25th September
O- 22nd September
P- 22nd April
N-25th October
Solution:
Reasoning For IBPS Exams 2019: 24th January 2019 |_3.1

Directions (6-10): Study the following information carefully and answer the given questions. 

A number arrangement machine when given an input line of numbers rearranges them following a particular rule in each step. The following is an illustration of input and rearrangement.

Input: 25 32 16 47 89 44 10 73 

Step I: 52 32 16 47 89 44 73 20

Step II: 74 52 32 89 44 73 20 32

Step III: 37 74 52 89 44 20 32 64
Step IV: 98 37 74 52 20 32 64 88
And step IV is the last step of the arrangement. As per the above rule followed in the above steps, find out in each of the following questions the appropriate step for the input given below;
Input: 22 57 38 14 69 15 46 93 

Q6. Which of the following is the last step of above input?


III
VI
IV
V
None of these
Solution:
In this input output question two numbers are arranged in each step following a certain pattern. Let us understand the logic behind it-
* Even numbers are arranged at the right end in ascending order after multiplying two in each number.
* Odd numbers are arranged at the left end in ascending order and the digits are interchanged within the number.
Input: 22 57 38 14 69 15 46 93
Step I: 51 22 57 38 69 46 93 28
Step II: 75 51 38 69 46 93 28 44
Step III: 96 75 51 46 93 28 44 76
Step IV: 39 96 75 51 28 44 76 92
Q7. Which is the following step? Step: 96 75 51 46 93 28 44 76
VI
III
IV
V
There is no such step
Solution:
In this input output question two numbers are arranged in each step following a certain pattern. Let us understand the logic behind it-
* Even numbers are arranged at the right end in ascending order after multiplying two in each number.
* Odd numbers are arranged at the left end in ascending order and the digits are interchanged within the number.
Input: 22 57 38 14 69 15 46 93
Step I: 51 22 57 38 69 46 93 28
Step II: 75 51 38 69 46 93 28 44
Step III: 96 75 51 46 93 28 44 76
Step IV: 39 96 75 51 28 44 76 92

Q8. What is 4th element from right end in Step IV?
28
75
96
44
51
Solution:
In this input output question two numbers are arranged in each step following a certain pattern. Let us understand the logic behind it-
* Even numbers are arranged at the right end in ascending order after multiplying two in each number.
* Odd numbers are arranged at the left end in ascending order and the digits are interchanged within the number.
Input: 22 57 38 14 69 15 46 93
Step I: 51 22 57 38 69 46 93 28
Step II: 75 51 38 69 46 93 28 44
Step III: 96 75 51 46 93 28 44 76
Step IV: 39 96 75 51 28 44 76 92

Q9. Which of the following elements lies exactly between 38 and 28 in step II? 75 51 38 69 46 93 28 44
93
28
51
46
75
Solution:
In this input output question two numbers are arranged in each step following a certain pattern. Let us understand the logic behind it-
* Even numbers are arranged at the right end in ascending order after multiplying two in each number.
* Odd numbers are arranged at the left end in ascending order and the digits are interchanged within the number.
Input: 22 57 38 14 69 15 46 93
Step I: 51 22 57 38 69 46 93 28
Step II: 75 51 38 69 46 93 28 44
Step III: 96 75 51 46 93 28 44 76
Step IV: 39 96 75 51 28 44 76 92

Q10. Which of the following is the forth step for input?
39 96 44 76 92 75 51 28
39 96 75 51 28 44 76 92
39 96 51 28 44 76 92 75
39 96 51 92 75 28 44 76
39 28 44 76 96 51 92 75
Solution:
In this input output question two numbers are arranged in each step following a certain pattern. Let us understand the logic behind it-
* Even numbers are arranged at the right end in ascending order after multiplying two in each number.
* Odd numbers are arranged at the left end in ascending order and the digits are interchanged within the number.
Input: 22 57 38 14 69 15 46 93
Step I: 51 22 57 38 69 46 93 28
Step II: 75 51 38 69 46 93 28 44
Step III: 96 75 51 46 93 28 44 76
Step IV: 39 96 75 51 28 44 76 92

Directions (11-15): Study the following information carefully and answer the given questions. 

In a certain code language, 


‘Outlook brave gloomy income’ is coded as ‘mx fe fm mn’ 
‘global benefit annual brave’ is coded as ‘fm xe kx dc’ 
‘Outlook brave impact global’ is coded as ‘xe fm fe gh’ 
‘gloomy brave google’ is coded as ‘ht mx fm’ 

Q11. Which of the following is the code for ‘brave’?


mx
xe
fe
fm
None of these
Solution:
Reasoning For IBPS Exams 2019: 24th January 2019 |_8.1

Q12. Which of the following word is coded as ‘ht’?
benefit
Outlook
google
gloomy
None of these
Solution:
Reasoning For IBPS Exams 2019: 24th January 2019 |_8.1
Q13. What may be the code of ‘word Outlook’?
fe fm
fe kx
fe xe
fe zx
None of these
Solution:
Reasoning For IBPS Exams 2019: 24th January 2019 |_8.1
Q14.What is the code for “annual income outlook”?
kx mx ht
dc mn fm
fe dc mn
mn fe kx
Can’t be determine
Solution:
Reasoning For IBPS Exams 2019: 24th January 2019 |_8.1
Q15. Which of the following is the code for ‘benefit’?
kx
mx
dc
either (a) or (c)
fe
Solution:
Reasoning For IBPS Exams 2019: 24th January 2019 |_8.1
                                                               

Reasoning For IBPS Exams 2019: 24th January 2019 |_13.1






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