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Reasoning For NIACL AO Prelims: 26th January 2019

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Reasoning Questions for NIACL AO Exam 2018-19:

Reasoning Ability is an onerous section. With the increasing complexity of questions, it becomes hard for one to give it the cold shoulder. The only way to make the grade in this particular section in the forthcoming banking exams like NIACL AO Prelims is to practice continuously with all your heart and soul. And, to let you practice with the best of the latest pattern questions, here is the Adda247 Reasoning Quiz based on the exact same pattern of questions that are being asked in the exams.

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Directions (1-5): Study the following information to answer the given questions: 

In a certain code
‘li fo nu’ means ‘Experience is mistake’, 

‘pil nu dil’ means ‘Lesson was mistake’ 
‘li re jit re’ means ‘Learn is Learn Teaches’. 

Q1. Which of the following is the code for ‘was’?

pil
nu
pil or dil
li
None of these
Solution:
Reasoning For NIACL AO Prelims: 26th January 2019 |_3.1

Q2. ‘fo re dil pil’ may represent:
learn car is Lesson
learn teaches is Lesson
Experience was learn mistake
learn Lesson was mistake
Experience was learn Lesson
Solution:
Reasoning For NIACL AO Prelims: 26th January 2019 |_3.1
Q3. ‘Lesson is learn teaches’, can be coded as:
pil re li jit
dil re li jit
fo re li jit
Cannot be determined
None of these
Solution:
Reasoning For NIACL AO Prelims: 26th January 2019 |_3.1
Q4. Which one of the following is the code for ‘teaches’?
li
re
jit
nu
None of these
Solution:
Reasoning For NIACL AO Prelims: 26th January 2019 |_3.1
Q5. Which of the following is the code of ‘fo’?
mistake
Experience
Lesson
learn
None of these
Solution:
Reasoning For NIACL AO Prelims: 26th January 2019 |_3.1

Directions (6-10): Study the following information carefully to answer the given questions: 

There are six kabaddi players i.e. A, B, C, D, E and F of different height and different teams – Flying squirrels, Punjab bulls, Delhi devils, Road Dogs, Rocking monks and Jaipur kings are standing on either sides of the road with 3 on each side. Each player of one side is facing a player on the other side of the road.
E, who is the tallest player is exactly opposite to a player from Flying squirrels. The shortest player is exactly opposite to the player from Jaipur kings. A is taller than C but shorter than B and D. The players from Rocking monks and Delhi are facing each other. F who is from Road Dogs, is standing between A and D. C is from Rocking monks and standing opposite to A. The player from Jaipur kings is standing exactly opposite to F. Player B is standing between E and C. No one is standing to the east or south of A.

Q6. Which of the following player is the third tallest?

F
D
B
Either B or D
None of these
Solution:
Reasoning For NIACL AO Prelims: 26th January 2019 |_8.1
Q7. Which of the following is the smallest player?
B
E
F
C
None of these
Solution:
Reasoning For NIACL AO Prelims: 26th January 2019 |_8.1
Q8. The tallest player is from which of the following teams?
Flying squirrels
Punjab bulls
Jaipur kings
Data inadequate
None of these
Solution:
Reasoning For NIACL AO Prelims: 26th January 2019 |_8.1
Q9. Which of the following player is second shortest in height?
Either C or D
C
D
Data inadequate
None of these
Solution:
Reasoning For NIACL AO Prelims: 26th January 2019 |_8.1
Q10. Player D is from which of the following teams?
Flying squirrels
Punjab bulls
ROAD DOGS
Delhi devils
None of these
Solution:
Reasoning For NIACL AO Prelims: 26th January 2019 |_8.1

Directions (11-15): In this question, relationship between different elements is shown in the statements. The statements are followed by conclusions. Study the conclusions based on the given statement and select the appropriate answer. 

Q11. Statements: 

A≥B=Q≤P<J≤Y;Z≥A>X; A<M
Conclusions:
I. B<Y
II. XJ
Only conclusion I is true.
Neither conclusion I nor II is true.
Only conclusion II is true.
Both conclusions I and conclusion II are true.
Either conclusion I or II is true.
Solution:
I.B=Q≤P<J≤Y(TRUE)
II. X<A≥B=Q≤P<J(FALSE)
Q12. Statements: 
M>A≥B=Q;Z≥A>X; Q≤P<J≤Y
Conclusions:
I. Z=Q
II. Z>Q
Only conclusion I is true.
Neither conclusion I nor II is true.
Only conclusion II is true.
Both conclusion I and conclusion II are true.
Either conclusion I or II is true.
Solution:
I.Z≥A≥B=Q(FALSE)
II.Z≥A≥B=Q(FALSE)
Q13. Statements: 
T<R;X<G<R=A≤S
Conclusions:
I. G<S
II. S>T
Only conclusion I is true.
Neither conclusion I nor II is true.
Only conclusion II is true.
Both conclusions I and conclusion II are true.
Either conclusion I or II is true.
Solution:
I.G<R=A≤S(TRUE)
II. S≥A=R>T(TRUE)
Q14. Statements: 
M<K≤I>N;D≥P;I≥C; P=U<M
Conclusions:
I. M<C
II. N>U
Only conclusion I is true.
Neither conclusion I nor II is true.
Only conclusion II is true.
Both conclusions I and conclusion II are true.
Either conclusion I or II is true.
Solution:
I.M<K≤I≥C(FALSE)
II. N<I≥K>M>U=P(FALSE)
Q15. Statements: 
P=U<M<K≤I>N;D≥P;I≥C 
Conclusions: 
I.D≥K
II.I>P
Only conclusion I is true.
Neither conclusion I nor II is true.
Only conclusion II is true.
Both conclusions I and conclusion II are true.
Either conclusion I or II is true.
Solution:
I.D≥P=U<M<K(FALSE)
II. I ≥K>M>U=P(TRUE)
                                          

Reasoning For NIACL AO Prelims: 26th January 2019 |_13.1






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