### Reasoning Questions for SBI PO Prelims 2019:

Reasoning Ability is an onerous section. With the increasing complexity of questions, it becomes hard for one to give it the cold shoulder. The only way to make the grade in this particular section in the forthcoming banking exams. And, to let you practice with the best of the latest pattern questions, here is the Adda247 Reasoning Quiz based on the exact same pattern of questions that are being asked in the exams.

**Directions (1-5): Read the given information carefully and answer the given questions.**

There are seven J, K, L, M, N, O, and P boxes placed in a room in a horizontal arrangement, each having different numbers of toys. M has more toys than only 2 boxes. J has more toys than N but less toys than O. J has more toys than L but less toys than K. N is not the box which has lowest number of toys. The box which has 2nd lowest number of toys has 25 toys. Number of toys in box P is double of box N. The number of toys in the box which has lowest number of toys is 0.5 times of O. Box P contain more toys than J but not highest.

**Q1. Which of the following Box has highest number of toys?**

O

K

J

N

P

Solution:

(i)- M has more toys than only 2 boxes. J has more toys than N and O but less than K, P and O. So position of J is fixed. N is not the box which has lowest number of toys. Hence N contain second lowest number of toys.

__>__ >__> J > M > N > L

(ii)- The box which has 2nd lowest number of toys has 25 toys. Number of toys in box P is double of box N. So, box P has 50 toys. The number of toys in the box which has lowest number of toys is 0.5 times of O. By using this condition, it is clear P has more toys than O and P does not contain highest number of toys. The final arrangement is-

K > P(50) > O > J > M > N(25) > L

**Q2. If the box O has 40 toys, then what is the possible number of toys does L have?**

27

28

18

14

20

Solution:

(i)- M has more toys than only 2 boxes. J has more toys than N and O but less than K, P and O. So position of J is fixed. N is not the box which has lowest number of toys. Hence N contain second lowest number of toys.

__>__ >__> J > M > N > L

(ii)- The box which has 2nd lowest number of toys has 25 toys. Number of toys in box P is double of box N. So, box P has 50 toys. The number of toys in the box which has lowest number of toys is 0.5 times of O. By using this condition, it is clear P has more toys than O and P does not contain highest number of toys. The final arrangement is-

K > P(50) > O > J > M > N(25) > L

**Q3. How many boxes have more toys than J?**

None

Two

Three

One

More than Three

Solution:

(i)- M has more toys than only 2 boxes. J has more toys than N and O but less than K, P and O. So position of J is fixed. N is not the box which has lowest number of toys. Hence N contain second lowest number of toys.

__>__ >__> J > M > N > L

(ii)- The box which has 2nd lowest number of toys has 25 toys. Number of toys in box P is double of box N. So, box P has 50 toys. The number of toys in the box which has lowest number of toys is 0.5 times of O. By using this condition, it is clear P has more toys than O and P does not contain highest number of toys. The final arrangement is-

K > P(50) > O > J > M > N(25) > L

**Q4. If Box L has 10 toys and Box J has 3 times more toys than Box L then what will be the possible toys does M have?**

26

19

21

14

33

Solution:

__>__ >__> J > M > N > L

K > P(50) > O > J > M > N(25) > L

**Q5. Which of the following box contain third highest number of toys?**

J

O

P

N

K

Solution:

__>__ >__> J > M > N > L

K > P(50) > O > J > M > N(25) > L

**Directions (6-10): Study the given information and answer the questions:**

When a word and number arrangement machine is given an input line of words and numbers, it arranges them following a particular rule. The following is an illustration of input and its rearrangement.

**Input: 49 92 home crew 34 few some 64 67 national**

Step I: national 7 49 92 home crew few some 64 67

Step II: national 7 home 4 92 crew few some 64 67

Step III: national 7 home 4 some 1 92 crew few 67

Step IV: national 7 home 4 some 1 crew 4 92 few

Step V: national 7 home 4 some 1 crew 4 few 2

**Step V is the last step of the above arrangement.**

As per the rules followed in the steps given above, find out in each of the following questions the appropriate step for the given input.

**Input: 65 spring 84 99 10 rain colourful 32 winter autumn **

**Q6. How many words/numbers is/ are between the number ‘5’ and the number ‘99’ in step III of the input?**None

Three

Two

Four

Six

Solution:

Logic of the given input output is-

(i) both number and words are arranged in each step

(ii) For words arrangement-The machine rearranges one word and one number in each step. First, it rearranges words in descending order of the number of vowels in the word from left to right. If two words contain the same number of vowels, then they are arranged in alphabetical order.

(iii) For number arrangement-Numbers are arranged in ascending order along with that each number is converted into its digital sum. (For example 39 = 3 + 9 = 1 + 2 = 3)

Input: 65 spring 84 99 10 rain colourful 32 winter autumn

Step I: colourful 1 65 spring 84 99 rain 32 winter autumn

Step II: colourful 1 autumn 5 65 spring 84 99 rain winter

Step III: colourful 1 autumn 5 rain 2 spring 84 99 winter

Step IV: colourful 1 autumn 5 rain 2 winter 3 spring 99

Step V: colourful 1 autumn 5 rain 2 winter 3 spring 9

**Q7. Which word/number would be at the fifth position from right end in step IV?**

2

winter

Rain

5

Spring

Solution:

Logic of the given input output is-

(i) both number and words are arranged in each step

(ii) For words arrangement-The machine rearranges one word and one number in each step. First, it rearranges words in descending order of the number of vowels in the word from left to right. If two words contain the same number of vowels, then they are arranged in alphabetical order.

(iii) For number arrangement-Numbers are arranged in ascending order along with that each number is converted into its digital sum. (For example 39 = 3 + 9 = 1 + 2 = 3)

Input: 65 spring 84 99 10 rain colourful 32 winter autumn

Step I: colourful 1 65 spring 84 99 rain 32 winter autumn

Step II: colourful 1 autumn 5 65 spring 84 99 rain winter

Step III: colourful 1 autumn 5 rain 2 spring 84 99 winter

Step IV: colourful 1 autumn 5 rain 2 winter 3 spring 99

Step V: colourful 1 autumn 5 rain 2 winter 3 spring 9

**Q8. Which of the following would be step III?**

colourful 1 autumn 5 99 winter rain 2 spring 84

colourful 1 5 rain 2 autumn spring 84 99 winter

colourful 1 autumn 5 rain 2 spring 84 99 winter

colourful 1 rain 2 autumn 5 spring 84 99 winter

None of these

Solution:

Logic of the given input output is-

(i) both number and words are arranged in each step

(ii) For words arrangement-The machine rearranges one word and one number in each step. First, it rearranges words in descending order of the number of vowels in the word from left to right. If two words contain the same number of vowels, then they are arranged in alphabetical order.

(iii) For number arrangement-Numbers are arranged in ascending order along with that each number is converted into its digital sum. (For example 39 = 3 + 9 = 1 + 2 = 3)

Input: 65 spring 84 99 10 rain colourful 32 winter autumn

Step I: colourful 1 65 spring 84 99 rain 32 winter autumn

Step II: colourful 1 autumn 5 65 spring 84 99 rain winter

Step III: colourful 1 autumn 5 rain 2 spring 84 99 winter

Step IV: colourful 1 autumn 5 rain 2 winter 3 spring 99

Step V: colourful 1 autumn 5 rain 2 winter 3 spring 9

**Q9. Which step number should be the following output?**

**“colourful 1 autumn 5 winter 2 spring 3 rain 99**

Step III

Step IV

Step V

Step VI

There will be no such step

Solution:

Logic of the given input output is-

(i) both number and words are arranged in each step

Input: 65 spring 84 99 10 rain colourful 32 winter autumn

Step I: colourful 1 65 spring 84 99 rain 32 winter autumn

Step II: colourful 1 autumn 5 65 spring 84 99 rain winter

Step III: colourful 1 autumn 5 rain 2 spring 84 99 winter

Step IV: colourful 1 autumn 5 rain 2 winter 3 spring 99

Step V: colourful 1 autumn 5 rain 2 winter 3 spring 9

**Q10. How many steps are required to get the final output?**

5

4

3

2

6

Solution:

Logic of the given input output is-

(i) both number and words are arranged in each step

Input: 65 spring 84 99 10 rain colourful 32 winter autumn

Step I: colourful 1 65 spring 84 99 rain 32 winter autumn

Step II: colourful 1 autumn 5 65 spring 84 99 rain winter

Step III: colourful 1 autumn 5 rain 2 spring 84 99 winter

Step IV: colourful 1 autumn 5 rain 2 winter 3 spring 99

Step V: colourful 1 autumn 5 rain 2 winter 3 spring 9

**Directions (11-13): Each of these questions is based on the following information:**

(i) A % B means A is the daughter of B.

(ii) A @ B means A is the sister of B.

(iii) A $ B means A is the father of B.

(iv) A * B means A is the son of B.

**Q11. Which of the following shows the relation that K is the cousin of B?**

A $ B % F @ K $ G

A $ B % F @ G $ K

A $ B @ F @ G $ K

A $ K % F @ G $ B

Both (b) and (d)

**Q12. If the expression A @ C * G % B $ F is definitely true, then which of the following is not true?**

C is nephew of F

B is grandfather of A

C is brother of A

G is brother of F

C is grandson of B

**Q13. If the expression A % B $ D $ K @ M * E is definitely true, then which of the following is true?**

D is sister of A

B is father of E

M is grandson of B

E is father of K

K is nephew of A

**Directions (14-15): Study the following information carefully and answer the given questions:**

There are seven members i.e. R, S, T, U, V, W, and X in a family, among them only 2 are males. There are only two married couples. U and V are sisters. X is a child of U. S is father in law of U. R is brother in law of V. W is grand-daughter of T. W is sister of X.

**Q14. How is T related to X’s father?**

Son

Mother

Daughter in law

Brother

father

**Q15. Who among the following is father of W?**

R

V

S

T

X

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