# SBI PO Quantitative Aptitude Quiz: 9th May

**Dear Aspirants,**

**Quantitative Aptitude Quiz For SBI PO/Clerk Prelims**

Numerical Ability or Quantitative Aptitude Section has given heebie-jeebies to the aspirants when they appear for a banking examination. As the level of every other section is only getting complex and convoluted, there is no doubt that this section, too, makes your blood run cold. The questions asked in this section are calculative and very time-consuming. But once dealt with proper strategy, speed, and accuracy, this section can get you the maximum marks in the examination. Following is the Quantitative Aptitude quiz to help you practice with the best of latest pattern questions

**Directions (1-5): Study the following information carefully and answer the questions given beside.**

**Three friends Seeta, Reeta and Geeta spends 12%, 14% and 16% of their monthly salary on travelling in the given order and each of them save half of the remaining amount. The monthly salary of Seeta and Geeta is same and the monthly saving of Seeta is Rs. 360 more than that of Geeta. The total expenditures of Seeta and Reeta together on travelling is Rs. 1240 more than that of Geeta.**

**Q1. What is the monthly expenditure of Seeta and Reeta together on travelling?**

Rs. 4240

Rs. 4120

Rs. 3890

Rs. 4480

Rs. 4032

Solution:

Let the monthly salary of Seeta = Rs. 100x

Then, Monthly expenditures on travelling = 12% of 100x = Rs. 12x

Remaining = Rs. (100x – 12x) = Rs. 88x

Saving = 88x/2 = Rs. 44x

Reeta’s month salary = Rs. 100y

Then, Monthly expenditures on travelling = 14% of 100x = Rs. 14y

Remaining = Rs. (100y – 14y) = Rs. 86y

Saving = 86y/2 = Rs. 43y

The monthly salary of Geeta = The monthly salary of Seeta = Rs. 100x

The monthly expenditures of Geeta on travelling = 16% of 100x = Rs. 16x

Remaining = Rs. (100x – 16x) = Rs. 84x

Saving = 84x/2 = Rs. 42x

The monthly salary of Seeta and Geeta are same and the monthly saving of Seeta is Rs. 360 more than that of Geeta

44x – 42x = 2x = 360

x = 180

The total expenditures of Seeta and Reeta together on travelling is Rs. 1240 more than that of Geeta.

12x + 14y = 16x + 1240

14y = 4x + 1240 = 720 + 1240 = 1960

y = 140

The monthly expenditure of Seeta and Reeta together on travelling = Rs. (12x + 14y) = Rs. (12 × 180 + 14 × 140)

= Rs. (2160 + 1960) = Rs. 4120

Then, Monthly expenditures on travelling = 12% of 100x = Rs. 12x

Remaining = Rs. (100x – 12x) = Rs. 88x

Saving = 88x/2 = Rs. 44x

Reeta’s month salary = Rs. 100y

Then, Monthly expenditures on travelling = 14% of 100x = Rs. 14y

Remaining = Rs. (100y – 14y) = Rs. 86y

Saving = 86y/2 = Rs. 43y

The monthly salary of Geeta = The monthly salary of Seeta = Rs. 100x

The monthly expenditures of Geeta on travelling = 16% of 100x = Rs. 16x

Remaining = Rs. (100x – 16x) = Rs. 84x

Saving = 84x/2 = Rs. 42x

The monthly salary of Seeta and Geeta are same and the monthly saving of Seeta is Rs. 360 more than that of Geeta

44x – 42x = 2x = 360

x = 180

The total expenditures of Seeta and Reeta together on travelling is Rs. 1240 more than that of Geeta.

12x + 14y = 16x + 1240

14y = 4x + 1240 = 720 + 1240 = 1960

y = 140

The monthly expenditure of Seeta and Reeta together on travelling = Rs. (12x + 14y) = Rs. (12 × 180 + 14 × 140)

= Rs. (2160 + 1960) = Rs. 4120

**Q2. The monthly salary of Reeta is how much more than/less than that of Seeta?**

Rs. 2000 more

Rs. 3000 more

Rs. 4000 more

Rs. 3000 less

Rs. 4000 less

Solution:

Let the monthly salary of Seeta = Rs. 100x

Then, Monthly expenditures on travelling = 12% of 100x = Rs. 12x

Remaining = Rs. (100x – 12x) = Rs. 88x

Saving = 88x/2 = Rs. 44x

Reeta’s month salary = Rs. 100y

Then, Monthly expenditures on travelling = 14% of 100x = Rs. 14y

Remaining = Rs. (100y – 14y) = Rs. 86y

Saving = 86y/2 = Rs. 43y

The monthly salary of Geeta = The monthly salary of Seeta = Rs. 100x

The monthly expenditures of Geeta on travelling = 16% of 100x = Rs. 16x

Remaining = Rs. (100x – 16x) = Rs. 84x

Saving = 84x/2 = Rs. 42x

The monthly salary of Seeta and Geeta are same and the monthly saving of Seeta is Rs. 360 more than that of Geeta

44x – 42x = 2x = 360

x = 180

The total expenditures of Seeta and Reeta together on travelling is Rs. 1240 more than that of Geeta.

12x + 14y = 16x + 1240

14y = 4x + 1240 = 720 + 1240 = 1960

y = 140

The monthly salary of Reeta = Rs. 100y = Rs. 14000

The monthly salary of Seeta = Rs. 100x = Rs. 18000

The required answer = Rs. (14000 – 18000) = 4000 less than that of Seeta

Then, Monthly expenditures on travelling = 12% of 100x = Rs. 12x

Remaining = Rs. (100x – 12x) = Rs. 88x

Saving = 88x/2 = Rs. 44x

Reeta’s month salary = Rs. 100y

Then, Monthly expenditures on travelling = 14% of 100x = Rs. 14y

Remaining = Rs. (100y – 14y) = Rs. 86y

Saving = 86y/2 = Rs. 43y

The monthly salary of Geeta = The monthly salary of Seeta = Rs. 100x

The monthly expenditures of Geeta on travelling = 16% of 100x = Rs. 16x

Remaining = Rs. (100x – 16x) = Rs. 84x

Saving = 84x/2 = Rs. 42x

The monthly salary of Seeta and Geeta are same and the monthly saving of Seeta is Rs. 360 more than that of Geeta

44x – 42x = 2x = 360

x = 180

The total expenditures of Seeta and Reeta together on travelling is Rs. 1240 more than that of Geeta.

12x + 14y = 16x + 1240

14y = 4x + 1240 = 720 + 1240 = 1960

y = 140

The monthly salary of Reeta = Rs. 100y = Rs. 14000

The monthly salary of Seeta = Rs. 100x = Rs. 18000

The required answer = Rs. (14000 – 18000) = 4000 less than that of Seeta

**Q3. What is the sum of the saving of all the three friends together?**

Rs. 21500

Rs. 22480

Rs. 24000

Rs. 20800

Rs. 25000

Solution:

Let the monthly salary of Seeta = Rs. 100x

Then, Monthly expenditures on travelling = 12% of 100x = Rs. 12x

Remaining = Rs. (100x – 12x) = Rs. 88x

Saving = 88x/2 = Rs. 44x

Reeta’s month salary = Rs. 100y

Then, Monthly expenditures on travelling = 14% of 100x = Rs. 14y

Remaining = Rs. (100y – 14y) = Rs. 86y

Saving = 86y/2 = Rs. 43y

The monthly salary of Geeta = The monthly salary of Seeta = Rs. 100x

The monthly expenditures of Geeta on travelling = 16% of 100x = Rs. 16x

Remaining = Rs. (100x – 16x) = Rs. 84x

Saving = 84x/2 = Rs. 42x

The monthly salary of Seeta and Geeta are same and the monthly saving of Seeta is Rs. 360 more than that of Geeta

44x – 42x = 2x = 360

x = 180

The total expenditures of Seeta and Reeta together on travelling is Rs. 1240 more than that of Geeta.

12x + 14y = 16x + 1240

14y = 4x + 1240 = 720 + 1240 = 1960

y = 140

The required sum = Rs. (44x + 43y + 42x) = Rs. (86x + 43y) = Rs. (86 × 180 + 43 × 140) = Rs. (15480 + 6020) = Rs. 21500

Then, Monthly expenditures on travelling = 12% of 100x = Rs. 12x

Remaining = Rs. (100x – 12x) = Rs. 88x

Saving = 88x/2 = Rs. 44x

Reeta’s month salary = Rs. 100y

Then, Monthly expenditures on travelling = 14% of 100x = Rs. 14y

Remaining = Rs. (100y – 14y) = Rs. 86y

Saving = 86y/2 = Rs. 43y

The monthly salary of Geeta = The monthly salary of Seeta = Rs. 100x

The monthly expenditures of Geeta on travelling = 16% of 100x = Rs. 16x

Remaining = Rs. (100x – 16x) = Rs. 84x

Saving = 84x/2 = Rs. 42x

The monthly salary of Seeta and Geeta are same and the monthly saving of Seeta is Rs. 360 more than that of Geeta

44x – 42x = 2x = 360

x = 180

The total expenditures of Seeta and Reeta together on travelling is Rs. 1240 more than that of Geeta.

12x + 14y = 16x + 1240

14y = 4x + 1240 = 720 + 1240 = 1960

y = 140

The required sum = Rs. (44x + 43y + 42x) = Rs. (86x + 43y) = Rs. (86 × 180 + 43 × 140) = Rs. (15480 + 6020) = Rs. 21500

**Q4. The total monthly saving of three friends together is what percentage of their total monthly salary?**

42%

44%

41%

43%

40%

Solution:

Let the monthly salary of Seeta = Rs. 100x

Then, Monthly expenditures on travelling = 12% of 100x = Rs. 12x

Remaining = Rs. (100x – 12x) = Rs. 88x

Saving = 88x/2 = Rs. 44x

Reeta’s month salary = Rs. 100y

Then, Monthly expenditures on travelling = 14% of 100x = Rs. 14y

Remaining = Rs. (100y – 14y) = Rs. 86y

Saving = 86y/2 = Rs. 43y

The monthly salary of Geeta = The monthly salary of Seeta = Rs. 100x

The monthly expenditures of Geeta on travelling = 16% of 100x = Rs. 16x

Remaining = Rs. (100x – 16x) = Rs. 84x

Saving = 84x/2 = Rs. 42x

The monthly salary of Seeta and Geeta are same and the monthly saving of Seeta is Rs. 360 more than that of Geeta

44x – 42x = 2x = 360

x = 180

The total expenditures of Seeta and Reeta together on travelling is Rs. 1240 more than that of Geeta.

12x + 14y = 16x + 1240

14y = 4x + 1240 = 720 + 1240 = 1960

y = 140

Their total monthly salary = Rs. (100x + 100y + 100x) = Rs. (200x + 100y) = Rs. (36000 + 14000) = Rs. 50000

Total monthly saving = Rs. (44x + 43y + 42x) = Rs. (86x + 43y) = Rs. (86 × 180 + 43 × 140) = Rs. (15480 + 6020) = Rs. 21500

The reqd. answer =

= 43%

Then, Monthly expenditures on travelling = 12% of 100x = Rs. 12x

Remaining = Rs. (100x – 12x) = Rs. 88x

Saving = 88x/2 = Rs. 44x

Reeta’s month salary = Rs. 100y

Then, Monthly expenditures on travelling = 14% of 100x = Rs. 14y

Remaining = Rs. (100y – 14y) = Rs. 86y

Saving = 86y/2 = Rs. 43y

The monthly salary of Geeta = The monthly salary of Seeta = Rs. 100x

The monthly expenditures of Geeta on travelling = 16% of 100x = Rs. 16x

Remaining = Rs. (100x – 16x) = Rs. 84x

Saving = 84x/2 = Rs. 42x

The monthly salary of Seeta and Geeta are same and the monthly saving of Seeta is Rs. 360 more than that of Geeta

44x – 42x = 2x = 360

x = 180

The total expenditures of Seeta and Reeta together on travelling is Rs. 1240 more than that of Geeta.

12x + 14y = 16x + 1240

14y = 4x + 1240 = 720 + 1240 = 1960

y = 140

Their total monthly salary = Rs. (100x + 100y + 100x) = Rs. (200x + 100y) = Rs. (36000 + 14000) = Rs. 50000

Total monthly saving = Rs. (44x + 43y + 42x) = Rs. (86x + 43y) = Rs. (86 × 180 + 43 × 140) = Rs. (15480 + 6020) = Rs. 21500

The reqd. answer =

= 43%

**Q5. By how much should Seeta's monthly salary be increased so the monthly expenditures of Seeta on travelling will become equal to that of Geeta?**

Rs. 4000

Rs. 6000

Rs. 8000

Rs. 3600

Rs. 2500

Solution:

Let the monthly salary of Seeta = Rs. 100x

Then, Monthly expenditures on travelling = 12% of 100x = Rs. 12x

Remaining = Rs. (100x – 12x) = Rs. 88x

Saving = 88x/2 = Rs. 44x

Reeta’s month salary = Rs. 100y

Then, Monthly expenditures on travelling = 14% of 100x = Rs. 14y

Remaining = Rs. (100y – 14y) = Rs. 86y

Saving = 86y/2 = Rs. 43y

The monthly salary of Geeta = The monthly salary of Seeta = Rs. 100x

The monthly expenditures of Geeta on travelling = 16% of 100x = Rs. 16x

Remaining = Rs. (100x – 16x) = Rs. 84x

Saving = 84x/2 = Rs. 42x

The monthly salary of Seeta and Geeta are same and the monthly saving of Seeta is Rs. 360 more than that of Geeta

44x – 42x = 2x = 360

x = 180

The total expenditures of Seeta and Reeta together on travelling is Rs. 1240 more than that of Geeta.

12x + 14y = 16x + 1240

14y = 4x + 1240 = 720 + 1240 = 1960

y = 140

Let the monthly salary of Seeta was increased by Rs a then,

12% × (18000 + a) = 16% × 18000

3 × (18000 + a) = 4 × 18000

a = Rs 6000

Then, Monthly expenditures on travelling = 12% of 100x = Rs. 12x

Remaining = Rs. (100x – 12x) = Rs. 88x

Saving = 88x/2 = Rs. 44x

Reeta’s month salary = Rs. 100y

Then, Monthly expenditures on travelling = 14% of 100x = Rs. 14y

Remaining = Rs. (100y – 14y) = Rs. 86y

Saving = 86y/2 = Rs. 43y

The monthly salary of Geeta = The monthly salary of Seeta = Rs. 100x

The monthly expenditures of Geeta on travelling = 16% of 100x = Rs. 16x

Remaining = Rs. (100x – 16x) = Rs. 84x

Saving = 84x/2 = Rs. 42x

The monthly salary of Seeta and Geeta are same and the monthly saving of Seeta is Rs. 360 more than that of Geeta

44x – 42x = 2x = 360

x = 180

The total expenditures of Seeta and Reeta together on travelling is Rs. 1240 more than that of Geeta.

12x + 14y = 16x + 1240

14y = 4x + 1240 = 720 + 1240 = 1960

y = 140

Let the monthly salary of Seeta was increased by Rs a then,

12% × (18000 + a) = 16% × 18000

3 × (18000 + a) = 4 × 18000

a = Rs 6000

**Directions (6-8): In the following questions two quantities are given for each question. Compare the numeric value of both the quantities and answers accordingly.**

**Q6. Quantity 1: No. of five digits number which can be formed using the digits 1, 3, 4, 5, 6, 7 without repetition of digits.**

**Quantity 2: Length of platform. Speed of a train is 90 km/h. It crosses a platform and a pole in 36 seconds and 6 seconds respectively.**

Quantity 1 > Quantity 2

Quantity 1 < Quantity 2

Quantity 1 ≥ Quantity 2

Quantity 1 ≤ Quantity 2

Quantity 1 = Quantity 2

**Q7. Quantity 2: Time in which the tank will be filled from start. A tap ‘A’ can fill a cistern in 12 hours while another tap B can empty the filled tank in 18 hours. If both pipes are opened together and after 3 hours tap B is closed.**

**Quantity 1: A man covers half of total distance with 12 km/h and another half distance with 24km/h. Find his average speed.**

Quantity 1 > Quantity 2

Quantity 1 < Quantity 2

Quantity 1 ≥ Quantity 2

Quantity 1 ≤ Quantity 2

Quantity 1 = Quantity 2

**Q8. Quantity1: Ravi can do three fourth of a work in 27/2 hours while Hira can do two third of the same work in 8 hours. If both started working together then in how much time the work will be completed?**

**Quantity 2: Raju’s age before two years was 75% of his sister, Rita’s age. After two years, Rita’s age will be**

**of her father’s age. Average age of Rita’s father and mother is 31 yrs. If Rita’s mother’s age is 28 yrs then what is the present age of Raju?**

Quantity 1 > Quantity 2

Quantity 1 < Quantity 2

Quantity 1 ≥ Quantity 2

Quantity 1 ≤ Quantity 2

Quantity 1 = Quantity 2

**Directions (9-15): What will come in place of the question mark (?) in the following questions?**

**Q9.**

17

19

279

289

269

**Q10.**

3

4

5

6

8

**Q11.**

5

6

7

8

10

**Q12.**

**Q13. 36% of 245 – 40% of 210 = 10 –?**

4.2

6.8

4.9

5.6

5.8

**Q14. 4345 + 5625 + 7125 – 3345 = ?**

11,750

13,750

12,750

10,350

14,450

Solution:

? = 17095 – 3345 = 13,750

**Q15.**

36

32

25

16

49

## No comments