Directions (1-5): In each of these questions a number series is given. In each series only one number is wrong. Find out the wrong number.
Q1. 111, 121, 134, 155, 191, 251, 345
(a)345
(b)111
(c)251
(d)191
(e)121
Q2. 1.5, 5, 36, 280, 1953, 11712, 58556
(a)5
(b)1.5
(c)1953
(d)58556
(e)11712
Q3. 1, 17, 25, 54, 218, 1745, 27920.50
(a)27920.50
(b)218
(c)1745
(d)17
(e)1
Q4. 55, 61, 48, 69, 39, 81, 25
(a)48
(b)69
(c)39
(d)25
(e)61
Q5. 492, 489, 481, 457, 409, 290, 121
(a)409
(b)482
(c)290
(d)221
(e)457
Directions (6-15): What approximate value will come in place of question mark (?) in the following questions? (You are not expected to calculate the exact value)
Q6. ?/5.02+44.98=(9.99)²-40.01
(a)35
(b)25
(c)75
(d)65
(e)55
Q7. 50.05% of 299.90+?% of 150.06=449.99
(a)600
(b)300
(c)500
(d)100
(e)200
Q8. 15.10% of 120+?=12.12×6.06
(a)26
(b)12
(c)36
(d)54
(e)42

Q11. 25.05% of 2500.01+10.10% of 3499.99=?+299.99
(a)325
(b)555
(c)445
(d)785
(e)675
Q12. 999.99+50.05-625.20=4.98× ?
(a)85
(b)55
(c)25
(d)45
(e)75
Q13. 5555.05+555.05+55.05+5=?
(a)6870
(b)8890
(c)7560
(d)6170
(e)8690
Q14. (12.02)²+(4.99)²=? ²
(a)11
(b)13
(c)17
(d)19
(e)21
Q15. (79.99+105.10-34.99)÷4.99=?+15.09
(a)10
(b)25
(c)15
(d)35
(e)50
Solutions








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