SBI PO Quantitative Aptitude For Prelims: 6th March 2019

Dear Aspirants,
SBI PO Quantitative Aptitude For Prelims: 6th March 2019

Quantitative Aptitude Quiz For SBI PO 

Numerical Ability or Quantitative Aptitude Section has given heebie-jeebies to the aspirants when they appear for a banking examination. As the level of every other section is only getting complex and convoluted, there is no doubt that this section, too, makes your blood run cold. The questions asked in this section are calculative and very time-consuming. But once dealt with proper strategy, speed, and accuracy, this section can get you the maximum marks in the examination. Following is the Quantitative Aptitude quiz to help you practice with the best of latest pattern questions.

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Directions (1-5): Study the following Bar-graph carefully to answer the questions that follow. The graph shows monthly income (in thousand) in six different years by Adil, Suhana and Jaya. 




Q1. What was the difference between the average monthly income of Adil in all the years together and Suhana’s monthly income in the year 2001?

Rs. 5.5 thousand
Rs. 6.5 thousand
Rs. 7.5 thousand
Rs. 8.5 thousand
Rs. 6 thousand
Solution:

Q2. What is the ratio of Adil’s monthly income in the year 2000, Suhana’s monthly income in the year 2001 and Jaya’s monthly income in the year 1999?

6 : 3 : 5
6 : 4 : 5
5 : 6 : 4
5 : 4 : 7
6 : 5 : 3
Solution:

Required ratio
= 18: 15: 9
= 6: 5: 3

Q3. In which year was the difference between Jaya’s and Adil’s monthly income the second highest?

1999
2000
2004
2001
2002
Solution:

From graph the required year is 2000

Q4. The monthly income of Suhana in the year 2003 was approximately what percentage of the monthly income of Jaya in the year 2004?

72%
89%
83%
67%
95%
Solution:

Q5. What was the percentage increase in the monthly income of Jaya in the year 2002 as compared to the previous year?

50%
150%
160%
60%
40%
Solution:

Q6. A and B together can complete a work in 5 days. They start together but after 3 days B left the work. If the work is completed after two more days. A alone could do the work in

5 days
9 days
6 days
10 days
12 days
Solution:

3 days work of A and B together = 3/5
Remaining work = 2/5
∵2/5 work A completes in 4 days
∴ Whole work will be completed by A in = 10 days

Q7. Two persons X and Y can dig a pit in 16 hours together. They worked together 4 hours and then a third person Z whose efficiency is half of their together’s efficiency joins them. Find in how many time the whole work will be completed?

10 hrs.
13 hrs.
12 hrs.
16 hrs.
18 hrs.
Solution:

Q8. C is twice as efficient as A. B takes thrice as many days as C. A takes 12 days to finish the work alone. If they work in pairs (i.e., AB, BC, CA) starting with AB on the first day, BC on the second day and AC on the third day and so on, then how many days are required to finish the work?

Solution:

Q9. The sum of present ages of Ria and Abby is 48 years. Today Abby is 4 years older than Shweta. The respective ratio of the present ages of Ria and Shweta is 4 : 7. What was Abby’s age two years ago ?

32 years
30 years
28 years
34 years
26 years
Solution:

Let present ages of Ria and Shweta be 4x and 7x respectively.
∴ Abby’s present age = (7x + 4) years
ATQ,
4x +7x + 4 = 48
⇒ x = 4
∴ Abby’s age two years ago = (7x + 4) -2
⇒ 32 - 2 = 30 years

Q10. The age of Sulekha and Arunima are in the ratio of 9 : 8 respectively. After 5 years the ratio of their age will be 10 : 9. What is the difference (in years) between their age ?

4 years
5 years
6 years
7 years
8 years
Solution:

Directions (11-15): What will come in place of question mark (?) in the following number series? 


Q11. 54, 77, 116, 187, 322, ?

521
578
585
713
649
Solution:

Q12. 1, 2, 6, ? , 88, 445

18
20
21
24
26
Solution:

Series is ×1+1, ×2×2, ×3+3, ×4+4, ×5+5
So, ? = 6 × 3 + 3 = 21.

Q13. 1, 3.5, 5, 14.5, 41.5, ?

168
141.25
149.25
143.25
147.25
Solution:

Pattern is ×1.5+2, ×2-2, ×2.5+2, ×3-2, ×3.5+2, …..
? = 41.5 × 3.5 + 2 = 147.25

Q14. 113, 105, 9, ? , -639

-219
-227
-221
-223
223
Solution:

Series is
11² - 2³ = 121 - 8 = 113
13² - 4³ = 169 - 64 = 105
15² - 6³ = 225 - 216 = 9
17² - 8³ = 289 - 512 = ? (-223)
19² - 10³ = 361 - 1000 = - 639

Q15. 71, 76, 84, 97, 118, ?

152
154
139
150
156
Solution:

               






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