Dear Aspirants,

Quantitative Aptitude Quiz For LIC AAO
Numerical Ability or Quantitative Aptitude Section has given heebie-jeebies to the aspirants when they appear for a banking examination. As the level of every other section is only getting complex and convoluted, there is no doubt that this section, too, makes your blood run cold. The questions asked in this section are calculative and very time-consuming. But once dealt with proper strategy, speed, and accuracy, this section can get you the maximum marks in the examination. Following is the Quantitative Aptitude quiz to help you practice with the best of latest pattern questions.

Directions (1-5): Study the bar graph given below and answer the following questions:

The bar graph below shows the percentage break-up of number of persons who voted for three candidates in five different constituency of Uttar Pradesh in parliament election of India.
Note: Total votes obtained by all the three candidates in each constituency is associated with constituency as shown in the bar graph.
No. of votes are in hundreds.

Q1. If the ratio of female to male votes in total votes obtained by Tej Pratap from Lucknow is 7: 8 then the no. of female votes obtained by him from Lucknow is what percent of the total no. of votes obtained by him from all the constituency together ? (approximately)
19%
23%
25%
15%
21%
Solution:

Q2. What is the difference between the total number of votes obtained by Baldev Singh and by Sharmila Devi ?
10,100
14,100
12,100
15,100
12,500
Solution:
Total no. of votes obtained by Baldev Singh
= (0.5 × 150 + 0.5 × 200 + 0.3 × 250 + 0.4 × 350 + 0.3 × 200) × 100
= 45,000
Total no. of votes obtained by Sharmila Devi
= (0.3 × 150 + 0.2 × 200 + 0.1 × 250 + 0.34 × 350 + 0.5 × 200) × 100
= 32,900
∴ Required difference = 45000 – 32,900 = 12,100

Q3. What is the total no. of votes obtained by Bladev Singh from all the five constituency together ?
37,100
45,000
32,900
46,500
45,500
Solution:
Total no. of votes obtained by Baldev Singh from all constituency together
= 45,000 (from solution 2)

Q4. The number of votes obtained by Baldev Singh & Sharmila Devi together from Lucknow is what percent of the number of votes obtained by Tej Pratap from Lucknow, Jhansi and Gorakhpur together ? (approximate)
52%
49%
42%
46%
36%
Solution:

Q5. Find the average no. of votes obtained by Baldev Singh from all the constituency?
9500
9000
10500
8900
9050
Solution:

Q6. A boat travels upstream from B to A and downstream from A to B in 3 h. If the speed of the boat in still water is 9 Km/h and the speed of the current is 3 Km/h, what is the distance between A and B?
6 Km
4 Km
8 Km
12 Km
15 Km
Solution:

Q7. A man can row at the rate of 4 km/hr in still water. If the time taken to row a certain distance upstream is 3 times as much as to row the same distance downstream, find the speed of the current ?
3 km/hr
1.5 km/hr
1 km/hr
2 km/hr
5 km/hr
Solution:

Q8. P, Q and R are three towns on a river which flows uniformly. Q is equidistant from P and R. A man rows from P to Q and back in 10 hrs. He can row from P to R in 4rs. The ratio of speed of man in still water to the speed of the current is:
5 : 3
3 : 5
2 : 5
1 : 2
None of these
Solution:

Q9. Ram and Shyam are travelling from point A to B, which are 60 km apart. Travelling at a certain speed Ram takes one hour more than Shyam to reach point B. If Ram doubles his speed he will take 30 minutes less than Shyam to reach point B. At what speed was Ram driving from point A to B ?
15 kmph
35 kmph
30 kmph
25 kmph
20 kmph
Solution:

Q10. A 180 metres long train crosses another 270 metres long train running in the opposite direction in 10.8 seconds. If the speed of the first train is 60 kmph, what is the speed of the second train in kmph ?
80 kmph
90 kmph
150 kmph
cannot be determined
None of these
Solution:

Directions (11-15): In each of the following questions a number series is given which has only one wrong number. You have to find out the wrong number.

Q11. 7.5 47.5 87.5 157.5 247.5 357.5 487.5
357.5
87.5
157.5
7.5
47.5
Solution:
The given number series is based pattern +30,+50,+70,+90,+110,+130
Clearly, 47.5 is the wrong number. It should be replaced by 37.5.

Q12. 13 16 21 27 39 52 69
21
39
27
52
16
Solution:
The given number series is based on the following pattern:
13 + 3 = 16
16 + 5 = 21
21 + 7 = 28 ≠ 27
28 + 11 = 39
39 + 13 = 52
52 + 17 = 69
Clearly, 27 is the wrong number. It should be replaced by 28.

Q13. 1500 1581 1664 1749 1833 1925 2016
1581
1664
1833
1925
1749
Solution:
The given number series is based on the following pattern:
1500 + 81 = 1581
1581 + 83 = 1664
1664 + 85 = 1749
1749 + 87 = 1836 ≠ 1833
1836 + 89 = 1925
1925 + 91 = 2016
Clearly, 1833 is the wrong number. It should be replaced by 1836.

Q14. 36 54 18 27 9 18.5 4.5
4.5
18.5
54
18
27
Solution:
Pattern of series is–
36 × 1.5 = 54
54 ÷ 3 = 18
18 × 1.5 = 27
27 ÷ 3 = 9
9 × 1.5 = 13.5 ≠ 18.5
13.5 ÷ 3 = 4.5

Q15. 1 8 27 64 124 216 343
8
27
64
124
216
Solution:
Pattern of series is
1³, 2³, 3³, 4³, [5³ = 125 ≠ 124], 216, 343

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