# SBI PO Quantitative Aptitude Quiz: 13th May

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**SBI PO Quantitative Aptitude Quiz**

The questions asked in the quantitative aptitude section are calculative and very time-consuming. But once dealt with proper strategy, speed, and accuracy, this section can get you the maximum marks in the examination. Following is the Quantitative Aptitude quiz to help you practice with the best of latest pattern questions**Directions (1-5): The following table shows total number of magazines published in 6 different years and percentage of good and defective magazines in those years also by a company. Study the table and answer the questions given below.**

**Q1. What is the average number of defective magazines in the year 2006, 2008 and 2010 together ?**

6,304

4,304

5,304

3,403

3,604

**Q2. The good magazines published in the year 2007 are approximately what percent more or less than the number of defective magazines published in 2011 ?**

456%

486%

525%

320%

376%

**Q3. What is the total number of good magazines published in year 2007, 2009 and 2010 together?**

65,650

82,790

77,894

70,294

85,974

**Q4. What is the difference between number of good magazines published in the year 2011 and number of good magazines published in the years 2007 and 2008 together ?**

2,488

2,388

2,255

2,648

2,848

Solution:

Required difference = (80% of 22,500 + 82% of 26,400) – (92% of 40,500)

= 39,648 – 37,260

= 2,388

= 39,648 – 37,260

= 2,388

**Q5. If percentage of good magazines is increased by 10% and total magazines also increased by 20% in year 2012 than 2011, then what will be the number of defective magazines published in the year 2012 ?**

8,050

7,550

8,214

7,614

None of these

**Directions (6-10): In each of the following questions two equations are given. You have to solve the equations and Give answer –**

**Q6. I. 8x² + 26x + 15 = 0**

**II. 4y² + 24y + 35 = 0**

if x < y

if x ≤ y

relationship between x and y cannot be determined

if x ≥ y

if x > y

Solution:

I. 8x² + 26x + 15 = 0

⇒ 8x² + 20x + 6x + 15 = 0

⇒ 4x (2x + 5) + 3(2x + 5) = 0

⇒ (2x + 5) (4x + 3) = 0

⇒ x = – 5/2, –3/4

II. 4y² + 24y + 35 = 0

⇒ 4y² + 10y + 14y + 35 = 0

⇒ 2y (2y + 5) + 7 (2y + 5) = 0

⇒ (2y + 5) (2y + 7) = 0

⇒ y = –5/2, –7/2

x ≥ y

⇒ 8x² + 20x + 6x + 15 = 0

⇒ 4x (2x + 5) + 3(2x + 5) = 0

⇒ (2x + 5) (4x + 3) = 0

⇒ x = – 5/2, –3/4

II. 4y² + 24y + 35 = 0

⇒ 4y² + 10y + 14y + 35 = 0

⇒ 2y (2y + 5) + 7 (2y + 5) = 0

⇒ (2y + 5) (2y + 7) = 0

⇒ y = –5/2, –7/2

x ≥ y

**Q7. I. 2x² + 9x + 9 = 0**

**II. 2y² + 17y + 36 = 0**

if x < y

if x ≤ y

relationship between x and y cannot be determined

if x ≥ y

if x > y

Solution:

I. 2x² + 9x + 9 = 0

⇒ 2x² + 6x + 3x + 9 = 0

⇒ (x + 3) (2x + 3) = 0

⇒ x = –3, –3/2

II. 2y² + 17y + 36 = 0

⇒ 2y² + 8y + 9y + 36 = 0

⇒ (y + 4) (2y + 9) = 0

y = – 4, –9/2

x > y

⇒ 2x² + 6x + 3x + 9 = 0

⇒ (x + 3) (2x + 3) = 0

⇒ x = –3, –3/2

II. 2y² + 17y + 36 = 0

⇒ 2y² + 8y + 9y + 36 = 0

⇒ (y + 4) (2y + 9) = 0

y = – 4, –9/2

x > y

**Q8. I. 5x² + 29x + 20 = 0**

**II. 25y² + 25y + 6 = 0**

if x < y

if x ≤ y

relationship between x and y cannot be determined

if x ≥ y

if x > y

Solution:

I. 5x² + 29 + 20 = 0

⇒ 5x² + 25x + 4x + 20 = 0

⇒ (x + 5) (5x + 4) = 0

⇒ x = –5, –4/5

II. 25y² + 25y + 6 = 0

⇒ 25y² + 15y + 10y + 6 = 0

⇒ (5y + 3) (5y + 2) = 0

⇒ y = – 3/5, –2/5

y > x

⇒ 5x² + 25x + 4x + 20 = 0

⇒ (x + 5) (5x + 4) = 0

⇒ x = –5, –4/5

II. 25y² + 25y + 6 = 0

⇒ 25y² + 15y + 10y + 6 = 0

⇒ (5y + 3) (5y + 2) = 0

⇒ y = – 3/5, –2/5

y > x

**Q9. I. 3x² – 16x + 21 = 0**

**II. 3y² – 28y + 65 = 0**

if x < y

if x ≤ y

relationship between x and y cannot be determined

if x ≥ y

if x > y

Solution:

I. 3x² – 16x + 21 = 0

⇒ 3x² – 9x – 7x + 21 = 0

⇒ (x – 3) (3x – 7) = 0

⇒ x = 3, 7/3

II. 3y² – 28y + 65 = 0

⇒ 3y² – 15y – 13y + 65 = 0

⇒ (y – 5) (3y – 13) = 0

⇒ y = 5, 13/3

y > x

⇒ 3x² – 9x – 7x + 21 = 0

⇒ (x – 3) (3x – 7) = 0

⇒ x = 3, 7/3

II. 3y² – 28y + 65 = 0

⇒ 3y² – 15y – 13y + 65 = 0

⇒ (y – 5) (3y – 13) = 0

⇒ y = 5, 13/3

y > x

**Q10. I. 8x²-26x+15=0**

**II. 2y²-17y+30=0**

if x < y

if x ≤ y

relationship between x and y cannot be determined

if x ≥ y

if x > y

**Q11. If three taps are open together, a tank is filled in 10 h. One of the taps can fill in 5 h and another in 10 h. At what rate does the 3rd pipe work?**

Waste pipe emptying the tank is 10 h

Waste pipe emptying the tank is 20 h

Waste pipe emptying the tank is 5 h

Fills the tank in 10 h

Fills the tank in 8 h

**Q12. Two pipes can fill a cistern in 14 hours and 16 hours respectively. The pipes are opened simultaneously and it is found that due to leakage in the bottom of the cistern, it takes 32 minutes extra for the cistern to be filled. When the cistern is full, in what time will the leak empty it?**

114 h

112 h

100 h

80 h

60 h

**Q13. The rate of filling pipes A and B is 50 m³/ min and 60 m³/ min respectively. They together can fill a tank which capacity is 3000 m³ in how much time?**

200/11 min

300/11 min

400/17 min

100/9 min

None of these

**Q14. There is a mixture of grapes Juice and alcohol in the ratio of 4 : 5 respectively. When 18 litre alcohol is added to this mixture the ratio of alcohol to grapes Juice become 9 : 4. Find the initial amount of grapes Juice.**

24 litre

22 litre

18 litre

20 litre

16 litre

**Q15. A boat goes upstream and downstream in 8 hours between two points A and B. The speed of boat in still water is 8 km/h. if AB = 24 km then speed of current is what percent of speed of boat in still water?**

60%

50%

40%

70%

30%

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