SBI Clerk Quantitative Aptitude Quiz: 1st June

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SBI-Clerk-Quantitative-Aptitude-Quiz: 1st June

Quantitative Aptitude Quiz For SBI PO/Clerk Prelims

Numerical Ability or Quantitative Aptitude Section has given heebie-jeebies to the aspirants when they appear for a banking examination. As the level of every other section is only getting complex and convoluted, there is no doubt that this section, too, makes your blood run cold. The questions asked in this section are calculative and very time-consuming. But once dealt with proper strategy, speed, and accuracy, this section can get you the maximum marks in the examination. Following is the Quantitative Aptitude quiz to help you practice with the best of latest pattern questions.



Q1. A trader bought two buffalo for Rs 19,500. He sold one at a loss of 20% and the other at a profit of 15%. If the selling price of each buffalo is the same, then their cost prices are respectively?
10,000 and 9,500
11,500 and 8,000
12,000 and 7,500
10,500 and 9,000
15,100 and 5,700
Solution:

Q2. A bath tub can be filled by the cold water pipe in 40 minutes and by the hot water pipe in 60 minutes. A person leaves the bathroom after turning on both pipes simultaneously and returns at the moment when the bath should be full. Finding, however, that the waste pipe has been open, he now closes it. In 12 minutes more the bath tub is full. In what time would the waste pipe empty it?
32 min
58 min
48 min
54 min
24 min
Solution:

Q3. 25 men can do a work in 20 days, when should 15 men leave the work, if the whole work is to be completed inafter they leave the work?
3 days
4 days
5 days
6 days
2 days
Solution:

Q4. Two equal sums of money are lent at the same times at 8% and 7% per annum simple interest. The former is recovered 6 months earlier than the latter and the amount in each case is Rs. 2560. The sums of money are lent out are :
Rs. 2000
Rs. 1500
Rs. 2500
Rs. 3000
Rs. 2800
Solution:

Q5. A person invested some amount at the rate of 12% simple interest and a certain amount at the rate of 10% simple interest. He received yearly interest of Rs. 130. But if he had interchanged the amounts invested, he would have received Rs. 4 more as interest. How much did he invest at 12% simple interest?
Rs. 700
Rs. 500
Rs. 800
Rs. 400
Rs. 200
Solution:

Directions (6-10): In each of the following questions two equations are given. You have to solve the equations and Give answer — 

Q6. I. 9x² – 36x + 35 = 0 
 II. 2y² – 15y – 17 = 0
if x < y
if x ≤ y
relationship between x and y cannot be determined
if x ≥ y
if x > y
Solution:
I. 9x² - 36x + 35 = 0
⇒ 9x² - 21x – 15x + 35 = 0
⇒ 3x (3x – 7) -5 (3x – 7) = 0
⇒ (3x- 7) (3x – 5) = 0
⇒ x=5/3,7/3
II. 2y² – 15y – 17 = 0
⇒ 2y² - 17y + 2y – 17 = 0
⇒ (y + 1) (2y – 17) = 0
⇒ y= -1, 17/2
No relation

Q7. I. 2x² – 7x + 3 = 0 
II. 2y² – 7y + 6 = 0
if x < y
if x ≤ y
relationship between x and y cannot be determined
if x ≥ y
if x > y
Solution:
I. 2x² - 7x + 3 = 0
⇒ 2x² - 6x – x +3 = 0
⇒ (x – 3) (2x – 1) = 0
⇒ x = 3, 1/2,
II. 2y² - 7y +6 = 0
⇒ 2y² - 4y – 3y + 6 =0
⇒ (y – 2) (2y – 3) = 0
⇒ y = 2, 3/2
No relation

Q8. I. 4x² + 16x + 15 = 0 
 II. 2y² + 3y + 1 = 0
if x < y
if x ≤ y
relationship between x and y cannot be determined
if x ≥ y
if x > y
Solution:
I. 4x² + 16x + 15 = 0
⇒ 4x² + 10x + 6x + 15 = 0
⇒ 2x (2x + 5) + 3 (2x + 5) = 0
⇒ (2x + 5) (2x + 3) = 0
⇒ x= -5/2, -3/2
II. 2y² + 3y + 1 = 0
⇒ 2y² + 2y + y + 1 = 0
⇒ (y + 1) (2y + 1) = 0
⇒ y = -1, -1/2
y > x

Q9. I. 9x² – 45x + 56 = 0 
 II. 4y² – 17y + 18 = 0
if x < y
if x ≤ y
relationship between x and y cannot be determined
if x ≥ y
if x > y
Solution:
I. 9x² - 45x + 56 = 0
⇒ 9x² - 24x – 21x + 56 = 0
⇒ 3x (3x – 8) – 7 (3x – 8) = 0
⇒ (3x – 8) (3x – 7) = 0
⇒ x = 8/3, 7/3
II. 4y² - 17y + 18 = 0
⇒ 4y² - 8y – 9y + 18 = 0
⇒ (y – 2) (4y – 9) = 0
⇒ y = 2, 9/4
x>y

Q10. I. 2x² + 11x + 14 = 0 
 II. 2y² + 15y + 28 = 0
if x < y
if x ≤ y
relationship between x and y cannot be determined
if x ≥ y
if x > y
Solution:
I. 2x² + 11x + 14 = 0
⇒ 2x² + 4x + 7x + 14= 0
⇒ (x + 2) (2x + 7) = 0
⇒ x = -2, -7/2
II. 2y² + 15y + 28= 0
⇒ 2y² + 8y + 7y + 28 = 0
⇒ (y + 4) (2y + 7) = 0
⇒ y = -4, -7/2
⇒ x ≥ y

Directions (11-15): Find the approximate value of the following questions. 

Q11. 21 + 4.9 × 7.9 + 9.88 =?
65
71
66
75
81
Solution:
? ≃ 21 + 5 × 8 + 10
 ≃ 71

Q12.
1/16
1/9
1/25
1/4
1/36
Solution:

Q13.
10
16
8
5
14
Solution:

Q14. 31.95² – 12.05² + ? = 900
15
40
50
75
20
Solution:
32² - 12² + ? ≃ 900
⇒ ? ≃ 900 - 880
⇒ ? ≃20

Q15. 1576 ÷ 45.02 + 23.99 × √255=?
340
420
380
460
360
Solution:

               




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