# Night Class: Quant Quiz

1. From a pack of 52 cards, 4 cards are drawn at random. What is the chance that they will be the four honours of the same suit?
1) 4/270725
2) 4/235425
3) 2/121225
4) 4/296324
5) None of these

2. The difference between the compound interest and the simple interest earned at the end of the second year on a sum of money at the rate of 10% p.a. is Rs 40. What is the sum (in Rs)?
1) 4000
2) 2000
3) 1000
5) None of these

3. From a group of 4 ladies and 7 gents a committee of 3 persons is to be formed in which Rajesh is always included. What is the probability that the committee includes two ladies?
1) 7/48
2) 2/15
3) 5/56
4) 11/49
5) None of these

4. The population of a town was 14500 in 2001 and 12500 in 1991. If increase in population remains the same for each year, find the population in 1996.
1) 1400
2) 13500
3) 15500
4) 14000
5) None of these.

5. A man borrows Rs 6000 at 3% compound interest. If he repays Rs 1200 at the end of each year, find the amount of loan outstanding at the beginning of the third year.
1) Rs 2578.25
2) Rs 3929.4
3) Rs 4015.8
4) Rs 4565
5) Rs 5000.25

Direction (6 – 10) :- Two equations (I) and (II) are given in each question. On the basis of these equations. You have to decide the relation between ‘x’ and ‘y’ and give answer :-

1) If x > y
2) If x < y
3) If x >= y
4) If x <= y
5) If x = y or no relation can be decided between ‘x’ and ‘y’.

6.

I. x = (-7)^2
II. y^2 – 46 y – 147 = 0

7.
I. 4x^2 – x – 3 = 0
II. 4y^2 – 16y + 15 = 0

8.
I. 2x^2 – 117x + 1701 = 0
II. y = Sqroot(992.25)

9.
I. 12x^2 – 41x + 35 = 0
II. 3y^2 – 17y – 28 = 0

10.
I. 4x – 3y = 16
II. 7x – 8y = 17

1. 1

The four honours are King, Queen, Ace and, Jack. So no. of ways of choosing those 4 honours of same suit = 4

No. of ways of choosing 4 cards out of 52 is

52C4 = (52 * 51 * 50 * 49)/(4 * 3 * 2) = 270752

Probability = 4/270725

2. 1

Sum = Diff (100/10)^2 = 40 × 100 = Rs 4000

3. 2

Rajesh is always included. So in a group of 4 ladies and 6 gents only 2 are chosen.
Total no. of ways = 10C2 = (10 * 9)/ 2 = 45

No. of ways of selection is = 4C2 = 4*3/2 = 6
Required probability = 6/45 = 2/15

4. 2

Reqd population = (14500 – 12500)/10 * 5 + 12500 = 13500

5. 2
Outstanding amount in the beginning of 2nd year = 6000 (103/100) – 1200 = Rs. 4980
Outstanding amount in the beginning of 3rd year = Rs. 4980 (103/100) – 1200 = Rs. 3929.4

6. 3

7. 2

8. 4

9. 5

10. 1