Reasoning Quizzes For IBPS RRB PO/Clerk Mains 2022- 4th October

Directions (1-5): Read the following arrangements of five-digits numbers carefully and answer the questions based on it. (Note: Consider the 1st, 2nd, 3rd, 4th and 5th digit of the number from the left side).

98766   84921   36728   43512   79632

Q1. If we arrange all the digits of the numbers in the ascending order within the number from the left end, then what will be the resultant sum of 5th digit of all the numbers after the rearrangement?
(a) 36
(b) 40
(c) 42
(d) 38
(e) None of these

Q2. If we arrange all the digits of the numbers in the ascending order within the number from the left end, then what will be the resultant product of the 3rd digit of first three numbers from the right end after the rearrangement?
(a) 106
(b) 108
(c) 112
(d) 144
(e) None of these

Q3. If one is subtracted from all the even digits of all the numbers then which number will be divisible by three after the rearrangement?
(a) 84921
(b) 36728
(c) Both (a) and (d)
(d) 98766
(e) 79632

Q4. If we interchange the first digit with fifth digit and second digit with fourth digit within the number then, how many numbers will be even numbers?
(a) One
(b) Two
(c) Three
(d) Four
(e) None of these

Q5. If one is subtracted from all the odd digits of all the numbers then which number will be second highest number after the rearrangement?
(a) 98766
(b) 84921
(c) 36728
(d) 43512
(e) 79632

Direction (6-10): Answer the following questions based on the arrangement given below.

J 7 K + E 8 # L Z @ M 3 $ P 4 2 C H & % Y 0 / 1 W < V U

Step I: The letters which are followed by a symbol but not preceded by a letter are arranged just before J in the reverse alphabetical series.
Step II: The symbols which are preceded by numbers are arranged such that the first symbol is arranged at the rightmost place, the second symbol to the leftmost place, the third symbol to the rightmost place and so on.
Step III: The numbers which are preceded by letters are arranged from right to left in the descending order at the end of the series.
Note: Step II is applied after step I and Step III is applied after step II.

Q6. How many such symbol(s) are there in step II which are followed and preceded by a letter?
(a) Two
(b) Three
(c) One
(d) None
(e) None of these

Q7. What is the sum of the numbers occurring between @ and < in step III?
(a) 9
(b) 5
(c) 3
(d) 1
(e) None of these

Q8. Which of the following element will be 5th to the left of 14th element from the left end in step I?
(a) M
(b) L
(c) @
(d) 8
(e) None of these

Q9. How many numbers is/are there which is/are followed by as well as preceded by a consonant in step III?
(a) Two
(b) Five
(c) One
(d) Six
(e) None of these

Q10. Which of the following pairs of elements will be there at the leftmost and rightmost places in step II?
(a) / and $
(b) / and 7
(c) K and U
(d) / and <
(e) None of these

Directions (11-15): In each of the questions given below, a group of letters is given followed by some combinations of number/symbol. You have to find out which of given combination correctly represents the group of letters based on the numbers/symbols codes and the conditions given below. If none of the given combinations represents the group of letters correctly, give (e) i.e. ‘None of these’ as the answer.

Condition for coding the group letters:
(i) If the first letter is vowel and last letter is consonant, the codes for the first and the last letter are to be interchanged.
(ii) If the first as well as the last letter is vowel, then both are to be coded by the code for the second last letter.
(iii) If the first as well as the last letter is consonant, then both are to be coded by the code for the first letter.
(iv)If the first letter is consonant and last letter is vowel, the codes for the first and the last letter are to be coded as ¥.

Q11. Find the code for ‘PACRWZ’.
(a) β2£6©β
(b) β2£©6β
(c) β2£6©%
(d) β£26©%
(e) None of these

Q12. Find the code for ‘IEXJFU’.
(a) !*< α!!
(b) !<* α!!
(c) #<* α!#
(d) $<* α!#
(e) None of these

Q13. Find the code for ‘ETQLP’.
(a) β17/<
(b) < β71/<
(c) β71/<
(d) <17/ β
(e) None of these

Q14. Find the code for ‘BPCRXA’.
(a) ¥β£6*¥
(b) ¥β6£*¥
(c) &β£6*2
(d) 2β£6*&
(e) None of these

Q15. Find the code for ‘ALQWE’.
(a) ©1/©©
(b) </1©2
(c) 2/1©<
(d) ©/1©©
(e) None of these

Solutions

S1. Ans. (b)
Sol. Given series – 98766 84921 36728 43512 79632
After operation – 66789 12489 23678 12345 23679
The sum of the 5th digit of all the numbers will be (9+9+ 8+5+9) = 40.

S2. Ans. (b)
Sol. Given series – 98766 84921 36728 43512 79632
After operation – 66789 12489 23678 12345 23679
The product of the 3rd digit of all the first three numbers from right end will be (6 x 3 x 6) = 108.

S3. Ans. (c)
Sol. Given series – 98766 84921 36728 43512 79632
After operation – 97755 73911 35717 33511 79531
Clearly 97755 and 73911 are divisible by 3. 97755 represent 98766, while 73911 represent 84921.

S4. Ans. (b)
Sol. Given series – 98766 84921 36728 43512 79632
After operation – 66789 12948 82763 21534 23697
Hence, there will be two even numbers.

S5. Ans. (b)
Sol. Given series – 98766 84921 36728 43512 79632
After operation – 88666 84820 26628 42402 68622
Hence, second highest number will be 84820 (84921).

Solution (6-10):
Sol. Given series – J 7 K + E 8 # L Z @ M 3 $ P 4 2 C H & % Y 0 / 1 W < V U
Step I: W K J 7 + E 8 # L Z @ M 3 $ P 4 2 C H & % Y 0 / 1 < V U
Step II: / # W K J 7 E 8 L Z @ M 3 P 4 2 C H & % Y 0 1 V U + $ <
Step III: / # W K J E L Z @ M P 2 C H & % Y 1 V U + $ < 0 3 4 7 8

S6. Ans.(c)
S7. Ans.(c)
S8. Ans.(b)
S9. Ans.(a)
S10. Ans.(d)

S11. Ans. (a)
Sol. Condition (iii) is applied.

S12. Ans. (b)
Sol. Condition (ii) is applied.

S13. Ans. (c)
Sol. Condition (i) is applied.

S14. Ans. (a)
Sol. Condition (iv) is applied.

S15. Ans. (d)
Sol. Condition (ii) is applied.