SBI PO 2019 Reasoning Quiz: 4th May |

Dear Aspirants,

Reasoning Questions for SBI PO Prelims 2019:

R easoning Ability is an onerous section. With the increasing complexity of questions, it becomes hard for one to give it the cold shoulder. The only way to make the grade in this particular section in the forthcoming banking exams. And, to let you practice with the best of the latest pattern questions, here is the Adda247 Reasoning Quiz based on the exact same pattern of questions that are being asked in the exams.

Directions (1-5): Study the following information to answer the given question:

Seven persons A, B, C, D, E, F and G have exam on seven different days of the same week starting from Sunday to Saturday.
More than three person has exam before E. G has exam before D and only two people has exam between them. C has exam immediate before A and none of them has exam on Monday. B has exam immediate before F. The number of persons has exam between F and G is less than number of persons has exam between D and A.

Q1. Who has exam on Monday?

none of these

Solution:

SBI PO 2019 Reasoning Quiz: 4th May |_3.1

Q2. Who has exam just before F?

none of these

Solution:

Q3. How many persons have exam in between B and C?

none of these

Solution:

Q4. Who has exam on Saturday?

none of these

Solution:

Q5. Who has exam just after E?

none of these

Solution:

Directions (6–10): Following questions are based on the five three-digit numbers given below:

369 717 922 625 434

Q6. If all the numbers are arranged in ascending order from left to right, which of the following will be the product of the first and last digits of the number which is in the middle in the new arrangements?

Solution:

exactly middle- 625 after arranging in the ascending order
Product of the first and the last digit of 625= 6x5= 30

Q7. If the positions of the first and third digits of each of the number interchange, what will be the sum of all the digits of the second lowest number?

Solution:

434 is the second lowest number after arranging the first and last digit of each of the numbers
Sum of all digits= 4 + 3 + 4 = 11

Q8. If one is subtracted from each odd digit and two is added to each even digit of each of the numbers, what will be the difference between the third digit and the first digit of the lowest number?

Zero

Solution:

288 is the lowest one
Required difference = 8 – 2 = 6

Q9. What will be the resultant if the first digit of the highest number is divided by the third digit of the lowest number?

0.5

2.2

None of these

Solution:

first digit of the highest number = 9
Third digit of the lowest number = 9
So 9/9 = 1

Q10. If all the digits in each of the numbers are arranged in descending order within the number from left to right, which of the following will be the second highest number in the new arrangement

369

717

922

625

None of these

Solution:

922 is the second highest number after arranging the digits in descending order.

Directions (11-15): In the following question, if all the statements are true. Find the true conclusion among given three conclusion and then further give your answers.

Q11. Statements: X ≥ A, X = L, Y<A
Conclusions: I. A<L
II. L ≤ Y
III. Y>X

Only I is true

Only I and II are true

Only I and III are true

Only II and III are true

None is true

Solution:

(I) A < L (False) (II) L ≤ Y (False) (III) Y > X (False)

Q12.Statements: E = H, T > C, E ≤ T
Conclusions: I. C < E
II. T ≥ H
III. C < H

Only I is true

Only III is true

I and III are true

II and III are true

None of these

Solution:

(I) C < E (False) (II) T ≥ H (True) (III) C < H (False)

Q13.Statements: G < T, G < R, Q ≤ T
Conclusions: I. R > T
II. R ≤ T
III. Q < G

Only I is true

Either I or II is true

Either II or III is true

None is true

Only III is true

Solution:

(I) R > T (False) (II) R ≤ T (False) (III) Q < G (False)

Q14. Statements: M < R, A ≤ J, R > A
Conclusions: I. J > R
II. M < A
III. M < J

None is true

Only I is true

Only II is true

II and III are true

I and II are true

Solution:

(I) J > R (False) (II) M < A (False) (III) M < J (False)

Q15.Statements: N = K, J ≥ M, M < N
Conclusions: I. J > N
II. J > K
III. K > M

Only I is true

Only II is true

I and II are true

Only III is true

None of these

Solution:

(I) J > N (False) (II) J > K (False) (III) K > M (True)

You may also like to Read:

!!Check the Video Course of Reasoning for All Exams

SBI PO 2019 Reasoning Quiz: 4th May |_8.1

SBI PO 2019 Reasoning Quiz: 4th May |_9.1

SBI PO 2019 Reasoning Quiz: 4th May

Reasoning Questions for SBI PO Prelims 2019:

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