# Quantitative Aptitude Quiz for IBPS Clerk Prelims: 20th October 2018

**Dear Students,**

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**Quantitative Aptitude Quiz for IBPS Clerk **

**Section has given heebie-jeebies to the aspirants when they appear for a banking examination. As the level of every other section is only getting complex and convoluted, there is no doubt that this section, too, makes your blood run cold. The questions asked in this section are calculative and very time-consuming. But once dealt with proper strategy, speed, and accuracy, this section can get you the**

*Numerical Ability or Quantitative Aptitude***maximum marks in the examination.**Following is the Quantitative Aptitude quiz to help you practice with the best of latest pattern questions.

**Q1. A dealer allowed a discount of 25% on the marked price of Rs 12000 on an article and incurred a loss of 10%. What discount should he allow on the marked price so that he gains Rs 440 on the article?**

11%

13%

19%

15%

17%

**Q2. Rana is twice as good a workman as Sunder and Finishes a piece of work in 3 hours. In how many hours they together could finish that piece of work?**

**Q3. A sum of Rs 2200 is invested at two different rates of interest. The difference between the simple interests got after 4 years is Rs 202.40 at these two rates, what is the difference between the rates of interest?**

3.3%

2.3%

3.5%

2.5%

4.3%

**Q4. While selling a watch, a shopkeeper gives a discount of 15%. If he gives a discount of 20%, he earns Rs 51 less as profit. What is the original marked price of the watch?**

Rs 920

Rs 985

Rs 1125

Rs 1020

Rs 1220

**Q5. In how many different ways can the letters of the word ‘THERAPY’ be arranged so that the vowels never come together?**

720

1440

5040

3600

4800

Solution:

Required arrangements

= 7! – 6! × 2!

= 5 × 6!

= 3600

= 7! – 6! × 2!

= 5 × 6!

= 3600

**Directions (6-10): Study the following table carefully to answer the questions that follows. Table shows number of students studying in different colleges over the years.**

**Q6. Number of students in college C in year 2007 is approximately what % of the total number of students in that college from all the years together?**

17%

20%

15%

28%

32%

**Q7. What is the difference between the average number of students from all the colleges together in year 2006 and 2008?**

12

10

14

16

20

**Q8. What is the average number of students in all the colleges together in the year 2007?**

2628

2640

2602

2614

2460

**Q9. What is the respective ratio of total number of students in college D in the years 2008, and 2010 together to the total number of students in college A from the same years?**

465 : 343

508 : 495

510 : 496

504 : 485

405 : 584

Solution:

Total students in 2008 and 2010 together in college D = 2540 + 2540 = 5080

Total students in 2008 and 2010 in college A = 2550 + 2400 = 4950

So, the ratio = 5080: 4950 = 508: 495

Total students in 2008 and 2010 in college A = 2550 + 2400 = 4950

So, the ratio = 5080: 4950 = 508: 495

**Q10. If average age of students in college B in 2006 is 18 years and average age of students in college C is 16 years in the same year, then find the difference between sum of ages of all students in these two colleges in year 2006 (in numerical value).**

6540

6250

6520

6450

6640

Solution:

Required difference = 2540 × 18 ̶ 2450 × 16

= 6520

= 6520

**Directions (11-15): In each of the following questions two equations are given. You have to solve the equations and Give answer —**

**Q11. I. 7x² + 13x + 6 = 0**

**II. 4y² + 7y – 11 = 0**

if x < y

if x ≤ y

relationship between x and y cannot be determined

if x ≥ y

if x > y

**Q12. I. x² + 46x + 520 = 0**

**II. 3y² – 17y + 24 = 0**

if x < y

if x ≤ y

relationship between x and y cannot be determined

if x ≥ y

if x > y

**Q13. I. 5y² – 13y – 18 = 0**

**II. 11x² + 23x + 12 = 0**

if x < y

if x ≤ y

relationship between x and y cannot be determined

if x ≥ y

if x > y

Solution:

b

**Q14. I. x⁴ – 13x² + 36 = 0**

**II. y² + 4y – 45 = 0**

if x < y

if x ≤ y

relationship between x and y cannot be determined

if x ≥ y

if x > y

**Q15. I. 6y² – 14y + 8 = 0**

**II. 4x² – 15x + 14 = 0**

if x < y

if x ≤ y

relationship between x and y cannot be determined

if x ≥ y

if x > y

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