Quantitative Aptitude Quiz For IBPS Clerk Mains: 6th January 2019

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Quantitative Aptitude Quiz For IBPS Clerk Mains: 6th January 2019



Quantitative Aptitude Quiz For IBPS Clerk Main

If talked about banking exams, Quant Section is considered to be one of the most difficult sections and so, gives heebie-jeebies to many. The questions asked in this section are calculative and very time-consuming and if you do not practice it well, it can make your blood run cold during the exam. The IBPS Clerk Mains Exam is scheduled to be held on the 20th of January 2019. Adda247 is here with “Practice Marathon for Clerk Mains 2018” with practice questions on all the topics that are likely to be asked in the exam. Today is Day 10 of IBPS Clerk Mains Practice Marathon, attempt the quiz and win this marathon against lakhs of IBPS Clerk Candidates.

WATCH VIDEO SOLUTIONS HERE

Directions (1-5): In the following questions two quantities are given for each question. Compare the numeric value of both the quantities and answers accordingly. 

Q1. ‘A’, ‘B’ and ‘C’ together can complete a work in 48 days if they work alternatively. ‘A’ is 25% more efficient than ‘B’ who isless efficient than ‘C’. Quantity I: Difference between days taken by ‘A’ alone and ‘C’ alone to complete the work. Quantity II: Days in which ‘A’, ‘B’ and ‘C’ together can complete half of the work.

Quantity I > Quantity II
Quantity I < Quantity II
Quantity I ≥ Quantity II
Quantity I ≤ Quantity II
Quantity I = Quantity II or No relation
Solution:

Q2. Neeraj invested Rs. X in two different schemes ‘A’ and ‘B’ equally. Scheme A offers 10% p.a. at S.I and scheme B offers 20% p.a. at C.I. After 2 years he got total Rs.2560 interest from both the schemes. Quantity I: Value of ‘X’ Quantity II: Rs. 7200

Quantity I ≥ Quantity II
Quantity I = Quantity II or No relation
Quantity I > Quantity II
Quantity I ≤ Quantity II
Quantity I < Quantity II
Solution:

Q3. Three partners invested capital in the ratio 2 : 7 : 9. The time period for which each of them invested was in the ratio of the reciprocals of the amount invested.. Quantity I: Profit share of the partner who brought in the highest capital if the profit is Rs. 1080 Quantity II: Profit share of the partner who brought in the lowest capital if the profit is Rs. 1080

Quantity I > Quantity II
Quantity I ≥ Quantity II
Quantity I < Quantity II
Quantity I = Quantity II or No relation
Quantity I ≤ Quantity II
Solution:

Q4. X started from a point A towards point B. After 2 hours. Y started from B towards A. By the time X travelled one-fifth of the total distance, Y had also travelled the same. Y’s speed is thrice of that of X’s speed. Quantity I: Difference in time (in hours) taken by X and Y to reach their respective destinations. Quantity II: 12 hours

Quantity I = Quantity II or No relation
Quantity I ≤ Quantity II
Quantity I ≥ Quantity II
Quantity I < Quantity II
Quantity I > Quantity II
Solution:

Q5. A vessel contains 2.5 litres of water and 10 litres of milk. 20% of the contents of the vessel are removed. To the remaining contents, x litres of water is added to reverse the ratio of water and milk. Then y litres of milk is added again to reverse the ratio of water and milk. Quantity I: Value of ‘y’ Quantity II: Value of ‘x’

Quantity I = Quantity II or No relation
Quantity I ≤ Quantity II
Quantity I ≥ Quantity II
Quantity I < Quantity II
Quantity I > Quantity II
Solution:

Q6. A shopkeeper buys 144 items at 90 paise each. On the way 20 items are broken. He sells the remainder at Rs. 1.20 each. His gain per cent correct to one place of decimal is

13.8%
14.6%
14.8%
15.8%
None of these
Solution:

Q7. The ratio of the number of boys and girls in a school is 2 : 3. If 25% of the boys and 30% of the girls are scholarship holders, the percentage of the school students who are not scholarship holders is

72%
36%
54%
60%
None of these
Solution:

Q8. A boat goes 24 km upstream and 28 km downstream in 6 hours. It goes 30 km upstream and 21 km downstream in 6 hours and 30 minutes. The speed of the boat in still water is

8 km/hr
9 km/hr
12 km/hr
10 km/hr
None of these
Solution:

Q9. A takes three times as long as B and C together to do a job. B takes four times as long as A and C together to do the work. If all the three, working together can complete the job in 24 days, then the number of days, A alone will take to finish the job is

100
96
95
90
None of these
Solution:

Q10. 20 litres of a mixture contains 20% alcohol and the rest water. If 4 litres of water be mixed in it, the percentage of alcohol in the new mixture will be

Solution:

Directions (11-15): In these questions, two equations numbered I and II are given. You have to solve both the equations and give answer: 

Q11. I. x² – 9x + 18 = 0
II. 5y² – 22y + 24 = 0

if x < y
if x > y
if x ≤ y
if x ≥ y
if relationship between x and y cannot be determined
Solution:

I. x² – 9x + 18 = 0
x² – 6x – 3x + 18 = 0
x (x – 6) –3 (x -6) = 0
(x – 3) (x – 6) = 0
x= 3, 6
II. 5y² – 22y + 24 = 0
5y² – 10y – 12y + 24 = 0
5y (y- 2) –12 (y – 2) = 0
(y – 2) (5y – 12) = 0
y=2, 12/5
∴ x > y

Q12. I. 6x² + 11x + 5 = 0 
II. 2y² + 5y + 3 = 0

 if x < y
 if x > y
 if x ≤ y
 if x ≥ y
 if relationship between x and y cannot be determined
Solution:

I. 6x² + 11x + 5 = 0
6x² + 6x + 5x + 5 = 0
6x (x + 1) + 5 (x + 1) = 0
(x+ 1) (6x +5) = 0
x = -1,-5/6
II. 2y² + 5y + 3 = 0
2y² + 2y + 3y + 3 = 0
2y (y+ 1) + 3 (y+ 1) = 0
(y+ 1) (2y + 3) = 0
y= -1,-3/2
∴x≥y

Q13. I. x² + 10x + 24 = 0 
II. y² – √625=0

 if x < y
 if x > y
 if x ≤ y
 if x ≥ y
 if relationship between x and y cannot be determined
Solution:

I. x² + 10x + 24 = 0
x² +6x + 4x + 24 = 0
x (x + 6) +4 (x+ 6) = 0
(x + 4) (x + 6) = 0
x = –4, –6
II. y² – √625=0
y²=√625
y²=25;
y= ±5
∴ Relationship between x and y cannot be determined

Q14. I. 10x² + 11x + 1 = 0 
II. 15y² + 8y + 1 = 0

 if x < y
 if x > y
 if x ≤ y
 if x ≥ y
 if relationship between x and y cannot be determined
Solution:

I. 10x² +11x + 1= 0
10x² + 10x+ x+ 1 = 0
10x (x + 1) + 1 (x + 1) = 0
(x + 1) (10x + 1) = 0
x= -1,-1/10
II. 15y² + 8y + 1 = 0
15y² +5y + 3y + 1 = 0
5y (3y + 1) + 1 (3y+ 1) = 0
(3y + 1) (5y + 1) = 0
 y=-1/3,-1/5
∴ Relationship between x and y cannot be determined

Q15. I.15x² – 11x + 2 = 0 
II. 10y² – 9y + 2 = 0

 if x < y
 if x > y
 if x ≤ y
 if x ≥ y
 if relationship between x and y cannot be determined
Solution:

I. 15x² – 11x + 2 = 0
15x² – 5x – 6x + 2 = 0
5x (3x – 1) – 2 (3x – 1) = 0
(3x – 1) (5x – 2) = 0
x=1/3,2/5
II. 10y² – 9y + 2 = 0
10y² – 5y – 4y + 2 = 0
5y (2y – 1) –2 (2y – 1) = 0
(2y – 1) (5y - 2) = 0
y = 1/2,2/5
∴ x ≤ y

               






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