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# Quantitative Aptitude Quiz 17 May- Daily Quantitative Aptitude Quiz for SBI PO Prelims 2020

Adda 247 will provide you daily Quantitative Aptitude Mock of “SBI PO Prelims. In today’s Quantitative Aptitude Mock, we have Quantity Based. Stay tuned with bankersadda to get  Quantitative Aptitude Mock and boost your preparation for the upcoming bank exam. You can also prepare with the study plan for SBI PO available on the bankersadda website.

Directions (1-5): In the following questions two quantities are given for each question.

Compare the numeric value of both the quantities and answers accordingly.

Q1.Quantity I: x² – 6x + 8 = 0

Quantity II: y² + 2y – 8 = 0

(a) Quantity I > Quantity II

(b) Quantity I < Quantity II

(c) Quantity I ≥ Quantity II

(d) Quantity I ≤ Quantity II

(e) Quantity I = Quantity II or No relation

Q2. A man invested Rs. 8000 in scheme A for 4 years at Simple Interest which offers interest rate of 20% p.a and Rs. 7200 in scheme B for 3 years which offers 25% p.a at Simple interest.

Quantity I: Interest earned from scheme A

Quantity II Sum of interest earned from scheme ‘B’ and Rs. 640

Q3. Sum of speed of boat in downstream and in upstream is 24 km/hr while speed of boat in still water is 200% more than speed of stream.

Quantity I: Time taken to cover 96km downstream

Quantity II: Time taken to cover 60km upstream

(a) Quantity I > Quantity II

(b) Quantity I ≤ Quantity II

(c) Quantity I ≥ Quantity II

(d) Quantity I = Quantity II or No relation

(e) Quantity I < Quantity II

Q4.     Quantity I : Find the principal if the compound interest is charged on principal at the rate of     per annum  for two years and the sum becomes Rs 245.

Quantity II : A sum of Rs 500 amounts to Rs 620 in 4 yrs at simple interest. What will Rs 150  amount to if the rate of interest is same and time period is  yrs.

(a) Quantity I > Quantity II

(b) Quantity II > Quantity I

(c) Quantity I >= Quantity II

(d) Quantity II >= Quantity I

(e) Quantity I = Quantity II or relation can’t be established

Q5.Quantity I: x² – 5x + 4 = 0

Quantity II: y² + 3y + 2 = 0

(a) Quantity I > Quantity II

(b) Quantity I < Quantity II

(c) Quantity I ≥ Quantity II

(d) Quantity I ≤ Quantity II

(e) Quantity I = Quantity II or No relation

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