# Quantitative Aptitude Quiz for IBPS Clerk Prelims: 7th December 2018

**Dear Aspirants,**

Numerical Ability or Quantitative Aptitude Section has given heebie-jeebies to the aspirants when they appear for a banking examination. As the level of every other section is only getting complex and convoluted, there is no doubt that this section, too, makes your blood run cold. The questions asked in this section are calculative and very time-consuming. But once dealt with proper strategy, speed, and accuracy, this section can get you the maximum marks in the examination. Following is the Quantitative Aptitude quiz to help you practice with the best of latest pattern questions.

**Directions: (1-5) Study the following bar graph carefully and answer the given question. The following bar graph shows the no. of students in different branches of 5 engineering college in 2016.**

**Q1. What is the ratio of IT students from college C and D together to mechanical students from college B and E together in 2016.**

23 : 14

20 : 21

14 : 23

21 : 20

7 : 11

Solution:

Required ratio =(80+60)/(90+140)=140/230=14 :23

**Q2. If 25% IT students in college A and C in 2017 changed branch from IT to mechanical, then IT students are how much percent of mechanical student in 2017 in college A and C together.**

**Q3. Find the difference of Average students of all branches of college A and College C**

17

8

12

10

23

Solution:

Average of students of all branches of college A = (60+100+150)/3=310/3

Average of students of all branches of college C = (140+80+120)/3=340/3

Required difference =340/3-310/3 =30/3=10

Average of students of all branches of college C = (140+80+120)/3=340/3

Required difference =340/3-310/3 =30/3=10

**Q4. If ratio of boy to girl student in each college is 7 : 3, 3 : 2 and 4 : 1 for IT, civil and mechanical respectively, then find the difference of total female student from college B to total male students of college E**

125

143

145

155

118

Solution:

Female student from college B =120×3/10+50×2/5+90×1/5

= 36 + 30 + 18 = 74 Male students from college E =90×7/10+140×4/5+70×3/5

= 63 + 112 + 42 = 217 Required difference = 217 – 74 = 143

= 36 + 30 + 18 = 74 Male students from college E =90×7/10+140×4/5+70×3/5

= 63 + 112 + 42 = 217 Required difference = 217 – 74 = 143

**Q5. Total civil students are how much percent less than total IT students in these five colleges**

13 ⅓%

16½%

12 ⅔%

18%

15 ⅗%

Solution:

Total IT students = 100 + 120 + 80 + 60 + 90 = 450

Total civil students = 60 + 50 + 140 + 70 + 70 = 390

Required percent =(450-390)/450×100 =13⅓%

Total civil students = 60 + 50 + 140 + 70 + 70 = 390

Required percent =(450-390)/450×100 =13⅓%

**Directions (6-10): What will come in place of question mark (?) in the following questions?**

**Q6. 112, 225, 345, 479, 634, ?**

803

817

825

793

786

**Q7. 516, 514, 502, 472, 416, ?**

298

334

371

326

352

**Q8. 12, 11, 18, 45, 164, ?**

825

845

795

784

640

Solution:

12 × 1 – 1² = 11

11 × 2 – 2² = 18

18 × 3 – 3² = 45

45 × 4 – 4² = 164

164 × 5 – 5² = 795

11 × 2 – 2² = 18

18 × 3 – 3² = 45

45 × 4 – 4² = 164

164 × 5 – 5² = 795

**Q9. 28, 15, 17, 28.5, 61, ?**

157.5

185.5

172

158

155.5

Solution:

28 × 0.5 + 1 = 15

15 × 1 + 2 = 17

17 × 1.5 + 3= 28.5

28.5 × 2 + 4 = 61

61 × 2.5 + 5 = 157.5

15 × 1 + 2 = 17

17 × 1.5 + 3= 28.5

28.5 × 2 + 4 = 61

61 × 2.5 + 5 = 157.5

**Q10. 71, 91, 117, 155, 217, ?**

292

338

286

327

317

**Directions (11-15): What approximate value will come in place of question mark (?) in following questions?**

**Q11. 5144.98 + 3449.95 – 4559.98 =?**

4035

4050

4135

5200

4345

Solution:

? = 5145+3450-4560 ? = 4035

**Q12. 49.98% of ? – 2/3 of 243.02 = 49.94**

436

424

450

474

502

Solution:

50% of ?-2/3 of 243=50

?×50/100=50+162 ⇒

?=424

?×50/100=50+162 ⇒

?=424

**Q13. 1.007 + 2.0008 + 30.09 ÷ 10 – 5.99 = ?**

1

12

3

2

0

Solution:

? = 1+2+3-6

? = 6 – 6 = 0

? = 6 – 6 = 0

**Q14. 44.95% of 599.98 + 34.98% of 299.98 = ?**

295

425

395

375

430

Solution:

?=45/100×600+35/100×300

? = 270+105 =375

? = 270+105 =375

**Q15. √441.13÷2.96+√(?)=46.98**

1900

1760

1650

1700

1600

Solution:

√441÷3+√(?)=47

√(?)=47-21/3=40

⇒ ? = 1600

√(?)=47-21/3=40

⇒ ? = 1600

## No comments