**Dear students,**

**Q1. In what ratio must a grocer mix two varieties of pulses costing Rs. 15 and Rs. 20 per kg respectively so as to get a mixture worth Rs. 16.50 per kg? **

**Q2. The cost of Type 1 rice is Rs. 15 per kg and Type 2 rice is Rs. 20 per kg. If both Type 1 and Type 2 are mixed in the ratio of 2 : 3, then the price per kg of the mixed variety of rice is **

**Q3. Two vessels A and B contain milk and water mixed in the ratio 8 : 5 and 5 : 2 respectively. The ratio in which these two mixtures be mixed to get a new mixture containing 693/13% milk, is **

**Q4. The sum of the ages of Jayant, Prem and Paras is 93 years. Ten years ago, the ratio of their ages was 2 : 3 : 4. What is the present age of Paras ? **

**Q5. The ratio of a manâ€™s age and his sonâ€™s age is 7 : 3 and the product of their ages is 756. The ratio of their ages after 6 years will be **

**Directions (6-10): The pie-chart shown below gives the distribution of land (in degrees) in a village under various food crops. Study the pie-chart carefully and answer the questions that follow:
Distribution of areas (in acres) under various food crops **

**Q6. Which combination of three crops contribute to 50% of the total area under the food crops ? **

**Q7. If the total area under jowar was 1.5 million acres, then what was the area (in million acres) under rice ? **

**Q8. If total production of wheat is 6 times that of barley, then what is the ratio between the yield per acre of wheat and barley ? **

**Q9. If the yield per acre of rice was 50% more than that of barley, then total production of barley is what percent of that of rice? **

**Q10. If the total area goes up by 5%, and the area under wheat production goes up by 12%, then what will be the angle for wheat in the new pie-chart? **

**Directions (11-15): In each of these questions, two equations are given. You have to solve both the equations and give answer **

**Q11. (i) 4xÂ² + 14x â€“ 18 = 0 **

** (ii) yÂ² + 12y + 35 = 0
**

**Q12. (i) 4xÂ² + 17x - 42 = 0 **

** (ii) yÂ² + 21y + 90 = 0
**

**Q13. (i) xÂ² - 24x + 128 = 0 **

** (ii) yÂ² - 34y + 288 = 0
**

**Q14. (i) 8xÂ² â€“ 30x + 28 = 0 **

** (ii) 5yÂ² â€“ 8y + 3 = 0
**

**Q15. (i) xÂ² â€“ 31x + 184 = 0 **

** (ii) yÂ² â€“ 47y + 552 = 0
**

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