**Directions (1-5):** In the given questions, two quantities are given, one as** ‘Quantity I’** and another as** ‘Quantity II’**. You have to determine relationship between two quantities and choose the appropriate option:

**Q1. A man invested in the ratio of 8 : 11 in two schemes ‘A’ & B. Scheme ‘A’ offered compound interest, while scheme ‘B’ offered simple interest. **

**Quantity I –** Amount invested in scheme ‘B’.

If rate of interest offered in scheme ‘A’ & ‘B’ was 20% p.a. and 16% p.a. respectively and the man got Rs. 3520 as total interest from both schemes after two years.

**Quantity II –** Amount invested by man in scheme ‘A’.

If rate of interest offered in scheme ‘A’ & ‘B’ was 10% p.a. and 20% p.a. respectively and man got Rs. 1870 more as interest from scheme ‘B’ as compared to A after two years. (a) Quantity I > Quantity II

(b) Quantity I < Quantity II

(c) Quantity I ≥ Quantity II

(d) Quantity I ≤ Quantity II

(e) Quantity I = Quantity II or no relation

**Q2. A bag contains 9 yellow balls, Y green balls and 7 red balls, if one ball is drawn at random from bag probability of it being green is 5/21 . **

**Quantity I –** The probability that at least one of the fruits is apple when, two fruits are taken out from bucket P without replacement.

Bucket ‘P’ contains 2Y apple, 3(Y – 2) banana & 1.5(Y – 1) orange.

**Quantity II –** The probability that both of the dice are of same color, when two dice are taken out from bucket Q without replacement.

Bag ‘Q’ contains 4 red dice, 3.5(Y – 3) green dice and 2Y yellow dice.

(a) Quantity I > Quantity II

(b) Quantity I < Quantity II

(c) Quantity I ≥ Quantity II

(d) Quantity I ≤ Quantity II

(e) Quantity I = Quantity II or no relation

**Q3. Two vessel A & B contains mixture of milk & water in the quantity of (X + 54) l and (X + 84) l respectively. The ratio of milk & water in vessel A and vessel B is 3 : 2 and 2 : 1 respectively. **

**Quantity I –** Quantity of milk in vessel B.

If 60% mixture from vessel A and 66 ⅔ % mixture from vessel B taken out, then the remaining mixture in both vessels is equal.

**Quantity II –** 144 l

(a) Quantity I > Quantity II

(b) Quantity I < Quantity II

(c) Quantity I ≥ Quantity II

(d) Quantity I ≤ Quantity II

(e) Quantity I = Quantity II or no relation

**Q4. Quantity I –** Breadth of rectangle.

Sum of circumference of a circle and perimeter of a rectangle is 154 cm. and area of the circle is 346.5 cm². Length of the rectangle is 166 ⅔% more than radius of circle.

**Quantity II –** Side of square.

Circumference of a circle is 132 cm and area of circle is 1130 cm2 more than area of square.

(a) Quantity I > Quantity II

(b) Quantity I < Quantity II

(c) Quantity I ≥ Quantity II

(d) Quantity I ≤ Quantity II

(e) Quantity I = Quantity II or no relation

**Q5. Quantity I –** Three times of amount invested by Gopal.

Arun and Gopal entered into a business with the capital of Rs. (P + 1200) and Rs. (P + 1500) respectively. After 8 months from starting, Arun withdrew half of his investment and Gopal doubled his investment. At the end of year Arun got Rs. 4250 out of total profit of Rs. 11250.

**Quantity II –** Profit share of C.

A and B started a business with initial investment of Rs. 27000 and Rs. 36000 respectively. After 4 months A withdraw Rs. 5000, B added Rs. 6000 and C joined with Rs. 35000. At the end of an year total profit of Rs. 130500 is obtained.

(a) Quantity I > Quantity II

(b) Quantity I < Quantity II

(c) Quantity I ≥ Quantity II

(d) Quantity I ≤ Quantity II

(e) Quantity I = Quantity II or no relation

**Directions (6-10): Line graph given below shows the distance between Delhi to five different cities in kilometer and Table given below shows the speed of five different cars in km/hr **

**NOTE: –** Some data is missing you have to calculate according to question.

**Q6. Time taken by car ‘P’ to travel from city ‘E’ to Delhi and then Delhi to city ‘B’, is equal to the time taken by car ‘R’ to travel from Delhi to city ‘A’ and then city ‘A’ to city ‘B’. Find the distance between city ‘A’ and city ‘B’. **

(a) 5650 km

(b) 5750 km

(c) 5450 km

(d) 5550 km

(e) 5320 km

**Q7. Find the approximate time car ‘T’ takes to reach city ‘E’ from city ‘A’ if city ‘A’ and city ‘E’ is north and east direction of Delhi respectively. **

(a) 24 hours

(b) 27 hours

(c) 20 hours

(d) 36 hours

(e) 42 hours

**Q8. Car Q and Car S start from Delhi for city B and city C respectively and they reached in equal time. If Car Q and Car S starts from city B and city D respectively at same time and move towards each other, then time taken by car Q to cross car S is what percent of the time taken by car Q to reach city B from Delhi. Distance between city B and city D is 1500 km. **

(a) 25%

(b) 20%

(c) 30%

(d) 40%

(e) 50%

**Q9. A thief runs in a car S from Delhi to city E and after 6 hours of running, a policeman started to catch him in a car R. Due to this, thief increases the speed of his car by 100%. By this, the policeman is able to catch him at ⅗th of the distance of city E from Delhi. Find the initial speed of car ‘S’. **

(a) 15 km/hr

(b) 27 km/hr

(c) 20 km/hr

(d) 25 km/hr

(e) 40 km/hr

**Q10. Car P and Car Q start from Delhi for city A. Car Q first reaches at city A and meets car P in between the way, 200 km from city ‘A’. Find after how much time they will meet second time after first time meeting if they continue their to and fro motion. **

(a) 24 hours

(b) 15 hours

(c) 16 hours

(d) 25 hours

(e) 20 hours

**Solutions**