**SBI PO Quantitative Aptitude Quiz**

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**SBI PO Mains**Study plan as there is left not enough time to deal in details. The questions asked in the quantitative aptitude section are calculative and very time-consuming. But once dealt with proper strategy, speed, and accuracy, this section can get you the maximum marks in the examination. Following is the Quantitative Aptitude quiz to help you practice with the best of latest pattern questions**For Queries related to Adda247 Ultimate for IBPS RRB 2019 Prelims, Click Here or mail us at ultimate@adda247.com**

**Directions (1-5): Pie-chart given bellows shows the income of five different persons and bar graph shows the percentage distribution of their income on different things. Study the question carefully and answer them.**

**Q1. Who among the following spend maximum amount on food?**

D

E

B

C

A

Solution:

**Q2. Amount spend by ‘E’ on furniture is what percent more than amount spend by ‘D’ on Transportation?**

70%

45%

80%

65%

60%

**Q3. Find the average amount spend by A, B and C on furniture?**

4622

4626

4262

4266

4662

**Q4. ‘D’ buy only three type of food X, Y and Z and amount spend on buying X, Y and Z is in the ratio 5 : 7 : 8. What is the difference between amount spend on buying Z type food to amount spend on buying X type food.**

2520

1680

8400

1260

2100

**Q5. Find the ratio of amount spend by ‘A’ and ‘B’ together on food to the amount spend by ‘C’ and ‘D’ together on furniture?**

295 : 277

277 : 295

311 : 301

301 : 305

301 : 310

**Q6. Quantity I: Percentage mark-up above cost price of an article so as to gain 33% after allowing the customer a discount of 5%.**

**Quantity II: Percentage of dancers under 25 years out of a group of 20 singers and 40 dancer if 20% of the singers are under 25 years old and 40% of the entire group is under 25 years.**

Quantity I > Quantity II

Quantity I < Quantity II

Quantity I ≥ Quantity II

Quantity I ≤ Quantity II

Quantity I = Quantity II or No relation

**Q7. Quantity I: Value of fifth number when Average of five numbers is 61. The average of 1st and 3rd number is 69 and average of second and fourth number is 69.**

**Quantity II: No. of boys in the class. The average age of all students of a class is 18 years. The average age of boys of the class is 20 years and that of the girls is 15 years. The no. of girls in the class is 20.**

Note: Compare the magnitudes of quantities.

Note: Compare the magnitudes of quantities.

Quantity I > Quantity II

Quantity I < Quantity II

Quantity I ≥ Quantity II

Quantity I ≤ Quantity II

Quantity I = Quantity II or No relation

**Q8. A 20 litres mixture contains milk and water in the respective ratio of 3 : 2. Then 10 litres of the mixture is removed and replaced with pure milk and the operation is repeated once more. At the end of the two removals and replacements, what is the ratio of milk and water in the resultant mixture respectively ?**

17 : 3

9 : 1

4 : 17

5 : 3

3 : 14

**Q9. On walking at 3/4 of his usual speed a man reaches his office 20 minutes late. What is the usual time taken by him in reaching his office ?**

75 minutes

60 minutes

40 minutes

30 minutes

None of these

**Q10. A wholesaler blends two varieties of tea, one costing Rs 60 per kilo and another costing Rs 105 per kilo. The respective ratio of quantities they were mixed in was 7 : 2. If he sold the mixed variety of Rs 100 per kilo, how much was his profit percentage?**

**Directions (11-15): In each of the following questions two equations are given. You have to solve the equations and**

Give answer –

Give answer –

**Q11. I. 8x² + 26x + 15 = 0**

**II. 4y² + 24y + 35 = 0**

if x < y

if x ≤ y

relationship between x and y cannot be determined

if x ≥ y

if x > y

Solution:

I. 8x² + 26x + 15 = 0

⇒ 8x² + 20x + 6x + 15 = 0

⇒ 4x (2x + 5) + 3(2x + 5) = 0

⇒ (2x + 5) (4x + 3) = 0

⇒ x = – 5/2, –3/4

II. 4y² + 24y + 35 = 0

⇒ 4y² + 10y + 14y + 35 = 0

⇒ 2y (2y + 5) + 7 (2y + 5) = 0

⇒ (2y + 5) (2y + 7) = 0

⇒ y = –5/2, –7/2

x ≥ y

**Q12. I. 2x² + 9x + 9 = 0**

**II. 2y² + 17y + 36 = 0**

if x < y

if x ≤ y

relationship between x and y cannot be determined

if x ≥ y

if x > y

Solution:

I. 2x² + 9x + 9 = 0

⇒ 2x² + 6x + 3x + 9 = 0

⇒ (x + 3) (2x + 3) = 0

⇒ x = –3, –3/2

II. 2y² + 17y + 36 = 0

⇒ 2y² + 8y + 9y + 36 = 0

⇒ (y + 4) (2y + 9) = 0

y = – 4, –9/2

x > y

**Q13. I. 5x² + 29x + 20 = 0**

**II. 25y² + 25y + 6 = 0**

if x < y

if x ≤ y

relationship between x and y cannot be determined

if x ≥ y

if x > y

Solution:

I. 5x² + 29 + 20 = 0

⇒ 5x² + 25x + 4x + 20 = 0

⇒ (x + 5) (5x + 4) = 0

⇒ x = –5, –4/5

II. 25y² + 25y + 6 = 0

⇒ 25y² + 15y + 10y + 6 = 0

⇒ (5y + 3) (5y + 2) = 0

⇒ y = – 3/5, –2/5

y > x

**Q14. I. 3x² – 16x + 21 = 0**

**II. 3y² – 28y + 65 = 0**

if x < y

if x ≤ y

relationship between x and y cannot be determined

if x ≥ y

if x > y

Solution:

I. 3x² – 16x + 21 = 0

⇒ 3x² – 9x – 7x + 21 = 0

⇒ (x – 3) (3x – 7) = 0

⇒ x = 3, 7/3

II. 3y² – 28y + 65 = 0

⇒ 3y² – 15y – 13y + 65 = 0

⇒ (y – 5) (3y – 13) = 0

⇒ y = 5, 13/3

y > x

**Q15. I. 8x²-26x+15=0**

**II. 2y²-17y+30=0**

if x < y

if x ≤ y

relationship between x and y cannot be determined

if x ≥ y

if x > y