SBI PO Quantitative Aptitude Quiz: 14th May |

SBI PO Quantitative Aptitude Quiz

The questions asked in the quantitative aptitude section are calculative and very time-consuming. But once dealt with proper strategy, speed, and accuracy, this section can get you the maximum marks in the examination. Following is the Quantitative Aptitude quiz to help you practice with the best of latest pattern questions

Directions (1-5): Table shown below shows population of five different cities. Some data is given in percent while some data is given in numbers. Study the table carefully and solve the following questions.

Note: Total population = Male + Female + Transgender

Q1. Population of city Z is what percent less than population of city Y.

30%

25%

20%

15%

17.5%

Solution:

SBI PO Quantitative Aptitude Quiz: 14th May |_4.1

Q2. Ratio of literate male to Illiterate male of city A is 11 : 7. What is the difference between literate male and Illiterate male of city A.

900

1050

1400

800

1200

Solution:

SBI PO Quantitative Aptitude Quiz: 14th May |_5.1

Q3. Female population in city Z is how much percent less than male and transgender population of city A.

SBI PO Quantitative Aptitude Quiz: 14th May |_6.1

SBI PO Quantitative Aptitude Quiz: 14th May |_7.1

SBI PO Quantitative Aptitude Quiz: 14th May |_8.1

SBI PO Quantitative Aptitude Quiz: 14th May |_9.1

SBI PO Quantitative Aptitude Quiz: 14th May |_10.1

Solution:

SBI PO Quantitative Aptitude Quiz: 14th May |_11.1

Q4. Male population of city B is how much more than female population of city X?

2900

2840

2760

2920

2980

Solution:

SBI PO Quantitative Aptitude Quiz: 14th May |_12.1

Q5. Find the ratio of transgender population of city Z to the transgender population of city A.

4/5

5/4

3/5

5/3

2/5

Solution:

SBI PO Quantitative Aptitude Quiz: 14th May |_13.1

Direction (6-10): Simplify the following problems.

Q6.

992

872

692

892

792

Solution:

? = 114 × 8 + 24 - 144
936 - 144 = 792

Q7.

SBI PO Quantitative Aptitude Quiz: 14th May |_16.1

SBI PO Quantitative Aptitude Quiz: 14th May |_17.1

SBI PO Quantitative Aptitude Quiz: 14th May |_18.1

SBI PO Quantitative Aptitude Quiz: 14th May |_19.1

SBI PO Quantitative Aptitude Quiz: 14th May |_20.1

Solution:

SBI PO Quantitative Aptitude Quiz: 14th May |_21.1

Q8. If x = 5 and y = 3 then x² + y² – 4xy =?

-18

-20

-36

-26

Solution:

x² + y² - 4xy = (x - y)² - 2xy
= (5 - 3)² - 2 × 5 × 3
= - 26

Q9.

Solution:

SBI PO Quantitative Aptitude Quiz: 14th May |_23.1

Q10.

34000

32000

36000

40,000

36,400

Solution:

SBI PO Quantitative Aptitude Quiz: 14th May |_25.1

Q11. A train ‘A’ having a length of 240 m can cross a tunnel which length is 150% more than that of the train A in 30 seconds. In how much time it can cross another train B which length is 320 m and running in opposite direction to train A with a speed of 72 km/h?

35/3 sec.

36 sec.

15 sec.

36/5 sec.

37/3 sec.

Solution:

SBI PO Quantitative Aptitude Quiz: 14th May |_26.1

Q12. Ratio between length of trains A and B is 3 : 5. Speed of train A is 72 km/h and that of train B is 54 km/h & they are running opposite to each other. If train A crosses train B in 16 seconds then find length of train B.

350 m

250 m

450 m

150 m

320 m

Solution:

SBI PO Quantitative Aptitude Quiz: 14th May |_27.1

Q13. A boat can cover upstream distance between two points in 6 hours and same distance downstream in 4 hours. If speed of boat in still water is 8 km/h, then find speed of stream.

2 km/h

1.6 km/h

3.2 km/h

4.8 km/h

3.8 km/h

Solution:

Let speed of stream = s km/hr
∴(8 – s) × 6 = (8 + s) × 4
⇒ 48 – 6s = 32 + 4s
⇒ s = 1.6 km/hr

Q14. Two trains X and Y cross each other in 48 sec, when both are running in same direction. If length of train X is 160 m and speed of train X and train Y are 54 km/h and 72 km/h respectively then find the length of train Y.

160 m

120 m

80 m

100 m

95 cm

Solution:

SBI PO Quantitative Aptitude Quiz: 14th May |_28.1

Q15. Three friends run around a circular track can complete a single loop in 24 min, 32 min and 56 min respectively. If they started running from the same initial point, then after how much time they will meet together for first time?

8.4 h

9.6 h

11.2 h

6.4 h

10 h

Solution:

Required time = LCM of (24, 32, 56)
= 672 min
= 11.2 h